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...AD+TAX+ PT+B+LSTAT) Please: Show me the tree. Mark -------- Original Message -------- Subject: Re: [R] help with rpart From: "Stephen Milborrow" <[1]milbo at sonic.net> Date: Fri, July 29, 2011 7:54 am To: <[2]mark at statcourse.com> Cc: <[3]sarah.goslee at gmail.com> Mark, check out my rpart.plot package. See also the PDF vignette that comes with the package. Steve [4]www.milbo.users.sonic.net ------------------------------------------------------------------ Message: 69 Date: Thu, 28 Jul 2011 16:10:35 -0400 From: Sarah...

...on a project involving creating many detailed weaving patterns, so I wrote R code to automate it. Details here: http://stringpage.com/blog/?p=822 If the overlap between R users and avid tablet weavers turns out to be >> 1, I'll polish it up and turn it into a package. Sarah -- Sarah Goslee http://www.functionaldiversity.org

...n the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM, "Sarah Goslee" <sarah.goslee at gmail.com> wrote: > So. Given that the second and third panels of the first figure in the > first link I gave show a decision tree with decision rules at each split > and the number of samples at each direction, what _exactly_ is your > problem? > > &...

Hi, I have a set of x, y points where x represents dates and y actual values. I am trying to plot a line graph of the data with points on top, but R is connecting the wrong points with lines. Does anyone know how I can rectify this. Please see sample below: x= 24/09/2009 09:13 16/10/2009 11:17 24/10/2009 21:43 11/09/2009 18:34 22/08/2009 15:45 10/08/2009 00:30 14/08/2009 14:52 24/09/2009

...346300L, 672000L, 729000L, 470800L, 423000L, 72184L, 368022L, 1037500L), .Dim = c(10L, 3L), .Dimnames = list(NULL, c("AGE", "OLD_CAR_PURCHASE_YRS", "Total.Spend.With.Maruti"))) Please advice if this would help. Thank you. Shivi On Sat, Mar 17, 2018 at 8:45 PM, Sarah Goslee <sarah.goslee at gmail.com> wrote: > I'm assuming you are using the corrplot package. > > If so, your data object does need to be a matrix, not a data frame. > Since it's already a data frame, your line of code: > > as.matrix(as.data.frame(CR1)) > > doesn'...

...= TRUE) ? library(rpart) ? fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) predict(fit,data[4,]) plot only reveals part of the tree in contrast to the results on obtains with CART or C5 -------- Original Message -------- Subject: Re: [R] help with rpart From: Sarah Goslee <sarah.goslee at gmail.com> Date: Fri, July 29, 2011 7:48 am To: mark at statcourse.com Cc: r-help at r-project.org Mark, The R-help list is not telepathic. I asked entirely reasonable follow-up questions intended to elicit from you a more extensive explanation of your problem. On Fri, Jul...

Dear list, I was curious how to subtract a vector from matrix? Say, I have mat <- matrix(1:40, nrow=20, ncol=2) x <-c(1,2) I want, x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements of x against column elements in mat. But x-mat won't do it. Thanks, Mike [[alternative HTML version deleted]]

.... Just like my email in > the beginning i need the output that looks like if A and if B and if C then > %77 it will be D. The examples you provided are just simply not similar. > They are different and would take interpretation to get what i need. > On Apr 14, 2016 1:26 AM, "Sarah Goslee" <sarah.goslee at gmail.com> wrote: > > > So. Given that the second and third panels of the first figure in the > > first link I gave show a decision tree with decision rules at each split > > and the number of samples at each direction, what _exactly_ is your > &...

...23000L, 72184L, 368022L, > 1037500L), .Dim = c(10L, 3L), .Dimnames = list(NULL, c("AGE", > "OLD_CAR_PURCHASE_YRS", "Total.Spend.With.Maruti"))) > > Please advice if this would help. > > Thank you. Shivi > > On Sat, Mar 17, 2018 at 8:45 PM, Sarah Goslee <sarah.goslee at gmail.com> > wrote: > >> I'm assuming you are using the corrplot package. >> >> If so, your data object does need to be a matrix, not a data frame. >> Since it's already a data frame, your line of code: >> >> as.matrix(as.data...

