search for: getvoidty

...{ // Function *F = M.getFunction("sleep"); // hook = Function::Create(F->getFunctionType(), GlobalValue::ExternalLinkage, "hook", F->getParent()); Constant *hookFunc; hookFunc = M.getOrInsertFunction("hook", Type::getVoidTy(M.getContext()), Type::getVoidTy(M.getContext()), (Type*)0); hook= cast<Function>(hookFunc); for(Module::iterator F = M.begin(), E = M.end(); F!= E; ++F) { for(Function::iterator BB = F->begin(), E = F->end(); BB != E; ++BB)...

Hi, I want to insert a function with a void type parameter, for example: int foo(void); OI declared fcall2 = M.getOrInsertFunction("foo", IntegerType::get(M.getContext(), 32), Type::getVoidTy(M.getContext())); then the question is how to get the void type value to make the CallInst inserted sucessfully? (what should be ********) CallInst::Create(fcall2, ******, "", insertPos); -- --Shuying

...ls only to me: CC the mailing > list too. That way others can join in and the discussion is > archived for the benefit of people with similar questions in > the future. > > On 20/11/11 01:29, 赵夏 wrote: > > Thank you for your reply, > > But after I remove the second Type::getVoidTy(M.getContext()),Another > problem > > occured > > > > opt: Value.cpp:175: void llvm::Value::setName(const llvm::Twine&): > Assertion > > `!getType()->isVoidTy() && "Cannot assign a name to void values!"' > failed. > > Probably you...

...ode that I have written to get the function type is: const std::vector<Type *> ParamTys; ParamTys.push_back(IntegerType::getInt32Ty(Context)); ParamTys.push_back(IntegerType::getInt32Ty(Context)); ParamTys.push_back(IntegerType::getInt32Ty(Context)); ParamTys.push_back(PointerType::get(Type::getVoidTy(Context), 0)); ParamTys.push_back(PointerType::get(Type::getVoidTy(Context), 0)); FunctionType *ftype = FunctionType::get(Type::getVoidTy(Context), ParamTys, true); And the errors are: /home/akshay/llvm/llvm-2.9/lib/Transforms/AliasPass/pass2.cpp: In member function ‘virtual bool {anonymous}::He...

Hi, sivart Thanks for pointing it out. I used it, and it works. Thank you again. BTW, for any later reference, the function prototype declaration with no arguments is not what I wrote: fcall2 = M.getOrInsertFunction("foo", IntegerType::get(M.getContext(), 32), Type::getVoidTy(M.getContext())); INSTEAD, I changed to : fcall2 = M.getOrInsertFunction("foo", FunctionType::get( IntegerType::get(M.getContext(), 32), false)); combining with this, the insertion works finally. Thanks, --Shuying On Mon, Nov 22, 2010 at 6:07 PM, <o.j.sivart at gmail.com> wrote:...

...ed for <type>. FunstionType is a type, so alloca for functionType should be possible? Not? If we have a valid Module *m we can get an allocate instruction allocating space for a non-argumented function as follows: AllocaInst* pa2 = new AllocaInst( FunctionType::get( Type::getVoidTy(m->getContext()), false ) , 1, "myName"); but how about nonvar-argumented functions? E.g. I32,I16 std::vector<Type*>FuncTy_args; FuncTy_args.push_back(IntegerType::get(mod->getContext(), 32)); FuncTy_args.push_back(IntegerType::get(mod->getContext(), 16)); AllocaIn...

...ot;, I can use the "getOrInsertFunction" call from Module class as follows: std::vector<Type*> FooArgs; FooArgs.push_back(IRB.getInt64Ty()); Value *FooFunction = M.getOrInsertFunction(std::string("foo"), FunctionType::get(IRB.getVoidTy(), ArrayRef<Type*>(FooArgs), false)); IRB.CreateCall(FooFunction, IRB.CreateLoad(LenAlloca)); I want to create a similar call, but to the pointer of foo ("foo_ptr" is defined as "(void) *foo_ptr (int)"). In C code, I would just call "foo_ptr(var)", and it woul...

...d); Regards On 23/11/2010, at 11:20 AM, Shuying Liang wrote: > Hi, I want to insert a function with a void type parameter, > for example: int foo(void); > OI declared > fcall2 = M.getOrInsertFunction("foo", > IntegerType::get(M.getContext(), 32), > Type::getVoidTy(M.getContext())); > > then the question is how to get the void type value to make the > CallInst inserted sucessfully? (what should be ********) > CallInst::Create(fcall2, ******, "", insertPos); > > > -- > > --Shuying > _________________________________...

...pe in >> that it is only allowed as the return value of functions and as the type of >> instructions like store. It seems better (though also not particularly >> high priority) to eliminate it to make the type system more consistent. >> > MVT::isVoid and Type::VoidTyID (getVoidTy) have equivalent relation in LLVM. I am wondering to know whether the relation becomes MVT::isVoid corresponding to { } If eliminating void type? Thanks a lot Mitnick -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.llvm.org/pipermail/llvm-dev/attac...

