search for: getfunctiontype

...n + 237 14 opt 0x0000000000521f91 Stack dump: 0. Program arguments: opt -load ../../../Release+Asserts/lib/Blocks.so -blocks Aborted (core dumped) ***The code is > std::vector<Type*> ArgTypes; > ValueToValueMapTy VMap; >FunctionType *FTy = FunctionType::get(F.getFunctionType()->getReturnType(), ArgTypes, F.getFunctionType()->isVarArg()); >Function *NewF = Function::Create(FTy, F.getLinkage(), F.getName()); > SmallVector<ReturnInst*, 8> Returns; >CloneFunctionInto(NewF, (Function*) &F, VMap, false, Returns, "_...

...torial paper - IRBuilder<> builder(block)) So, I believe this is just outdated information? I think it just need some quick attention with getting materials up to date. In the end I got following code, that satisfy my needs: llvm::Constant* c = M.getOrInsertFunction(dummyFunctionName, F.getFunctionType()); llvm::Function* dummy = llvm::cast<llvm::Function>(c); dummy->setLinkage(llvm::Function::ExternalLinkage); dummy->setCallingConv(llvm::CallingConv::C); llvm::BasicBlock* block = llvm::BasicBlock::Create("entry", dummy); // no context needed llvm::IRBuilder b...

Hello, I have a simple question. How to create "dummy" function which will have no functionality behind (return nothing and do nothing)? Currently I'm trying to do this: llvm::Constant* c = Module.getOrInsertFunction("dummy", FunctionThatNeedsToBeReplaced.getFunctionType()); llvm::Function* dummy = llvm::cast<llvm::Function>(c); This way I create new function that do nothing.Then next step is: FunctionThatNeedsToBeReplaced.replaceAllUsesWith(dummy); This code is doing what I want to do, but it ends up with exception: ERROR: Program used external function &...

...(block)) > > So, I believe this is just outdated information? I think it just need > some quick attention with getting materials up to date. > > In the end I got following code, that satisfy my needs: > > llvm::Constant* c = M.getOrInsertFunction(dummyFunctionName, > F.getFunctionType()); > llvm::Function* dummy = llvm::cast<llvm::Function>(c); > dummy->setLinkage(llvm::Function::ExternalLinkage); > dummy->setCallingConv(llvm::CallingConv::C); > llvm::BasicBlock* block = llvm::BasicBlock::Create("entry", dummy); > // no context ne...

...Program arguments: opt -load ../../../Release+Asserts/lib/Blocks.so > -blocks > Aborted (core dumped) > > > > ***The code is > > > > std::vector<Type*> ArgTypes; > > > ValueToValueMapTy VMap; > > >FunctionType *FTy = > FunctionType::get(F.getFunctionType()->getReturnType(), > ArgTypes, F.getFunctionType()->isVarArg()); > > >Function *NewF = Function::Create(FTy, F.getLinkage(), F.getName()); > > > SmallVector<ReturnInst*, 8> Returns; > > >CloneFunctionInto(NewF, (Function*) &...

...; I have a simple question. How to create "dummy" function which will > have no functionality behind (return nothing and do nothing)? > Currently I'm trying to do this: > > llvm::Constant* c = Module.getOrInsertFunction("dummy", > FunctionThatNeedsToBeReplaced.getFunctionType()); > llvm::Function* dummy = llvm::cast<llvm::Function>(c); Hi Oleg, Every function needs a BasicBlock, even if the basic block just contains a return. The only reason to create a function without a basic block is when the function is extern'd and imported via JIT, but I guess it...

Hi All, I generated the following code with "clang -flto" command. void test(struct StruTyName *a) { ... } Then the type of test function is "void (%struct.StruTyName.100*)" by calling function::getFunctionType API. What's the meaning of number 100? Best, Haopeng

Hi all, I am trying to extend a FunctionType to include new parameters. In particular, I want to ensure that the main function has been declared with both argsc and argsv. However there seems to be no easy way to accomplish this: llvm::Function::getFunctionType() returns a a reference to a const object, while modifying only the argument list yields an error during verification since the function type does not match its arguments. Is there any approach that I am missing or a simple workaround to this problem? Thanks in advance, and best regards, Gabr...

...} CallInst::Create(new_function->getFunctionType(), new_function, args, functionName + "__swordomp__", &F.getEntryBlock().front()); } but I am getting the following error: void llvm::Value::setNameImpl(const llvm::Twine&):...

...>> Hi All, >> >> I generated the following code with "clang -flto" command. >> >> void test(struct StruTyName *a) { >> ... >> } >> >> Then the type of test function is "void (%struct.StruTyName.100*)" by calling function::getFunctionType API. >> >> What's the meaning of number 100? >> >> Best, >> Haopeng >> _______________________________________________ >> LLVM Developers mailing list >> LLVMdev at cs.uiuc.edu http://llvm.cs.uiuc.edu >> http://lists.cs.uiuc.edu/mail...