...em. The examples are sort of similar. You just provided links to general info about trees. Sent from my Verizon, Samsung Galaxy smartphone<div> </div><div> </div><!-- originalMessage --><div>-------- Original message --------</div><div>From: Sarah Goslee <sarah.goslee at gmail.com> </div><div>Date: 4/13/16 8:04 PM (GMT-06:00) </div><div>To: Michael Artz <michaeleartz at gmail.com> </div><div>Cc: "r-help at r-project.org" <R-help at r-project.org> </div><div>Subject: Re: [...

I am trying to replicate the SAS proc univariate in R. I got most of the stats I needed for a by grouping in a data frame using: all1 <- ddply(all,"ACT_NAME", summarise, mean=mean(COUNTS), sd=sd(COUNTS), q25=quantile(COUNTS,.25),median=quantile(COUNTS,.50), q75=quantile(COUNTS,.75), q90=quantile(COUNTS,.90), q95=quantile(COUNTS,.95), q99=quantile(COUNTS,.99) )

...a=seq(as.Date("2009-12-01"),by="weeks",length=11) axis(1, at = a, labels = format(a, "%Y %b %d"), cex.axis=0.6) #Error :$ operator is invalid for atomic vectors Thanks Ahmed Attia, Ph.D. Agronomist & Soil Scientist On Fri, Jun 30, 2017 at 10:37 AM, Sarah Goslee <sarah.goslee at gmail.com> wrote: > There are a bunch of things wrong here, although without a > reproducible example I can't really fix most of them. > > - You're overwriting SH within the loop. > - You're running the regression 2641 times, even though the result...

...there, e.g., frame 1,AB 2,BCD will turn into 1,1,1,0,0 2,0,1,1,1 however this would work only if the number of different field values is manageable. What do people do? Can I have a columns of "sets" in data frame? Does R support the "set" data type? Thanks! PS. thanks to Sarah Goslee who answered my previous question in so much detail! -- Sam Steingold (http://sds.podval.org/) on Ubuntu 11.10 (oneiric) X 11.0.11004000 http://camera.org http://openvotingconsortium.org http://iris.org.il http://mideasttruth.com http://memri.org http://honestreporting.com Don't take life too...

...ecific > than "Re: Contents of R-help digest..." > > > Today's Topics: > > 1. how can I show the xlab and ylab information while using > layout (Jie Tang) > 2. Re: how can I show the xlab and ylab information while using > layout (Sarah Goslee) > 3. Re: Extracting arithmetic mean for specific values from > multiple .txt-files (Rui Barradas) > 4. Re: How to use external image with R plot? (Michael Sumner) > 5. Re: is it possible to insert a figure into into another new > figure by r script (Thomas...

Hi, Can R read in .xyz files? If so, what is the package, thanks -- Shane [[alternative HTML version deleted]]

I have started using the circular package but it is not recognizing the function arrows.circular. I attempted to use the example provided in the circular manual. Here is the example code using the circular package: plot(rvonmises(10, circular(0), kappa=1)) arrows.circular(rvonmises(10, circular(0), kappa=1)) arrows.circular(rvonmises(10, circular(0), kappa=1), y=runif(10), col=2)

Dear r-Gods! I am interesting in making an equivalent command like outreg in stata where I get all my 8 regressions in one table. Does R have an easy command to that? MVH Dave [[alternative HTML version deleted]]

Hi just a quick question in which I must use the "function and return" part of R. If I was asked to define a function called "median" where the function has a single argument x and returns the median value of a vector. How would I go about saying the median = element x in terms of n (say (n + 1)/2 or whatever it would be) if there is an even amount of elements, or x in terms

Hi R, Please solve my problem........... I am extracting Bloomberg data from R, in a loop. R is getting fatigued by doing this process and gives some errors. I introduced sleep function. Doing this sometimes I get the results and sometimes not. I even noticed that if I give complete rest for R (don't open R window) for 1 day and then run my code with the sleep function, then the

...ames. > > Try this instead: > > yourframe[,30:51] <- cbind( newcolumn,yourframe[,30:50]) > > Adjust column names after via: > > names(yourframe) [30:51] <- c(newcolname,names(yourframe[30:50]) > > Cheers, > Bert > > On Mon, Aug 1, 2011 at 10:10 AM, Sarah Goslee <sarah.goslee at gmail.com> wrote: >> x <- cbind(x[,1:29], newcolumn, x[,30:ncol(x)]) >> >> On Mon, Aug 1, 2011 at 12:59 PM, Bansal, Vikas <vikas.bansal at kcl.ac.uk> wrote: >>> Dear all, >>> >>> I have a very simple question.I have data f...