search for: groupsid

Hi, I'm running Samba4 now for a couple of weeks, I'm currently stuck at the following problem: how do I change the AD groupsid? And this without the use of SUA in windows. For instance I have the group NiagaraUsers (S-1-5-21-1512407341-4132623508-1653607534-1001) with groupsid 10020. I just want to know how I can change this to 7002 for example. Best Regards Tim Vangehugten

...mba, port: 3306 Error while executing MySQL query: You have an error in your SQL syntax near ';,passcantime;,passmusttime;,username,domain;,ntusername;,fullname;,hom edir;,dir' at line 1 INSERT INTO users (acct_ctrl,passmusttime;,passmusttime;,hourslen;,logondivs;,uid;,gid,use rsid;,groupsid;,username,domain;,fullname;,lanmanpass;,ntpass;) VALUES (128,1038503414,1036689014,21,168,1001,102,'S-1-5-21-185972153- 986818063-2128889050-3002','S-1-5-21-185972153-986818063-2128889050- 1205','bbmachine$','BBNETWORK','BBMACHINE','7A58D4CAF8CB00A46E...

...$username = substr($_, $beginpoint); open(USERSIDS, 'wbinfo -n ' . $_ . ' |'); while (<USERSIDS>){ $space = ' '; $endpoint = index($_, $space); $usersid = substr($_, 0, $endpoint); open(GROUPSIDS, 'wbinfo --user-domgroups ' . $usersid . ' |'); $j = 0; while (<GROUPSIDS>){ if ($j != 0) { open(GROUPNAME, 'wbinfo -s ' . $_ . ' |'); whil...

...char(255), fullname varchar(255) default 'Guest User', logontime int(9), logofftime int(9), kickofftime int(9), workstations varchar(255) default NULL, lanmanpass varchar(255) default NULL, ntpass varchar(255) default NULL, plaintextpass varchar(255), uid int(9), gid int(9), usersid int(9), groupsid int(9) ); GRANT ALL PRIVILEGES ON sambauser.* TO samba@localhost IDENTIFIED BY 'sambapass' WITH GRANT OPTION; INSERT INTO users (username, ntusername, plaintextpass) VALUES ("testuser", "testuser", "testpass"); -- smb.conf: [global] workgroup = BBNET...

..._groups_ (users no problem) !!!! if i press "admit" or "ok" to store the new permissions everything is reseted in the logs i see, that samba is searching for the correct SID (S-1-4-21-xxx-xxx-xxx-512 -> DomAdmins) _AND_ for the attribute sambaSamAccount of course, for a groupsid, which is mapped to a unix-group (groupmap) there's no entry with this search criteria !!! so samba can't find an entry in LDAP and fails who uses LDAP and groupmapping and can tell me, how to solve this problem, that i just can grant file-access on ACL-User-Base ??? btw: wbinfo -u $UI...

I have installed lots of samba 3 servers as PDCs for little networks serving 10 users or so. I have always set up the user "root" as the domain administrator, by setting its group SID to <domainSID>-512 with pdbedit. My "root" user has usually a user SID of <domainSID>-1000 since it is the first user I add to Samba. I have never set up a username map

...n include = /etc/samba/prof.%G (or %g, %U, %u), samba is unable to load it too, because it's looking for a file named "prof." %v and %m are correctly changed. Below, some outputs. I'm stuck since 5 days... if someone could help me... Thank you very much. Paul. Some outputs: (groupsID < 100 are defined in /etc/group, others are on LDAP) (nobody is an /etc/passwd and /etc/group account) # id su uid=0(su) gid=0(root) groups=0(root),512(ntadmins) # id paul uid=201(paul) gid=200(admin) groups=200(admin) # id mdho uid=11102(mdho) gid=11100(gte1g1) groups=11100(gte1g1),11000(gte...

Hello, I've build a domain with Samba 3.0.23 and sucessfully joined this domain with a Windows-XP-Machine. I can log in to that machine as User "Root", wich is in the Group "Domain Admins" (rid=512). But I have no admin-rights on that machine. Also, normal User can not log in over the Remotesession (RDP). Can anybody help me to figure out why? Here is my smb.conf:

...> >>the problem is on the samba-side >>on unix-side the user "test_user" has access on /home/board, cause he's >>in group "kids", too >> >>but samba just recognised group "users" for "test_user" because >>sambaPrimaryGroupSID maps to -> "users" >>so samba establishes a connection as user "testuser" / group "users", >>which fails because of my restrictive acl :/ >> >>so: is "valid users" my only chance? >> >>no way of adding more GroupSIDs for...

...~# id test_user uid=500,gid=500 (users),groups (users,kids) as you can see, this user is in primary group "users" and also member of group "kids" if he tries to access /home/board via smb (Samba 3.0 + openldap) from a windows client (XP), he fails, because his sambaPrimaryGroupSID maps to -> "users" and /home/board is not accessible for group "users" - just for "kids" if i add valid users = @kids to /home/board - share, access is granted isn't it possible in samba, that the user "test_user" gets an attribute like sambaSecon...

...users),groups (users,kids) > > as you can see, this user is in primary group "users" and also member of > group "kids" > > if he tries to access /home/board via smb (Samba 3.0 + openldap) from a > windows client (XP), he fails, because his > > sambaPrimaryGroupSID maps to -> "users" > > and /home/board is not accessible for group "users" - just for "kids" > if i add > > valid users = @kids > > to /home/board - share, access is granted > > isn't it possible in samba, that the user "test_user...

Hi All, Are there any special CTDB/SMB configuration settings/dependencies to manage Winbind across CTDB managed servers authenticating via Active Directory(AD)? An example would be Samba's IDMAP backend for Winbind: RID vs. AD or tag Winbind to a primary CTDB node and point other nodes to authenticate from AD via proxy primary CTDB node? /etc/sysconfig/ctdb on all nodes is as follows:

...that in the ldapsam backend the rid mapping is algorthmic based: rid='2*uidNumber+1000' and primaryGroup='2*uidNumber+100+1', so a root or any administrative account must have a rid of 1000, and a sambaSID like: sambaSID: S-1-5-21-298858960-1863792627-3661451959-1000 sambaPrimaryGroupSID: S-1-5-21-298858960-1863792627-3661451959-1001 The root/administrator (uidNumber=0) SHOULD be present in the NT's Admins group (rid=512). " What I interpret from this is that I have to create three posixAccounts (root, Administrator and nobody, although it seems root and nobody might hav...