Displaying 1 result from an estimated 1 matches for "hair_colour_id".
2006 Dec 20
6
select lists - DB best practice
...9;, ''height'', ''Location'' etc etc.
The way I m thinking about doing it is to create new table for each
group of options like...
************
hair_colour
id
colour
************
and then in the profile table have..
************
profiles
id
user_id
hair_colour_id
************
It just semms like there must be a better way of doing this without
creating so many tables?
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