Displaying 8 results from an estimated 8 matches for "genmoics".
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genetics
2019 Jun 21
4
Calculation of e^{z^2/2} for a normal deviate z
Hello,
Well, try it:
p <- .Machine$double.eps^seq(0.5, 1, by = 0.05)
z <- qnorm(p/2)
pnorm(z)
# [1] 7.450581e-09 1.228888e-09 2.026908e-10 3.343152e-11 5.514145e-12
# [6] 9.094947e-13 1.500107e-13 2.474254e-14 4.080996e-15 6.731134e-16
#[11] 1.110223e-16
p/2
# [1] 7.450581e-09 1.228888e-09 2.026908e-10 3.343152e-11 5.514145e-12
# [6] 9.094947e-13 1.500107e-13 2.474254e-14 4.080996e-15
2019 Jun 21
4
Calculation of e^{z^2/2} for a normal deviate z
...values:
> qnorm(-5000, log=TRUE)
[1] -99.94475
-pd
> On 21 Jun 2019, at 17:11 , jing hua zhao <jinghuazhao at hotmail.com> wrote:
>
> Dear Rui,
>
> Thanks for your quick reply -- this allows me to see the bottom of this. I was hoping we could have a handle of those p in genmoics such as 1e-300 or smaller.
>
> Best wishes,
>
>
> Jing Hua
>
> ________________________________
> From: Rui Barradas <ruipbarradas at sapo.pt>
> Sent: 21 June 2019 15:03
> To: jing hua zhao; r-devel at r-project.org
> Subject: Re: [Rd] Calculation of e^{z^...
2019 Jun 21
0
Calculation of e^{z^2/2} for a normal deviate z
Dear Rui,
Thanks for your quick reply -- this allows me to see the bottom of this. I was hoping we could have a handle of those p in genmoics such as 1e-300 or smaller.
Best wishes,
Jing Hua
________________________________
From: Rui Barradas <ruipbarradas at sapo.pt>
Sent: 21 June 2019 15:03
To: jing hua zhao; r-devel at r-project.org
Subject: Re: [Rd] Calculation of e^{z^2/2} for a normal deviate z
Hello,
Well, try it:
p &...
2019 Jun 23
2
Calculation of e^{z^2/2} for a normal deviate z
...gt; [1] -99.94475
>
> -pd
>
>> On 21 Jun 2019, at 17:11 , jing hua zhao <jinghuazhao at hotmail.com> wrote:
>>
>> Dear Rui,
>>
>> Thanks for your quick reply -- this allows me to see the bottom of this. I was hoping we could have a handle of those p in genmoics such as 1e-300 or smaller.
>>
>> Best wishes,
>>
>>
>> Jing Hua
>>
>> ________________________________
>> From: Rui Barradas <ruipbarradas at sapo.pt>
>> Sent: 21 June 2019 15:03
>> To: jing hua zhao; r-devel at r-project.org
>>...
2019 Jun 21
0
Calculation of e^{z^2/2} for a normal deviate z
...r values:
> qnorm(-5000, log=TRUE)
[1] -99.94475
-pd
> On 21 Jun 2019, at 17:11 , jing hua zhao <jinghuazhao at hotmail.com> wrote:
>
> Dear Rui,
>
> Thanks for your quick reply -- this allows me to see the bottom of this. I was hoping we could have a handle of those p in genmoics such as 1e-300 or smaller.
>
> Best wishes,
>
>
> Jing Hua
>
> ________________________________
> From: Rui Barradas <ruipbarradas at sapo.pt>
> Sent: 21 June 2019 15:03
> To: jing hua zhao; r-devel at r-project.org
> Subject: Re: [Rd] Calculation of e^{z^2/2}...
2019 Jun 23
0
Calculation of e^{z^2/2} for a normal deviate z
...gt;
> >> On 21 Jun 2019, at 17:11 , jing hua zhao <jinghuazhao at hotmail.com>
> wrote:
> >>
> >> Dear Rui,
> >>
> >> Thanks for your quick reply -- this allows me to see the bottom of
> this. I was hoping we could have a handle of those p in genmoics such as
> 1e-300 or smaller.
> >>
> >> Best wishes,
> >>
> >>
> >> Jing Hua
> >>
> >> ________________________________
> >> From: Rui Barradas <ruipbarradas at sapo.pt>
> >> Sent: 21 June 2019 15:03
> >&...
2019 Jun 24
2
Calculation of e^{z^2/2} for a normal deviate z
...g hua zhao <jinghuazhao at hotmail.com>
>> wrote:
>> >>
>> >> Dear Rui,
>> >>
>> >> Thanks for your quick reply -- this allows me to see the bottom of
>> this. I was hoping we could have a handle of those p in genmoics such as
>> 1e-300 or smaller.
>> >>
>> >> Best wishes,
>> >>
>> >>
>> >> Jing Hua
>> >>
>> >> ________________________________
>> >> From: Rui Barradas <ruipb...
2019 Jun 24
0
Calculation of e^{z^2/2} for a normal deviate z
...g hua zhao <jinghuazhao at hotmail.com>
>> wrote:
>> >>
>> >> Dear Rui,
>> >>
>> >> Thanks for your quick reply -- this allows me to see the bottom of
>> this. I was hoping we could have a handle of those p in genmoics such as
>> 1e-300 or smaller.
>> >>
>> >> Best wishes,
>> >>
>> >>
>> >> Jing Hua
>> >>
>> >> ________________________________
>> >> From: Rui Barradas <ruipb...