search for: hamiltonian

Hello, I have a system of quadratic equations (results of a Hamiltonian optimization) which I need to find the roots for. Is there a package and/or function which will find the roots for a quadratic system? Note that I am not opimizing, but rather solving the first order conditions which come from a Hamiltonian. I am basically looking for something in R that will do...

Dear List Is there a package for leapfrog plotting (Hamiltonian Monte Carlo estimation) in R? I tried the actual "LEAPFrOG" package which doesn't actually give the plot like this one? http://xianblog.files.wordpress.com/2010/09/hamilton.jpg How doe one plot this in R? So, there semi-circle and dots on that semi-circle. I don't think curve()...

...lems as simple iterative thing is often quicker in practice. (That's assuming it is an exact Ising model: I hadn't realized LLVM was using that and a quick skim of the file doesn't make me fully confident I understand what model it's implementing.) The cost function does map to the Hamiltonian of an Ising model (give or take a couple of constants), and all interactions are non-negative, making it ferromagnetic. There are a couple of cheats, though: - The nodes are tri-state, {-1, 0, +1}, with the neutral state being used as the starting point. This allows a small spin-up seed to grow in...

With the D-Wave computer in the news recently, you may find it interesting that LLVM’s register allocator is using Ising models to compute regions for live range splitting. The problem of finding a region for splitting a live range is mapped to an Ising model with the help of the edge bundle graph, see EdgeBundles.h. A node in the edge bundle graph represents a set of CFG edges that enter or

This was posted not too long ago on sci.crypt... Enjoy... I think the most relevant information is near the top, but it''s all quite good... :-) -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- There is no intrinsic difference between algorithm and data, the same information can be viewed as data in one context and as algorithm in another. Why then do so many people claim that encryption algorithms

...? ? ? > ? } > ??? } > } > > So, here I have used i and j to range over the elements of > x[[1]], x[[2]] > respectively. > (*This prints all the paths of length 2 starting at vertex > 1. But I'm trying > to generalise this for a path of length nrow(A), i.e. a > Hamiltonian path)*) > I want to iterate this process a certain number of times, > so instead of i,j > I thought to use a list of scalars, v. > I don't want v to be identical to x... I want v to be a > list of scalars > which range (inside a for loop) over an elements of the > list x. (...