Displaying 20 results from an estimated 123 matches for "geom_smooths".
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geom_smooth
2023 Aug 12
2
geom_smooth
Colleagues,
Here is my reproducible code for a graph using geom_smooth
set.seed(55)
scatter_data <- tibble(x_var = runif(100, min = 0, max = 25)
?????????????????????? ,y_var = log2(x_var) + rnorm(100))
library(ggplot2)
library(cowplot)
ggplot(scatter_data,aes(x=x_var,y=y_var))+
? geom_point()+
? geom_smooth(se=TRUE,fill="blue",color="black",linetype="dashed")+
2009 Aug 18
1
ggplot2: geom_smooth and legend
Hi all,
Is that possible to remove the grey colour in the legend key that goes
with the geom_smooth? In my case it doesn't ease the reading of the
legend.
http://www.4shared.com/file/125864977/e10644f8/desorb.html
Cordialement / Regards
-------------------------------------------
Benoit Boulinguiez
Ecole de Chimie de Rennes (ENSCR) Bureau 1.20
Equipe CIP UMR CNRS 6226 "Sciences
2012 Mar 15
2
ggplot2: goem_smooth and suppress messages
Hi
When I run my script using ggplot and geom_smooth I get messages that I
would like to suppress:
p <- ggplot(dataSubset)
p <- p + aes(x = as.Date(factor(key),format="%Y%m%d")) + geom_line()
p <- p + geom_smooth(span=0.2,se=FALSE,size=0.7)
The messages look like this:
geom_smooth: method="auto" and size of largest group is <1000, so using
loess. Use 'method
2023 Aug 12
1
geom_smooth
?s 05:17 de 12/08/2023, Thomas Subia via R-help escreveu:
> Colleagues,
>
> Here is my reproducible code for a graph using geom_smooth
> set.seed(55)
> scatter_data <- tibble(x_var = runif(100, min = 0, max = 25)
> ?????????????????????? ,y_var = log2(x_var) + rnorm(100))
>
> library(ggplot2)
> library(cowplot)
>
> ggplot(scatter_data,aes(x=x_var,y=y_var))+
2023 Aug 12
1
geom_smooth
G'day Thomas,
On Sat, 12 Aug 2023 04:17:42 +0000 (UTC)
Thomas Subia via R-help <r-help at r-project.org> wrote:
> Here is my reproducible code for a graph using geom_smooth
The call "library(tidyverse)" was missing. :)
> I'd like to add a black boundary around the shaded area. I suspect
> this can be done with geom_ribbon but I cannot figure this out. Some
>
2012 Oct 30
4
Error unary operator
Hi R - listers,
I am receiving an error. Does anyone know what this means? J
ggplot(subset(foo, Rayos != "Rayos.NA"), aes(x=HTL, y=DevelopIndex,
colour=TotalEggs)) +geom_point() +geom_jitter() +
facet_grid(Aeventexhumed ~ Rayos)
+ geom_smooth(method="lm", fill=NA) + ylim(c(0, 7))
Error in +geom_smooth(method = "lm", fill = NA) :
invalid argument to unary
2016 Jul 20
4
Geom_smooth
Default level = 0.95.
Does this mean +/- 0.025 from estimate?
[[alternative HTML version deleted]]
2012 Oct 04
0
extract fit values from geom_smooth
Dear all,
I have a plot with two gaussian distributions:
ggplot( tofdf, aes( x = tof, y = counts ) ) +
geom_histogram( stat = "identity", position = "stack", fill = 2 ) +
geom_smooth( method = "nls", formula = y ~ (a/b)*exp(-(x-c)^2/(2*b^2)) +
(d/e)*exp(-(x-f)^2/(2*e^2)), se=F,
start=list(a=100, b=1, c=695, d=100, e=1, f=710),
2017 Sep 07
0
Geom_smooth
> On Jul 20, 2016, at 10:01 AM, Tom Subia <tgs77m at gmail.com> wrote:
>
> Default level = 0.95.
> Does this mean +/- 0.025 from estimate?
>
> [[alternative HTML version deleted]]
I would have guessed that it meant something along the lines of localized (or one might say "loess-ized") mean +/- 2* similarly localized standard error of the estimate. To find out
2008 Sep 22
2
adding layers in ggplot2 (data and code included)
Here is some sample data:
mydata <- read.table(textConnection("Est Group Tri
0 0 4.639644
1 0 4.579189
2 0 4.590714
0 1 4.443696
1 1 4.588243
2 1 4.650505
0 2 4.296608
1 2 4.826036
2 2 4.765386"),header=TRUE);
closeAllConnections();
I can form two plots,
2023 May 16
1
Newbie: Drawing fitted lines on subset of data
Hello,
I's still working with my tsibble of weight data for the last 20 years.