Hello Duncan, There is a discussion with Chris Lattner: http://old.nabble.com/Eliminating-the-'void'-type-td33726468.html In the discussion, Chris Lattner suggest Type::getVoidTy() should still exist and return {} for API continuity. If VoidTy and isVoidTy() go away, how do deal with the isVoidTy() function call in LLVM source tree? Another issue is: What should ReturnInst constructor looks like with VoidTy or not? Thanks Mitnick

...ocal) 64 bit integer in LLVM IR, I used: Value *var = builder.CreateAlloca(Type::getInt64Ty(Ctx)); I wish to pass this variable to a function "void foo(unsigned long)". I created the signature of function foo() as follows: Constant *func = M->getOrInsertFunction("foo", Type::getVoidTy(Ctx),Type::getInt64Ty(Ctx), NULL); To pass the newly created variable var to foo(): Value *args[] = {var}; builder.CreateCall(func, args); However, LLVM backend throws assertion error: "Calling a function with a bad signature!" If I print the types of the following: errs() << *Ty...

...int argc, char* argv[]) { printf("hello world\n"); exit(0); //***I want to insert this exit } My llvm code snippet is vector<const Type *> params = vector<const Type *>(); params.push_back(Type::getInt32Ty(M.getContext())); FunctionType *fType = FunctionType::get(Type::getVoidTy(M.getContext()), params, false); Constant *temp = M.getFunction("exit", fType); if(!temp){ errs() << "exit function not in symbol table\n"; exit(1); } Function *f = cast<Function>(temp); CallInst *ci = CallInst::Create(...) On Thu, Mar 31, 2011 at 2...

...ute(~0, Attribute::NoReturn); > abort->addAttribute(~0, Attribute::NoUnwind); > > However, I do not know what to fill up in /*POINTER TO ABORT*/. Can > anyone help me? Something like: // Once, M = llvm::Module*, C = LLVMContext&: FunctionType *AbortFTy = FunctionType::get(Type::getVoidTy(C), false); Function *AbortF = Function::Create(AbortFTy, GlobalValue::ExternalLinkage, "abort", M); // Each call site: CallInst *abort = CallInst::Create(AbortF, ... Nick > > Thank you very much, > > Victor > > > > _____________________________________________...

Hi Team, I am migrating one of the Pass that was written for llvm2.2 or older to llvm3.1. The code snippet looks like the following: Constant *func; void add( Module *M) { func = M->getOrInsertFunction("func", Type::getVoidTy(M->getContext()), NULL); } virtual bool runOnModule(Module &M) { add (&M); for(Module::iterator F = M.begin(), E = M.end(); F != E; ++F) { Function *fun = dyn_cast<Function>(F); Value *Opts[1]; BasicBlock &bb = F->getEntryBlock(), *...

Guys, I would like to instrument the bytecode that LLVM produces with assertions. I have written the instrumentation code manually, but I do not know how to halt the program in case the assertion is false. I took a look into the bytecode that LLVM produces for a program like: #include <stdlib.h> int main() { exit(1); } And it is like this: define i32 @main() nounwind { entry:

Akshay Jain <jivan.molu at gmail.com> writes: > I have tried it, but I always end up with some kind of error. Can you > explain how can I get a function type for function which returns void > (nothing) and it's arguments are (int, int, int, void *, void *, ...) ?? Instead of getting something to cut&paste, you would be much more enriched if the problematic code and the

Hi Dan, >> I am willing to do "eliminating the void type" project. > > Is this really a good idea? I'm not going to argue at length > about it, but it is worth thinking about. > > The only practical downsides of void are when newcomers take C's > syntax for functions with no arguments a little too literally, or > when they try to create pointers to

Hi LLVM, In lib/VMCare/Verifier.cpp::visitInstruction, we have such code 1287 // Check that the return value of the instruction is either void or a legal 1288 // value type. 1289 Assert1(I.getType() == Type::getVoidTy(I.getContext()) || 1290 I.getType()->isFirstClassType() 1291 || ((isa<CallInst>(I) || isa<InvokeInst>(I)) 1292 && isa<StructType>(I.getType())), 1293 "Instruction returns a non-scalar type!", &I); line 1291-1292...

Hi: In a function pass, I tried to create a function which takes a int32 and return void. When I call this function with CallInst::Create and using opt, it always has the error report: opt: Value.cpp:189: void llvm::Value::setName(const llvm::Twine&): Assertion `getType() != Type::getVoidTy(getContext()) && "Cannot assign a name to void values!"' failed. if I change the return type to int32, then it works. so what is the special trick to use a function with void return type. Any help would be appreciated. -- --Gang. -------------- next part -------------- An...

...nt to insert this exit > } > My llvm code snippet is > > vector<const Type *> params = vector<const Type *>(); The initialization is unnecessary (but harmless). > params.push_back(Type::getInt32Ty(M.getContext())); > > FunctionType *fType = FunctionType::get(Type::getVoidTy(M.getContext()), > params, false); > > Constant *temp = M.getFunction("exit", fType); M.getOrInsertFunction("exit", fType); > if(!temp){ > > errs() << "exit function not in symbol table\n"; > > exit(1); > > } > > Function *f...