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...[,-1]-cy[,-nrow(cy)]) 1 2 3 4 21 3 4 8 5 5 22 3 6 8 6 NA 23 4 5 11 4 3 24 4 2 1 4 6 25 6 4 4 6 6 However, if I use that I lose the first column label. Is there a way to do something like this without losing that label? (again, if possible, that also works for data frames?) thanks! Glen_B. -- View this message in context: http://www.nabble.com/Cumulative-row-sums%2C-row-differences-tp24692986p24692986.html Sent from the R help mailing list archive at Nabble.com.

For the life of me I couldn't work out what to searc I have an m*n numeric matrix x and a numeric vector y (of length m+n-1) How do I do a calculation like this? z[i,j] = x[i,j] * y[i+j] ? Well, one can write a pair of loops, or write a single loop within which we calculate a vector at a time, but ... is there a "neat" way to do it? tiny example:

Dear all, How can I fit a truncated power law to a vector? I can't find a function to do that. If the function provides an AIC, even better. John

Dear R-listers, I want to reperfrom a poisson distribution test that presented in a recent-published biological research paper (Plant Physiology 2008, vol 148, pp. 1189-1200). That test is about the occurrence number of a kind of gene in separate chromosomes. For instance: The observed gene number in chromosome A is 36. The expected gene number in chromosome A is 30. Then, the authors got a