Displaying 8 results from an estimated 8 matches for "group_b".
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group_by
2011 Apr 28
3
Simple General Statistics and R question (with 3 line example) - get z value from pairwise.wilcox.test
Hi there,
I am trying to do multiple pairwise Wilcoxon signed rank tests in a
manner similar to:
a <- c(runif(1000, min=1,max=50), rnorm(1000, 50), rnorm(1000, 49.9,
0.5), rgeom(1000, 0.5))
b <- c(rep("group_a", 1000), rep("group_b", 1000), rep("group_c",
1000), rep("group_d", 1000))
pairwise.wilcox.test(a, b, alternative="two.sided",
p.adj="bonferroni", exact=F, paired=T)
This gives me the following output:
group_a group_b group_c
group_b <2e-16 - -
group_c <...
2008 Mar 10
2
Share permissions
Hello all,
I have a SAMBA share called "share_a" and it is working fine (below is a
snapshot of it):
[share_a]
path = /shares/share_a
browseable = no
valid users = @group_a @group_b @group_c
write list = @group_a @group_b
read list = @group_c
create mode = 777
directory mode = 777
Inside this share there's a lot of sub-folders.
The problem is: How can I give to one of these folders permission to a
restrict group, like "group_d" that others (group_a-c) won't...
2010 Oct 26
4
divide column in a dataframe based on a character
...quot;ii_jj","jj_kk","kk_ll")
ddd <- cbind(dd, group = zz)
and I want to divide the column named group by the "_", how would I do this?
so instead of the first row being
x y fac char group
1 1 C a aa_bb
it should be:
x y fac char group_a group_b
1 1 C a aa bb
I know for a vector I can:
x1 <- c("a_b","b_c","c_d")
do.call("rbind",strsplit(x1, "_"))
but I am not sure how this relates to my data.frame
Thanks,
Daisy
--
Daisy Englert Duursma
Room E8C156
Dept. B...
2019 Feb 19
2
Reloading smbd session process group membership cache
...R/W access to it via his
*group_a* group membership.
Then, without unmounting the share, we add another share and HUP smbd.
*smb.conf: *
[share_a]
path = /mnt/share_a
valid users = dude
[share_b]
path = /mnt/share_b
valid users = dude
*ls -l /mnt:*
drwxrwxr-x root group_a share_a
drwxrwxr-x root group_b share_b
*/etc/group:*
group_a:*:2000:user
group_b:*:2000:user
Now, the same client is able to mount the new share, but can't write to it
since to its cached knowledge, *dude* is not a member of *group_b* since he
wasn't one at the time of connection.
What I'm looking for is a way to...
2003 Aug 19
2
Samba 3beta3 - Winbind and groups in groups - question
Hi everybody, im new here, and I have problem.
Im running samba 3beta3 at gentoo linux.
Do anybody know how to resolve something like this:
There are three groups in AD
group_a, and group_b and group_c
Members of group_a are user_0, user_1, user_2
Members of group_b are user_3, user_4, user_5
Members of group_c are user_6 and group_b
If i try to do
getent group
At my linux box i got
group_a: user_0,user_1,user_2
group_b: user_3,user_4,user_5
group_c: user_6
Problem is group_c, I...
2019 Feb 22
0
Reloading smbd session process group membership cache
...t unmounting the share, we add another share and HUP smbd.
>
> *smb.conf: *
> [share_a]
> path = /mnt/share_a
> valid users = dude
>
> [share_b]
> path = /mnt/share_b
> valid users = dude
>
> *ls -l /mnt:*
> drwxrwxr-x root group_a share_a
> drwxrwxr-x root group_b share_b
>
> */etc/group:*
> group_a:*:2000:user
> group_b:*:2000:user
>
> Now, the same client is able to mount the new share, but can't write to it
> since to its cached knowledge, *dude* is not a member of *group_b* since he
> wasn't one at the time of connection...
2019 Feb 22
1
Reloading smbd session process group membership cache
...; >
> > *smb.conf: *
> > [share_a]
> > path = /mnt/share_a
> > valid users = dude
> >
> > [share_b]
> > path = /mnt/share_b
> > valid users = dude
> >
> > *ls -l /mnt:*
> > drwxrwxr-x root group_a share_a
> > drwxrwxr-x root group_b share_b
> >
> > */etc/group:*
> > group_a:*:2000:user
> > group_b:*:2000:user
> >
> > Now, the same client is able to mount the new share, but can't write to
> it
> > since to its cached knowledge, *dude* is not a member of *group_b* since
> he
&g...
2013 Feb 15
10
reading data
...? 2? 2 AR??? 4???? 7640 8926
#3??? aA? 2? 1??? 1 0.0845435? 2 AA? 2 6790 734,1092?? NA
#4?? aAA? 1? 2 1965 0.0007000? 4? 3 AR??? 2??? 11616 8926
#5? aAAA? 1? 3 3660 0.0008600 18? 3 AA??? 2??? 20392? 496
#6??? AA na? 2 1972 0.0007000 11? 3 AR?? 25????? 509? 734
If you want the names to be group_a, group_b etc.
?names(res)<-paste("group_",gsub("\\d+","",names(res)),sep="")
res[grep("group_b",names(res))]
$group_b
#???? Id? M mm??? x???????? b? u? k? j??? y??????? p??? v
#1?? aAA? 1? 2? 739 0.1257000? 2? 2 AA??? 2???? 8867 8926
#2 aAAAA? 1? 2 2263 0...