...gt;wrote: > A CallInst in one module can't reference a Function in another module. > Build a declaration of foo in the module where you're building the > call, and call that. > > -Eli > Hmm, before emitting any code i've added this: Function::Create(fooFunction->getFunctionType(),fooFunction->getLinkage(),"foo",myModule); Now i see @foo declaration when dumping myModule, but the error is still same. -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.llvm.org/pipermail/llvm-dev/attachments/20111112/60fb08ec/attach...

I need to get the type of a call instruction to typecast a (void*) pointer to the type of the function which is called. How can I achieve that? -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.llvm.org/pipermail/llvm-dev/attachments/20130211/6a044cde/attachment.html>

...ctor<Function *> Functions; for (auto &Fn : M.functions()) { Functions.push_back(&Fn); } for (auto *F : Functions) { if (F->size() > 0) { dbgs() << "duplicating " << F->getName() << "\n"; duplicate(M, *F, F->getFunctionType()); Modified = true; } } return Modified; } char FunctionDuplication::ID = 0; INITIALIZE_PASS(FunctionDuplication, "dupl", "Duplicate every function", false, false) ModulePass *createFunctionDuplicationPass(void) { return new FunctionDuplication...

...uez wrote: > Hi all, > > I am trying to extend a FunctionType to include new parameters. In > particular, I want to > ensure that the main function has been declared with both argsc and > argsv. However > there seems to be no easy way to accomplish this: > llvm::Function::getFunctionType() returns a > a reference to a const object, while modifying only the argument list > yields an error during verification > since the function type does not match its arguments. Is there any > approach that I am missing or > a simple workaround to this problem? If I understand cor...

...he following code with "clang -flto" command. >>>> >>>> void test(struct StruTyName *a) { >>>> ... >>>> } >>>> >>>> Then the type of test function is "void (%struct.StruTyName.100*)" by calling function::getFunctionType API. >>>> >>>> What's the meaning of number 100? >>>> >>>> Best, >>>> Haopeng >>>> _______________________________________________ >>>> LLVM Developers mailing list >>>> LLVMdev at cs.uiuc.edu...

...ype of each argument of the argument list of the function. 2. Based on its data type like character array or integer array, pointer, int, char, take different action. 3. I have added following code to check its data type. // F is any function basically of type function * FunctionType *FTy = F->getFunctionType(); unsigned int numArgs = FTy->getNumParams(); //Currently just checking data type of the 0th argument. Eventually will be running it in the loop from 0 to numArgs. errs() << "\n1 Argument type int 32 : " << FTy->getParamType(0)->isIntegerTy(32); errs() <<...

...{ >> Functions.push_back(&Fn); >> } >> >> for (auto *F : Functions) { >> if (F->size() > 0) { >> dbgs() << "duplicating " << F->getName() << "\n"; >> >> duplicate(M, *F, F->getFunctionType()); >> Modified = true; >> } >> } >> >> return Modified; >> } >> >> char FunctionDuplication::ID = 0; >> INITIALIZE_PASS(FunctionDuplication, "dupl", "Duplicate every function", >> false, >>...

...t_arg_iterator I = F->arg_begin(), E = F->arg_end(); I != E; ++I) if (ValueMap.count(I) == 0) // Haven't mapped the argument to anything yet? ArgTypes.push_back(I->getType()); // Create a new function type... FunctionType *FTy = FunctionType::get(F->getFunctionType()->getReturnType(), ArgTypes, F->getFunctionType()->isVarArg()); // Create the new function... Function *NewF = Function::Create(FTy, F->getLinkage(), F->getName()); // Loop over the arguments, copying the names of the mapped argu...

...z wrote: > > Hi all, > > I am trying to extend a FunctionType to include new parameters. In > particular, I want to > ensure that the main function has been declared with both argsc and argsv. > However > there seems to be no easy way to accomplish this: > llvm::Function::getFunctionType() returns a > a reference to a const object, while modifying only the argument list yields > an error during verification > since the function type does not match its arguments. Is there any approach > that I am missing or > a simple workaround to this problem? > > If I underst...

...s not represent what the type of the actual memory object passed into the function will be. A caller can cast a pointer of one structure type to a different structure type and pass that into a function. > > // F is any function basically of type function * > FunctionType *FTy = F->getFunctionType(); > unsigned int numArgs = FTy->getNumParams(); > > //Currently just checking data type of the 0th argument. Eventually > will be running it in the loop from 0 to numArgs. > errs() << "\n1 Argument type int 32 : " << > FTy->getParamType(0)->isInte...