Displaying 1 result from an estimated 1 matches for "gbms".
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bms
2010 Aug 03
2
subset based on column names and then subset based on the inverse (grep?, or...)
...;ftbr", "ftbr", "ftbr", "ftbr",
"ftbr", "ftbr", "ftbr"), creek = c("jcms", "wpms", "lrf1", "bmcm",
"fcms", "lrtb", "hcms", "jpms", "fbms", "gbms"), date = c("06/20/2010",
"06/20/2010", "06/18/2010", "06/18/2010", "06/21/2010", "06/22/2010",
"06/22/2010", "06/21/2010", "06/19/2010", "06/19/2010"), elevation_m = c(101,
81, 59, 75, 73, 55,...