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alex
2008 Oct 27
1
Exponential regression (Y = exp(a*X)) and standard error of Ŷi
...Xi.
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Well,
> exp1 <- nls(Y~exp(X*a), start=list(a=0.3), trace=T)
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from this I can get summary statistics, 'a' is different from what i obtained using SPSS. Can someone help please atleast with getting SE of ?i.
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I wrote very long to make the question clear.
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thanks in advance
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ggalex
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Helsinki, Finland
ggalex2002 at yahoo.com