search for: grouppass

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2006 Nov 21
1
NEWBIE: Help explaining use of lm()?
...ve none ctr.8w > summary(lm(walk ~ group)) Call: lm(formula = walk ~ group) Residuals: Min 1Q Median 3Q Max -2.7083 -0.8500 -0.3500 0.6375 3.6250 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 10.1250 0.6191 16.355 1.19e-12 *** grouppassive 1.2500 0.8755 1.428 0.1696 groupnone 1.5833 0.8755 1.809 0.0864 . groupctr.8w 2.2250 0.9182 2.423 0.0255 * --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 Residual standard error: 1.516 on 19 d...