search for: gray

Hi, In the example dataset below - how can I cahnge "gray20", to "blue" # data black <- rep(c("black","red"),10) gray <- rep(c("gray10","gray20"),10) black_gray <- data.frame(black,gray) # none of this desperate things works # replace(black_gray$gray, gray=="gray20","red&quot...

Hi, I am facing a problem with the legend, I don?t know how to use the fill option in the legend in order to achieve the same standard gray levels that are plotted. Sorry for this easy one, but I really did not find anything so far. It works fine with color: ###### C O L O R mat <- matrix(2,3,rep(2,6)) rownames(mat)<-c("A","B","C") par(xpd=T, mar=par()$mar+c(2,0,0,0)) barplot(mat,col=rainbow(3)) l...

The gray (level) function returns different shades of gray, where level is a vector of numbers ranging from 0 to 1.? 0 is white and 1 is black and everything in between is a shade of gray. Is there a function that will let me choose two different colors?? For example, a 0 might be blue and 1 might be red a...

Hey!! It is now showing the former users' folders at the top level of the current user. Great! Perhaps dovecot just needed time to "index" the new messages? Anyway, Luigi's suggestion on moving and renaming the folders apparently worked. Thanks!!!! --Mark -----Original Message----- > Subject: Re: Moving Maildir folders > From: Frank-Ulrich Sommer <f-u.s at

Dear expeRts, I would like to color a certain region in a levelplot. The region for z <= 0.02 should have a dark gray color. Below is a minimal example. It almost does what I want, but The region between z=0.02 and z=1 is also colored in dark gray (instead of just the region for z <= 0.02). How can I solve this? Cheers, Marius ## z values for given x and y f <- function(x) 4*((1-x)^(-1/2)-1) eps <- 1e...

...tively easy to answer (probably, there's a simple way to do what I'm working toward). R's statistical functions are coming along easily enough, but graphics seem to be a little tougher for me, probably because I'm used to working in SigmaPlot. As an exercise, I tried to create a gray bar chart with white grid overlay, like the one on page 128 of Tufte's "Visual Display of Quantitative Information." I figure this would cover a lot of the basic techniques that I'll need for "real" work. I got as far as having a gray bar chart (I was working within...

In the example R script below, horizontal gray gridlines are drawn at y coordinates where the points are drawn with the code: panel.abline(h=y, v=xScale, col.line="gray") How do I change this so that the horizontal gray gridlines are drawn at y coordinates where the y labels are drawn? The challenge is that each panel has different...

I'm trying to create figures in PDF that use the 'gray' colormodel instead of the default 'RGB' model, by requirements of a publisher. My problem has to do with the fact that I'm not being able to get gray colors with this option on the pdf() driver. Here is a small example for problem replication: > R.version _...

Hi all, I got one problem with comparing strings like if any string is like "*RIGHT, EPICARDIUM: FOCUS, GRAY-WHITE, SINGLE, APPROX 0.6 CM IN DIAMETER*." and i have to compare "*GRAY-WHITE*" with the above string or otherwise i have to compare " *TUMOR BENIGN*" this string with "*MEDULLRY TUMOR BENIGN,TYP PHEOCHROMOCYTOMA*" i tried with spli...

I'm trying to create a graph where different cells of a grid (a shapefile) will be painted with a color share scale, where the most easy way is to use gray(). Can I somehow get a vector (gradient) of colors, a vector of colors with other methods but gray()? I'm doing this until now quad_N_sp <- merge(sp_dist[sp_dist$sp==splist[i],],grelha_ID,by.x="quad",by.y="quadricula ",all.y=T,) quad_N_sp$x[is.na(quad_N_sp$x)...

code: op <- par(bg='black',fg='gray',col='gray',col.axis='gray',col.lab='gray',col.main='gray',col.sub='gray',mai=c(0,0,0,0), tck = 0.01, mgp = c(0, -1.4, 0), mar=c(0,0,0,0)) plot(x,y,ylim=c(-20,20),xlim=c(min(x),max(x)),pch='X',col = rgb(1,1,1, 0.5),yaxt="n", ann=FALSE) a...

Hi there, I'm having trouble working out how to change the colors of polygon shading lines. If I plot a polygon with polygon(poly,density=30,borders=gray(0.5)) I get gray borders but black shading lines; I have tried adding col=gray(0.5), bg=gray(0.5) and fg=gray(0.5), but no luck. How can I change the colors of the shading? The help file doesn't seem to detail this, so any suggestions would be greatly appreciated. Many thanks Luke Spadav...

Am 2016-07-17 um 02:36 schrieb Mark Foley: > Not quite there yet. The folders show up, but I cannot see the mail inside the folders unless > (in the Thunderbird client) I uncheck the setting "Show only subscribed folders". Still, the > top-level folder is shown as grayed-out/italics as well as the the sub-folder INBOX. All other > sub-folder at the same level as INBOX are not grayed-out, nor are folders subordinate to INBOX: > > user at mydom.org <-- topmost "real" account folder > +Inbox > Drafts > Templates > send I...

Selim Daoud wrote: > here''s an interesting status report published by Microsoft labs > > http://research.microsoft.com/research/pubs/view.aspx?msr_tr_id=MSR-TR-2005-166 That is the paper in which Jim Gray coined "Mean time to data loss". It''s been quoted here before. Sad note: Turing award winner Jim Gray has been missing now for two weeks, after he went sailing out of San Fransisco on his sailboat Tenacious on jan 28. Friends of Jim mobilised Amazon''s mechanical Turk t...

hi all I guess that *Theora* will convert the input color space (RGB or CMYK or any) into YUV before it process and encode. (that means theora can operate on several color space, but it get convert into YUV before process) Is that true...? I want to get a gray scale, encoded video output from the *Theora* encoder while the input video is getting from a web cam (color input and gray scale output). *If the above is true.....(*theora use YUV color space*)* it is possible that get a gray scale video output by just considering only the Y component of the vi...

Hello, I have two short questions concerning a key (legend) in a lattice plot. I have points represented by two different plot characters (crosses and circles) and they are colored from light to dark gray. I would like to have 3 parts in my legend showing the two different plot characters in the first two lines and the last line should consist of a line segment for explaining the different shades of gray. Below you can see what I reached so far. My first problem is, that I do not get the 2 p...

When I try writing the current device to a jpeg file I keep getting a gray background for the jpeg images using dev.print. I have tried using the option bg="white" and bg="#FFFFFF" but neither seem to have any effect. If instead of writing to a screen device I open a jpeg device I can get any background color I want. This works, but I prefer to writ...

Dear R-helpers, the problem I'm facing today is to convince lattice to paint some areas in gray. The areas I would like to have in gray, are confidence bands I've googled around in the mailing list archives and eventually find some clues. This link is my starting point http://tolstoy.newcastle.edu.au/R/e2/help/07/04/15595.html I'm reproducing here the code for your convenience est...

M. Camanm posted in Jul 1999 the following message: " Is there any way to fill the bars in a barplot() with solid lines for postscript output, i.e. cross hatch or parallel lines, or a halftone gray rather than (semi) continuous-tone gray produced by gray()? S allows this, or at least used to, via the angle and density arguments to barplot(). The objective of course, is to produce camera ready black and white plots on a laser printer. The gray values produced by gray() do not reproduce well. &...

Hi, I'm trying to make a png file of a histogram. I would like a white background in the final product but end up producing a gray one, despite setting what I think are the correct parameters. Suggestions for how to properly set a white background would be welcome. Thanks in advance, Scot # for non-lattice > par("bg"="white") > par("bg") [1] "white" # for lattice background&l...