search for: ghi

Dear R helpers I have following data stocks <- c("ABC", "DEF", "GHI", "JKL") prices_df <- data.frame(ABC = c(17,24,15,22,16,22,17,22,15,19),                                          DEF = c(22,28,20,20,28,26,29,18,24,21),                                           GHI = c(32,27,32,36,37,37,34,23,25,32),                                         ...

Sorry about the odd terminology, but I suspect that my intent might be completely missed had I used "aggregate" or "classify" (each of which appears to have some rather special meanings in statistical analysis and modeling). I have some data about software builds; one of the characteristics of each is the name of the branch. A colleague has generated some fairly interesting

If I have this object: x <- c("abc\ndef", "", "ghi") and I write it to a file using `writeLines(x, "test.txt")`, my text editor sees a 5 line file: 1: abc 2: def 3: 4: ghi 5: which is what I'd expect: the last line in the editor is empty. If I use `readLines("test.txt")` on that file, I get the vec...

Hi all I'm have a character vector and would like to suppress the blanks if there are more than one after the other. Example: Character value is: "abc def ghi" The result should be: "abc def ghi" I know that it's possible to delete the leading blanks with the command "trim". But how can I delete blanks within a character? Thank you very much in advance for an answer Thomas

...l data (where x contains several thousand lines), Rui's seems best. Duncan On 2025-02-05 9:13 a.m., peter dalgaard wrote: > This also seems to work: > >> strsplit(paste(x,collapse="\n"),"\n")[[1]] > [1] "abc" "def" "" "ghi" > > >> On 5 Feb 2025, at 14:44 , Duncan Murdoch <murdoch.duncan at gmail.com> wrote: >> >> If I have this object: >> >> x <- c("abc\ndef", "", "ghi") >> >> and I write it to a file using `writeLines(x,...

...sociated labels. This means, on a continious scale between 1-100, there are 5 markers. E.g. 'abc' marks the timestampls between 10 and 19, 'def' marks the timestamps between 20 and 32, and so on. a <- data.frame(timestamp=c(3,5,8), mylabel=c("abc","def","ghi")) b <- data.frame(timestamp=c(1:10)) I would like to assign these labels as an extra collumn 'label' to the data.frame b which currently only consists of a the timestamp. The output would then look like this: timestamp label 1 1 NA 2 2...

On Wed, 5 Feb 2025 08:44:12 -0500 Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > If I have this object: > > x <- c("abc\ndef", "", "ghi") > > and I write it to a file using `writeLines(x, "test.txt")`, my text > editor sees a 5 line file: > > 1: abc > 2: def > 3: > 4: ghi > 5: > > which is what I'd expect: the last line in the editor is empty.If I > use `re...

...#39;ll go thru my Firewall at Warp 9.9 regardless of other traffic from other users. Assumptions: (1) I don''t care about slowing down other traffic flows. H.323 packets should be serviced first no matter what. (2) Any traffic with source or destination public IP Address "abc.def.ghi.jkl" or private IP Address 192.168.16.4 is to/from from the videoconference device. After all the reading and studying, is it really this simple? Does anyone have ideas on how to test this? How do I watch packets to see which packets go into what PFIFO band? #!/bin/sh VTC1_PRIVATE=&quot...

This also seems to work: > strsplit(paste(x,collapse="\n"),"\n")[[1]] [1] "abc" "def" "" "ghi" > On 5 Feb 2025, at 14:44 , Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > > If I have this object: > > x <- c("abc\ndef", "", "ghi") > > and I write it to a file using `writeLines(x, "test.txt")`, my text edit...

...several thousand lines), Rui's seems best. > > Duncan > > On 2025-02-05 9:13 a.m., peter dalgaard wrote: >> This also seems to work: >>> strsplit(paste(x,collapse="\n"),"\n")[[1]] >> [1] "abc" "def" "" "ghi" >>> On 5 Feb 2025, at 14:44 , Duncan Murdoch <murdoch.duncan at gmail.com> wrote: >>> >>> If I have this object: >>> >>> x <- c("abc\ndef", "", "ghi") >>> >>> and I write it to a file usi...

Hi, my data frame is x<-data.frame(ID=c("abc/def","abc/def/ghi","abc","mno/pqr/st/ab")) I want to split my column ID using "/" as the place to split. How can I do that without telling the code how many sub-columns. I could use nchar(gsub("[^/]","",x$ID)) to get how many "/" are in each row of th...

