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Neal O'Doan plays 4 piano concerti: Chopin#2, Grieg, Moszkowski#1 and Rachmaninoff#1 Neal and Nancy O'Doan play St-Saens Carnival of the Animals together with pieces by Poulenc, Korsakov, Warner and Tufts. Pan116e. <p><p><p>--- >8 ---- List archives: http://www.xiph.org/archives/ Ogg project homepage: http://www.xiph...

Full_Name: Dale Houston Version: 1.5.0 OS: Solaris 8 Submission from: (NULL) (192.35.79.70) I am trying to get RT-1.5.0 installed on Solaris 8. The programs compile fine and 'make check' seems to work. But when I do a 'make install' I see this: /home/dhouston/R-1.5.0 grieg> make install installing afm ... installing doc ... installing doc/html ... install: index.html does not exist *** Error code 1 make: Fatal error: Command failed for target `install' Current working directory /home/dhouston/R-1.5.0/doc/html *** Error code 1 make: Fatal error: Command failed...

Hi All, How can I get the expected value from a discrete cdf? Is there any R function that can do this? Thanks, Annie [[alternative HTML version deleted]]

My statistics teacher wrote a textbook and included .rdata files for the problem set data. I downloaded these and opened one of them up. Then I used the ls() command, and it gave me this: > ls() [1] "ex02-12" However, when i try to use the object, it interprets it as ex02 - 12, and I get the following error: > ex02-12 Error: object 'ex02' not found I don't know why

There seems to be a latent flaw in the definition of struct SEXPREC in Rinternals.h, which likely doesn't cause problems now, but could if the relative sizes of data types changes. The SEXPREC structure contains a union that includes a primsxp, symsxp, etc, but not a vecsxp. However, in allocVector in memory.c, zero-length vectors are allocated using allocSExpNonCons, which appears to

Dear List, i would like to mimic the behaviour or the following indexing with a do.call construct to be able to supply the arguments to `[` as a list: test = matrix[1:4,2] result = test[2,] My try, however, did not work: result = do.call(`[`,list(test,2,NULL)) result = do.call(`[`,list(test,2,)) result = do.call(`[`,list(test,2,'')) How can I use the do.call in that way with

Dear colleagues, I have a data set that looks roughly like this; mydat<-data.frame(state=c(rep("Alabama", 5), rep("Delaware", 5), rep("California", 5)), news=runif(15, min=0, max=8), cum.news=rep(0, 15)) For each state, I'd like to cumulatively sum the value of "news" and make that put that value in cum.news. I'm trying as follows but I get

From SVN revision 57032, with configuration R is now configured for i686-pc-linux-gnu Source directory: . Installation directory: /usr/local C compiler: gcc -std=gnu99 -g -O2 Fortran 77 compiler: gfortran -g -O2 C++ compiler: g++ -g -O2 Fortran 90/95 compiler: gfortran -g -O2 Obj-C compiler: Interfaces supported: X11

I have the following results for an ANOVA comparing two nested models. I wasn't sure how I am supposed to report this result in the area of psychology. Specifically, am I supposed to report the DF's or just the F ratio? I could manually calculate the degrees of freedoms, but there must be a reason why R does not give this information, i.e. those are not conventionally used in the

Hi, I've data from an incomplete fatorial design. One level of a factor doesn't has the levels of the other. When I use lm(), the summary() return NA for that non estimable parameters. Ok, I understant it. But I use contrast::contrast(), gmodels::estimable(), multcomp::glht() and all these fail when model has NA estimates. This is becouse vcov() and coef() has different dimensions. Is

Dear all, I am trying to aggregate a table (divided in two lists here), but get a memory error. Here is the code I'm running : sessionInfo() print(paste("memory.limit() ", memory.limit())) print(paste("memory.size() ", memory.size())) print(paste("memory.size(TRUE) ", memory.size(TRUE))) print(paste("size listX ", object.size(listX)))

Hi, sorry for repeating the question but this is kind of important to me and i don't know whom should i ask. So as noted before when I do a parameter fit to the beta distr i get: fitdist(vectNorm,"beta"); Fitting of the distribution ' beta ' by maximum likelihood Parameters: estimate Std. Error shape1 2.148779 0.1458042 shape2 810.067515 61.8608126 Warning

Why does R think these numbers ***are*** equal? In a somewhat bizarre set of circumstances I calculated x0 <- 0.03580067 x1 <- 0.03474075 y0 <- 0.4918823 y1 <- 0.4474461 dx <- x1 - x0 dy <- y1 - y0 xx <- (x0 + x1)/2 yy <- (y0 + y1)/2 chk <- yy*dx - xx*dy + x0*dy - y0*dx If you think about it ***very*** carefully ( :-) )

dear all, i have a quite simple question, i want to fill up a Matrix like done in the following function, but the performance is very bad for large dimensions is there a way to do this like with apply or something similar? makeMatrix <- function(a, b,dim) { X=matrix(0,ncol=dim,nrow=dim) for (i in c(1:dim)){ for (j in c(1:dim)) { if (i==j) {X[i,j]<-a} else { X[i,j]<- exp((

Hi, all. I'm new to R. I've been a SAS programmer for 20 years. I seem to be having trouble with the most basic task - bringing a table in an *.RData file into a data.frame object. Here's how I created the *.RData file. library(RODBC) db <- odbcConnect("*******") df <- sqlQuery( db , "select * from schema.table where year(someDate)=2006" ) save(

Hello, I was wondering if someone knows the formula used by the function lm to compute the t-values. I am trying to implement a linear regression myself. Assuming that I have K variables, and N observations, the formula I am using is: For the k-th variable, t-value= b_k/sigma_k With b_k is the coefficient for the k-th variable, and sigma_k =(t(x) x )^(-1) _kk is its standard deviation.

Dear R-helpers, In the following example I compute ret and returns the SAME way. In ret I use compute returns for EACH column and in returns I do it for the whole data frame. Could someone please tell me why I see a lagged result,by which I mean ret and returns are different by one lag. getSymbols("GOOG",src="yahoo") ret<-apply(GOOG,2,function(x) diff(log(x)) / lag(x,1) )

Dear all, Even though one of R users answered my question, I cannot understand, so I re-ask this question. I am trying to use "do.call", but I don't think I totally understand this function. Here is an simple example. -------------------------------------------- > B <- matrix(c(.5,.1,.2,.3),2,2) > B [,1] [,2] [1,] 0.5 0.2 [2,] 0.1 0.3 > x <- c(.1,.2) >

Have tried to install R.app several times (6, in fact: versions 2.12, 13 & 14, both 32 and 64 bit versions), using packages freshly downloaded from the official project page, and failed every time, given exception reports such as the following (appended below, the 2 reports arising out of my 1st & 6th attempts). Machine & software version specifics are all contained therein. What

Mathew Brown Institute of Bioclimatology University of G?ttingen B?sgenweg 2 37077 G?ttingen, Germany t: +49 551 39 9359 mathew.brown at forst.uni-goettingen.de On 9/24/2011 6:00 PM, r-help-request at r-project.org wrote: > Send R-help mailing list submissions to > r-help at r-project.org > > To subscribe or unsubscribe via the World Wide Web, visit >