In addition to drawing an overall trend line, using lm, for the whole
data set, I'd like to draw short lines that would recompute lm and draw
it, say, just for the years from 2010:2015.
Here's a short example that I think illustrates what I'm trying to do.
The commented out sections show what
2010 Nov 30
1
Zooming in to a ggplot (a sort of ylim, but ylim won't do)
Dear Helpers,
I wonder whether you might be able to help me. I have a plot composed of
ggplot (and a follow on geom_smooth call). I would like to restrict the
display range of the y axis to a smaller range, a sort of zooming onto a
region. I attempted to use ylim, but it will effect the range (i.e. effect
the geom_smooth call). Is there any way that I can save the results up to
geom_smooth call
2024 Aug 11
1
geom_smooth with sd
Dear community
Using after_stat() I was able to visualise ggplot with standard deviations
instead of a confidence interval as seen in the R help.
p1<-ggplot(data = MS1, aes(x= Jahr, y= QI_A,color=Bio, linetype=Bio)) +
geom_smooth(aes(fill=Bio,
ymax=after_stat(y+se*sqrt(length(y))), ymin=after_stat(y-se*sqrt(y))) ,
method = "lm" , formula = y ~ x +
2024 Aug 11
1
geom_smooth with sd
Hi!
This is probably completely off base, but your ymin and y max setup lines
are different. One uses sqrt(y), while the second uses sqrt(length(y)).
Could that play a part, please?
Thank you
Erin Hodgess, PhD
mailto: erinm.hodgess at gmail.com
On Sun, Aug 11, 2024 at 10:10?AM SIBYLLE ST?CKLI via R-help <
r-help at r-project.org> wrote:
> Dear community
>
>
>
> Using
2023 May 16
0
Newbie: Drawing fitted lines on subset of data
Yep, that did it. I didn't know that you could have pipelines within
pipelines.
Thanks, again, for all your help.
-Kevin
On 5/16/23 11:44, Rui Barradas wrote:
> ?s 15:29 de 16/05/2023, Kevin Zembower via R-help escreveu:
>> Hello,
>>
>> I's still working with my tsibble of weight data for the last 20 years.
>> In addition to drawing an overall trend line,
2007 Jun 14
1
back-transform predictors for x-axis in plot -- mgcv package
My question is related to plot( ) in the mgcv package. Before modelling
the data, a few predictors were transformed to normalize them.
Therefore, the x-axes in the plots show transformed predictor values.
How do I back-transform the predictors so that the plots are easier to
interpret?
Thanks in advance,
Suzan
--
Suzan Pool
Oregon State University
Cooperative Institute for Marine
2011 Jan 25
1
ggplot - controlling point size
Can anyone illuminate the following for me?
How can I get rid of the blue line in the key in the second plot?
## Create a simple data frame
df=data.frame(x=1:1000, y=2*1:1000+rnorm(1000,sd=1000),
type=sample(letters[1:2],1000, replace=TRUE))
## Very nice! Almost what I want
qplot(x, y, data=df, colour=factor(type)) + geom_smooth()
## Make a nicer plot, with smaller points
## but why
2013 Dec 17
1
ggplot2: stat_smooth for family=binomial with cbind(Y, N) formula
With ggplot2, I can plot the glm stat_smooth for binomial data when the
response is binary or
a two-level factor as follows:
data("Donner", package="vcdExtra")
ggplot(Donner, aes(age, survived)) +
geom_point(position = position_jitter(height = 0.02, width = 0)) +
stat_smooth(method = "glm", family = binomial, formula = y ~ x,
alpha = 0.2, size=2)
But how can I
2023 May 12
2
Newbie: Controlling legends in graphs
Hello, I'm trying to create a line graph with a legend, but have no
success controlling the legend. Since nothing I've tried seems to work,
I must be doing something systematically wrong. Can anyone point this
out to me?
Here's my data:
> weights
# A tibble: 1,246 ? 3
Date J K
<date> <dbl> <dbl>
1 2000-02-13 133 188
2
2023 Dec 14
0
R-help Digest, Vol 250, Issue 13
Kevin,
Maybe also look at what air quality monitoring is being done in area.
https://cran.r-project.org/web/packages/RAQSAPI/vignettes/RAQSAPIvignette.html
Depends what and how near, but might be something relevant there?
Karl
Dr Karl Ropkins
Transport Studies | Environment | University of Leeds
------------------------------
Message: 2
Date: Tue, 12 Dec 2023 07:52:59 -0800
From: Bert Gunter