...age encoded with Shift-JIS. I have an HTML construct like: <head> <meta http-equiv="content-type" content="text/html; charset=Shift_JIS"> </head> <body> ... <ul id="test"> <li><a>abc</a><a>def</a><a>ghi</a><span>123</span></li> <li><a>abc</a><a>def</a><a>ghi</a><span>123</span></li> <li><a>abc</a><a>def</a><a>ghi</a><span>123</span></li> </ul> ....

...sociated labels. This means, on a continious scale between 1-100, there are 5 markers. E.g. 'abc' marks the timestampls between 10 and 19, 'def' marks the timestamps between 20 and 32, and so on. a <- data.frame(timestamp=c(3,5,8), mylabel=c("abc","def","ghi")) b <- data.frame(timestamp=c(1:10)) I would like to assign these labels as an extra collumn 'label' to the data.frame b which currently only consists of a the timestamp. The output would then look like this: timestamp label 1 1 NA 2 2...

...ot;: 3, "value": "ABC" }, { "key": "Key2", "t": 3, "value": "DEF" } ] -h.node_set_values (b, values) +h.node_set_values (B, values) value1 = { "key": "Key3", "t": 3, "value": "GHI" } -h.node_set_value (b, value1) +h.node_set_value (B, value1) value1 = { "key": "Key1", "t": 3, "value": "JKL" } -h.node_set_value (b, value1) +h.node_set_value (B, value1) -val = h.node_get_value (b, "Key1") +val = h.node_get_v...

Dear all, I have a data frame containing the results of an experiment. Like this: a<-seq(1,4,by=1) b<-seq(1,2,by=1) test<-expand.grid(b,a,a) colnames(test)<-c("replicates","bins", "groups") test$abc <- rnorm(32) test$def <- rnorm(32) test$ghi <- rnorm(32) test The following code snippet aggregates the data for one variable and then draws a plot: tmp <- aggregate(test$abc, list( test$bins, test$groups), mean) colnames(tmp) <- c("bins", "groups", "abc") tmp #pltName <- paste("line_da...

..."abc") BODY "def") 85 select "Archive.2004.2005.2006.2007.2008" 86 UID fetch 1:* (FLAGS) 87 uid SEARCH UNDELETED (OR (OR BODY "xyz" BODY "abc") BODY "def") 88 IDLE Searching for "xyz", "abc", "def" and "ghi" in Archive and subfolders 217 secs 89 select "Archive" 90 uid SEARCH UNDELETED (OR (OR (OR BODY "xyz" BODY "abc") BODY "def") BODY "ghi") 91 select "Archive.2004" 92 UID fetch 1:* (FLAGS) 93 uid SEARCH UNDELETED (OR (OR (OR BODY &qu...

Hi all, I have this code, but the marginal distribution plot doesn?t appear aligned with the left plot. I think could be something about layout or par() mar. The code was programmed by me time ago. Can anyone help me to get the marginal distribution on the center (more higher centered) id.txt Could have this code: 05/01/2016;9335,200195 06/01/2016;9197,400391 07/01/2016;9059,299805

I am new to R but am experienced SAS user and I was hoping to get some help on counting the occurrences of a character within a string at a row level. My dataframe, x, is structured as below: Col1 abc/def ghi/jkl/mno I found this code on the board but it counts all occurrences of "/" in the dataframe. chr.pos <- which(unlist(strsplit(x,NULL))=='/') chr.count <- length(chr.pos) chr.count [1] 3 I'd like to append a column, say cnt, that has the count of "/" for e...

...all, I wonder how you can replace all words that need to be changed using replacePatterns(). The following is my code. I want to replace both "abc" and "def" to " Yes ". However, I can only replace the first occurrence in sample[[1]]. > sample[[1]] [1] abc def ghi > change <- c("abc","def") > replacePatterns(sample[[1]],change," Yes ") [1] Yes def ghi Thank you so much!!!! -- View this message in context: http://www.nabble.com/replacePatterns%28%29-for-multiple-words-replacement-in-tm-tp24921281p24921281.html Sent fr...

dear all, I have some very long strings and would like to break up each long string into multiple strings with a fixed length, e.g. to break up abcdefghijkl into abc, def, ghi, jkl I tried a couple of commands but was not successful. Any help will be appreciated. Best, Jimmy -- View this message in context: http://www.nabble.com/break-up-a-string-into-strings-with-a-fixed-length-tp25712955p25712955.html Sent from the R help mailing list archive...