search for: heighly

Note: I am almost certain that this has been asked and answered here before, so my apologies for the redundant query. I also know that there are several packages that will do this, but I wish to do it using base R functions only (see below). The query: Suppose I have a character vector of names like this: somenames <- c("Heigh", "Ho", "Silver", "Away")

Thanks, Rich. I thought of that, too, but it violates the spirit of my restraints (to avoid character strings), which I unfortunately did not clearly articulate. So my apologies for that failure. My concern is that with more complex model formula, using as.formula, etc. to parse/convert character strings can get a bit hairy. But in most cases, as here maybe, it may be perfectly fine. So think of

Another solution. reformulate + substitute + as.formula: substitute(~ (.)^2, list(. = reformulate(somenames)[[2]])) |> as.formula() On Sat, Mar 29, 2025 at 5:31?PM Bert Gunter <bgunter.4567 at gmail.com> wrote: > > Note: I am almost certain that this has been asked and answered here > before, so my apologies for the redundant query. > > I also know that there are several

Gabor, Duncan, et. al. 1. Thank you for your great comments and solutions. This is what I was hoping for! 2. Duncan: I completely agree with your criticisms. In fact, I realized the for() loop only needed the <- assignment, but your comment is important to note. However, I didn't like the for() loop either; I *much* preferred your Reduce() solution which is exactly the sort of elegant

> somenames <- c("Heigh", "Ho", "Silver", "Away") > as.formula(paste("~(",paste(somenames, collapse="+"),")^2")) ~(Heigh + Ho + Silver + Away)^2 > > On Mar 29, 2025, at 14:30, Bert Gunter <bgunter.4567 at gmail.com> wrote: > > somenames <- c("Heigh", "Ho", "Silver",

As always, I would like to thank all who responded for their insights and suggestions. I have learned from them. Thus far, my own aesthetic preference -- and therefore not to be considered in any sense as a "best" approach -- is to use Duncan's suggestion to produce the call directly with call() rather than substitute in my simple for() loop; i.e. somenames <-

I am confused. Richard's answer that Bert did not like did not use parse explicitly. Richard pasted together a string that a function like lm() will have to parse to run the analysis. However, the answers so far do not use parse(). In the reply to Richard, Bert indicated we cannot use strings. Even if I pass a vector where R can assume that the first variable is the dependent variable and all

my take of the assignment was to avoid 'parse' specifically. we start with a character vector, so avoiding characters is not possible. i was dealing with the fortune "if parse is the answer, you have the wrong question" Sent from my iPhone On Mar 29, 2025, at 15:39, Bert Gunter <bgunter.4567 at gmail.com> wrote: ? Thanks, Rich. I thought of that, too, but it violates

The general formula is y ~ a + b + c + ... There is this approach: formula <- reformulate(independent_vars, response = "y") model <- lm(formula, data = mydata) summary(model) It does not generate a string object, but the formula is still a string even if it is of class formula. Also, in this approach you only get + and if you want interactions or such you will need to code them

Hello, I thought of answering "reformulate can solve the problem" but how do you create quadratic terms with reformulate? ~(Heigh + Ho + Silver + Away)^2 is still a problem with no solution that I know of but paste/as.formula. Or Bert's bquote or substitute. Rui Barradas ?s 23:18 de 29/03/2025, Ebert,Timothy Aaron escreveu: > The general formula is y ~ a + b + c + ... >

Hello, I'm quite new to R, but I've already stepped into this problem: I open a PDF device with: pdf("Name-%d.pdf", width=10, height=10, onefile=FALSE) And draw 4 histograms in a row, expecting the pdf device to automatically number them from 1 to 4. What I get back is only 2 images with names "Name-1.pdf" and "Name-2.pdf" that contain the two last

I installed package plotrix because reading its vignette it looks like it can help me solve a "legend" problem. The package instaleed correctly on my Mac OS/X 10.5.8 But I cannot reproduce the examples centered on function "lgendg". > library(plotrix) > plot(0.5,0.5,xlim=c(0,1),ylim=c(0,1),type="n", + main="Test of grouped legend function") >

Hi, I have processed measurements of a rough surface to a heigh-height correlation plot. What the meaning of this exactly is, is not important. Only that it is a plot that had two (almost ) linear parts when plotted on a logaritmic scale. In this plot, I want to draw the best fitting lines for these linear parts but I just can't get it done. It is easy when the scales are linear but as you

Back in August David Chelimsky wrote: "FYI - I tried using the unit_record gem and there are some changes required in rspec to make it work, but they are trivial and it works great. The only trick is that the prevention of DB access is global per process, so you''d have to separate examples that hit the DB from those that don''t into two separate suites. I''ll explore

I want to write a function mimic the function of select.list(), here is my preliminary version. select <- function(x,multiple=TRUE,...){ ans<-new.env() g <- gwindow(title=title,wid=200,heigh=500) x1<-ggroup(FALSE,con=g) x2<-gtable(x,multiple=multiple,con=x1,expand=TRUE) gbutton("OK",con=x1,handler=function(h,...){ value <- svalue(x2) if (length(value)==0)

Dear all, I am trying (!!!) to generate pdfs that have 8 plots on one page: df = data.frame( day = c(1,2,3,4), var1 = c(1,2,3,4), var2 = c(100,200,300,4000), var3 = c(10,20,300,40000), var4 = c(100000,20000,30000,4000), var5 = c(10,20,30,40), var6 = c(0.001,0.002,0.003,0.004), var7 = c(123,223,123,412), var8 = c(213,123,234,435), all = as.factor(c(1,1,1,1)))

Hello, I'm trying to produce graphs automatically from data stored in database. Before saving the graphs, I would like to maximize the size of the graphs. The best would be to directly open maximized windows with x11() but up to now I failed doing it. I tried different widths and heighs but I never managed to obtain a full screen window. Is there a command to do it ? Thanks in advance, Ptit

Hello David, thanks for detailed response! Do you have any tests that you use to measure the PGO effectiveness? I have tested clang version 6.0 with the same sample that Jie Chen used in 2016 and actually both frontend-based PGO and IR-based make code run slower, see the average time: clang++ -O3: 3.15 sec  clang++ -O3 and -fprofile-instr-use: 3.160 sec clang++ -O3 and -fprofile-use: 3.180 sec

On Sun, Feb 4, 2018 at 9:59 PM, Victor Leschuk <vleschuk at accesssoftek.com> wrote: > Hello David! > > I have recently started acquaintance with PGO in LLVM/clang and found > your e-mail thread: > http://lists.llvm.org/pipermail/llvm-dev/2016-May/099395.html . Here you > posted a nice list of optimizations that use profiling and of those > which could be using but

Hello David! I have recently started acquaintance with PGO in LLVM/clang and found your e-mail thread: http://lists.llvm.org/pipermail/llvm-dev/2016-May/099395.html . Here you posted a nice list of optimizations that use profiling and of those which could be using but don't. However that thread is about 2 years old. Could you please kindly let me know if there were any significant changes in