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On Tue, 14 Nov 2023 at 09:41, Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > > Also why should that difference result in different behavior? That's justifiable, I think; consider: > d1 = data.frame(a = 1:4) > d2 = d3 = data.frame(b = 1:2) > row.names(d3) = c("a", "b") > data.frame(d1, d2) a b 1 1 1 2 2...

Also why should that difference result in different behavior? On Tue, Nov 14, 2023 at 9:38?AM Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > > In that case identical should be FALSE but it is TRUE > > identical(a1, a2) > ## [1] TRUE > > > On Tue, Nov 14, 2023 at 8:58?AM Deepayan Sarkar > <deepayan.sarkar at gmail.com> wrote: > > > > They differ in whether the row na...

...eepayan.sarkar at gmail.com> wrote: > > They differ in whether the row names are "automatic": > > > .row_names_info(a1) > [1] -3 > > .row_names_info(a2) > [1] 3 > > Best, > -Deepayan > > On Tue, 14 Nov 2023 at 08:23, Gabor Grothendieck > <ggrothendieck at gmail.com> wrote: > > > > What is going on here? In the lines ending in #### the inputs and outputs > > are identical yet one gives a warning and the other does not. > > > > a1 <- `rownames<-`(anscombe[1:3, ], NULL) > > a2 <- anscombe[1:3, ] &gt...

Also note that the functionality discussed could be regarded as a generalization of matrix multiplication where * and + are general functions and in this case we have * replaced by == and + replaced by &. On Fri, Oct 11, 2019 at 10:46 AM Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > > Using the example in the link here are two one-liners: > > A <- c(2,3,4,1,2,3,4,1,1,2) > x <- c(1,2) > > # 1 - zoo > library(zoo) > which( rollapply(A, length(x), identical, x, fill = FALSE, align = "left") ) > ##...

...PM, Michael Lawrence <lawrence.michael at gene.com> wrote: > I'll add the drop argument but I'm wondering about the order of the > levels. Should we set the levels to unique(names(x)) or sort them, > too? > > On Mon, Jun 27, 2016 at 10:39 AM, Gabor Grothendieck > <ggrothendieck at gmail.com> wrote: >> stack() seems to drop empty levels. Perhaps there could be a >> drop=FALSE argument if one wanted all the original levels. In the >> example below, we may wish to retain level "b" in s$ind even though >> component LL$b has length 0. &gt...

Hi, I am using RpgSQL to retrieve data from a PostgreSQL database wich is with encoding UTF8, and I have some Chinese character in one of the columns, unfortunately R can't show it correctly. > df <- dbGetQuery(con, "select * from test") > df a b 1 1 ????????\xa2 2 2 ???? EURO\xa1 I see the following option, do I need to change the encoding option to show

...back to you. Nevertheless, having a installer and a "portable" version is something pretty common (R Studio, Notepad++ and 7Zip pop to my mind now) and pretty helpful to deal with security restrictions, so I thought R had one, somewhere. On Fri, Jan 26, 2018, 00:49 Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > Can you clarify what the nature of the security restriction is? > > If you can't run the R installer then how it is that you could run R? > That would still involve running an external exe even if it came > in a zip file. > > Could it be that the...

.... > LL <- list(a = 1:3, b = list()) > s <- stack(LL) > str(s) 'data.frame': 3 obs. of 2 variables: $ values: int 1 2 3 $ ind : Factor w/ 1 level "a": 1 1 1 -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com

.... I cant execute exes. But I can unzip files. Thanks Gabor, I had that in mind, but can't execute the exe due to security restrictions. Geez, really, treating people who ask questions this way just makes you don't want to ask a single one. On Thu, Jan 25, 2018, 11:19 Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > I believe that the ordinary Windows installer for R can produce a > portable result by choosing the appropriate configuration options from the > offered screens when you run the installer Be sure to enter the desired > path in the Select Destination Location...

...nzip files. > Thanks Gabor, I had that in mind, but can't execute the exe due to security > restrictions. > Geez, really, treating people who ask questions this way just makes you > don't want to ask a single one. > > > On Thu, Jan 25, 2018, 11:19 Gabor Grothendieck <ggrothendieck at gmail.com> > wrote: >> >> I believe that the ordinary Windows installer for R can produce a >> portable result by choosing the appropriate configuration options from the >> offered screens when you run the installer Be sure to enter the desired >> path in the...

They differ in whether the row names are "automatic": > .row_names_info(a1) [1] -3 > .row_names_info(a2) [1] 3 Best, -Deepayan On Tue, 14 Nov 2023 at 08:23, Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > > What is going on here? In the lines ending in #### the inputs and outputs > are identical yet one gives a warning and the other does not. > > a1 <- `rownames<-`(anscombe[1:3, ], NULL) > a2 <- anscombe[1:3, ] > > ix <- 5:8 > >...

Hi, I have a question for my simulation problem: I would like to generate a positive (or semi def positive) covariance matrix, non singular, in wich the spectral decomposition returns me the same values for all dimensions but differs only in eigenvectors. Ex. sigma [,1] [,2] [1,] 5.05 4.95 [2,] 4.95 5.05 > eigen(sigma) $values [1] 10.0 0.1 $vectors [,1]

...BF87185B/www.dans.knaw.nl> > DANS is an institute of the Dutch Academy KNAW <http://knaw.nl/nl> and funding organisation NWO <http://www.nwo.nl/>. > > ?On 23/07/2018, 16:52, "R-devel on behalf of Gabor Grothendieck" <r-devel-bounces at r-project.org on behalf of ggrothendieck at gmail.com> wrote: > > Note the inconsistency in the names in these two examples. X.Time in > the first case and Time.1 in the second case. > > > transform(BOD, X = BOD[1:2] * seq(6)) > Time demand X.Time X.demand > 1 1 8.3 1...

...he second does not. Though not wrong, it seems inconsistent. list(a = 1, b = 2) ## $`a` ## [1] 1 ## ## $b ## [1] 2 R.version.string ## [1] "R version 3.5.1 Patched (2018-07-02 r74950)" -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com

something like "sprintf" in C? so I can do: print(sprintf("the correct result is %3.4f\n", myresult)); ------- Also, I am desperately looking for a "clear console screen" function in R... thanks a lot! [[alternative HTML version deleted]]

Dear All, The following code should return 1, but it returns 0: source("http://r-bc.googlecode.com/svn/trunk/R/bc.R") bc("9 % 2") Do you confirm this bug? Paul

I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =

...(presidents, order = c(1, 0, 0)) Tracing optim(init[mask], armafn, method = optim.method, hessian = TRUE, .... on exit Error in str(returnValue()) : could not find function "returnValue" -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com

.../4) ## Error in my.compose2(sin, cos, tan)(pi/4) : unused argument (tan) Seems like a bug in R. This is taken from: https://stackoverflow.com/questions/52463170/a-recursive-compose-function-in-r -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com

I have two vectors, a and b. b is a text file. I want to find in b those elements of a which occur at the beginning of the line in b. I have the following code, but it only returns a value for the first value in a, but I want both. Any ideas please. a = c(2,3) b = NULL b[1] = "aaa 2 aaa" b[2] = "2 aaa" b[3] = "3 aaa" b[4] = "aaa 3 aaa"