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...s not completely compatible with the expectation of result we can have according to the table help? Or would it be possible to have the same results independently of the vector type? This post was rejected on the R-devel mailing list so I ask my question here as suggested. Best regards, Alain Guillet -- Alain Guillet Statistician and Computer Scientist SMCS - IMMAQ - Universit? catholique de Louvain http://www.uclouvain.be/smcs Bureau c.316 Voie du Roman Pays, 20 (bte L1.04.01) B-1348 Louvain-la-Neuve Belgium Tel: +32 10 47 30 50 Acc?s: http://www.uclouvain.be/323631.html

...ve the same number of levels (2). If you split it and then let table convert each split to a factor, one split will have 1 level and the other 2. To see the details of the output , use str() instead of print(). Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, Feb 6, 2018 at 12:20 AM, Alain Guillet <alain.guillet at uclouvain.be> wrote: > Dear R users, > > When I use aggregate with table as FUN, I get what I would call a strange > behaviour if it involves numerical vectors and one "level" of it is not > present for every "levels" of the "by"...

...lda_analysis)$x, labels=predict(lda_analysis)$class, > col=palette()[predict(lda_analysis)$class]) > > The above code only reproduce the first plot using predict to obtain > coordinates and classes for the first tow discriminant axis. > > Thanks , > > Alejo > -- Alain Guillet Statistician and Computer Scientist SMCS - Institut de statistique - Universit? catholique de Louvain Bureau c.316 Voie du Roman Pays, 20 B-1348 Louvain-la-Neuve Belgium tel: +32 10 47 30 50

...rface and I get the following code : test$variable <- recode(test$x, '1:5 = 0; else = 1; ', as.factor.result=FALSE) And a vector of NA as result. > test$variable [1] NA NA NA NA NA NA NA NA NA NA I am using R 2.11.1 with Rcmdr 1.5-5 on Windows Vista. Regards, Alain -- Alain Guillet Statistician and Computer Scientist SMCS - IMMAQ - Universit? catholique de Louvain Bureau c.316 Voie du Roman Pays, 20 B-1348 Louvain-la-Neuve Belgium tel: +32 10 47 30 50

Dear R-users, I am using R(a package igraph) to calculate certain topological features of networks. When I try to draw a plot between these features I get an error. Following is the code I am using : *> plot(met_eco_deg,met_eco_bet) > lmout<-lm(met_eco_bet ~ met_eco_deg) > abline(lmout) Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) : plot.new

Hi folks, OS - Ubuntu 10.04 On R I create a datafile named "data". I can evoke it on R with; > data On R Commander Data -> Active data set -> Select active data set -> (data) OK only one data set there "data" -> View data set I can read it -> Edit data set showing 25 rows of data. Clicking the box shows a thick border around it. But I couldn't

Is it possible to add labelled contour lines to filled.contour plot ? [[alternative HTML version deleted]]

...to know if a point is inside the ellipse. Is any R functions to do it without computing the equation of the ellipse manually? Thanks. For example, if I do "plot(ellipse(0.8), type = 'l')", I would like to know if (0,1) belongs to the drawn ellipse. Regards, Alain -- Alain Guillet Statistician and Computer Scientist SMCS - Institut de statistique - Universit? catholique de Louvain Bureau d.126 Voie du Roman Pays, 20 B-1348 Louvain-la-Neuve Belgium tel: +32 10 47 30 50

I'm trying to assign NAs to values that satisfy certain conditions (more complex than shown below) and it gives the right result, but breaks the loop having done the first one viz: new<-c(rep(5,4),6) for (i in 1:6) {new[new[i]>5.5][i]<-NA} gives the correct result, though an error message appears which causes a break if it's in a loop. If I can get rid of the error message and

Dear fellow users Are there any Vietnamese language resources for beginners of R? If so, I would be interested in hearing from people who have had experience with them and which are better (if there is more than one). I am involved with an aid project in Vietnam, and would like to move the scientists involved from using Excel for 'analysis' to R. Thanks .... Peter Alspach The

Hi R-List, I have a question regarding R-language formats, I think. I am producing a series of graphs (using plot, barplot, barchart, and bwplot, using either text or mtext to place values on the graphs) and tables for a Francophone country. In fact, I have already done so. However, while they are pleased with the results they've requested I convert all of my decimal points into the French

...he bat file with the scheduled task of Windows XP. Then I log off. It works up to the log off of another user on the same computer with R-2.9.1 but this problem doesn't appear with R-1.9.1 on the same machine. Is anything wrong in the syntax of my bat file? Thanks. Regards, Alain -- Alain Guillet Statistician and Computer Scientist SMCS - Institut de statistique - Universit? catholique de Louvain Bureau d.126 Voie du Roman Pays, 20 B-1348 Louvain-la-Neuve Belgium tel: +32 10 47 30 50

Dear Forum, I have a class variable 1 (populations A-E), and two other class variables, variable 2 and variable 3. What I want is to see if the combination of var 2 and var 3, will give me a pattern that allows to distinguish populations. I found several packages like ade4, with pcaiv function and factoMineR. but there are not working. Using the ade4 package, when I try to build the pca: pca1

Hi everyone, I 'm building a function, in the middle it controls the sign of a variable x. If x < 0 the function write a warning (Error: negative value!). At this point I want the function stops without execute the remaining code. How can I do to terminate the function before your ending? Thanks in advance. Paolo

Hello, I have another stupid question. I hope you can give me a hint how to solve this: I have a list and one element is again a list containing matrices, all of the same dimensions. Now, I'd like to set the dimnames for all matrices: example code: m1 <- matrix(1:25, nrow=5) m2 <- matrix(26:50, nrow=5) # ... there can be much more than two matrices l <- list() l[[1]] <-

Dear all, i'm trying to label specific individuals (supplementary ones) after a PCA with the FactoMiner package. There is not much details (possibilities?) in the R-help of the plot.pca function. There is indeed a "label" parameter but i could only manage to label the supplementary individuals with there "row.names" (i.e. label="indiv.sup") and not with the

Dear list, I have a list of three matrices : i = list(matrix(1:4,2,2), matrix(3:6,2,2), matrix(9:12,2,2)) I would like to sum the matrices, as follows : [,1] [,2] [1,] 13 19 [2,] 16 22 I used this code : k <- i[[1]] for (j in (2:length(i))) { k <- k + i[[j]]} But, is it possible to sum without a loop ? Thanks in advance, Carlos [[alternative HTML version deleted]]

I'm confused on how is the right way to plot a discriminant analysis made by lda function (MASS package). (I had attached my data fro reproduction). When I plot a lda object : X <- read.table("data", header=T) lda_analysis <- lda(formula(X), data=X) plot(lda_analysis) #the above plot is completely different to: plot(predict(lda_analysis)$x,

Dear all, let suppose I have following vector:   > dat1 <- c(rep("asd", 5), rep("xyz", 12), rep("erd", 17)) > dat1 <- dat1[sample(1:length(dat1), length(dat1), replace=F)] > dat1  [1] "erd" "xyz" "erd" "asd" "asd" "erd" "xyz" "asd" "erd" "erd"

Hi all, I hope it's not too trivial for the list - I'm trying to concatenate two factor arrays, and obtain the following: > f1<-factor(c("a","a","b")) > f1 [1] a a b Levels: a b > f2<-factor(c("b","b","a")) > f2 [1] b b a Levels: a b > c(f1,f2) [1] 1 1 2 2 2 1 Instead of getting: [1] a a b b b a Levels: a