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Usually the y-axis is shown on the left-hand-side of a graph, is it possible to artifically creat one more y-axis on the right-hand-side in R? What is the main reference? Thank you in advance. [[alternative HTML version deleted]]

...39;s really short, under 100 lines with comments. Of course, this is just a really rough solution that I hacked together to experiment with interfacing with broadcasting clients and audio players. Anyway, here it is: http://pastie.caboo.se/59073 Thanks, -carl -- EPA Rating: 3000 Lines of Code / Gallon (of coffee)

I have the following data ID x y time 1 10 20 0 1 10 30 1 1 10 40 2 2 12 23 0 2 12 25 1 2 12 28 2 2 12 38 3 3 5 10 0 3 5 15 2 ..... x is time invariant, ID is the subject id number, y is changing over time. I want to find out the difference between the first and last observed y value for each subject and get a table like ID x y 1 10 20 2 12 15 3 5 5 ...... Is there any easy way to generate

I have the complete data like id time censor 1 10 0 1 20 0 1 30 0 2 10 0 2 20 1 2 30 0 2 40 0 3 10 0 3 20 0 3 30 1 .... for id 1, i want to select the last row since all censor indicator is 0; for id 2, i want to select the row where censor ==1; for id 3, i also want to select the row where censor==1. So if there is a 1 for censor, then I want to select such a row, otherwise I want to select the

Hi, I'm a second year Master's student in Applied Statistics. I am doing a project using average weekly U.S. regular gasoline prices (in cents, per gallon) from an Excel file (from the years 1990- May 2010). I want to find the probability that the average weekly U.S. regular gasoline prices (in the long term) goes over 400 cents a gallon (or $4.00 a gallon). I am using the extRemes program (in R), and I've already uploaded my data, and fo...

find the position of the first value who equals certain number in a vector: Say a=c(0,0,0,0,0.2, 0.2, 0.4,0.4,0.5) i wish to return the index value in a for which the value in the vector is equal to 0.4 for the first time. in this case, it is 7. [[alternative HTML version deleted]]

Dear r-helpers, I have a very simple question. Suppose my data is like id=c(rep(1,2),rep(2,2)) b=c(2,3,4,5) m=cbind(id,b) > m id b [1,] 1 2 [2,] 1 3 [3,] 2 4 [4,] 2 5 I wish to select the first observation for each id. That is, I want to quickly select two rows: id b 1 2 2 4 only. how should i do this? [[alternative HTML version deleted]]

say, I am plotting x=seq(0,5,len=100) y=-(x-5)^2 plot(x,y) how can I put some color or verticle lines below the plotted curve? [[alternative HTML version deleted]]

...is in the legend. I tried using the points command but this does not work. Is there another command in R that would allow me to use different symbols and colors for the points? Thank you kindly. data(mtcars) plot(mtcars$wt,mtcars$mpg,xlab= "Weight(lbs/1000)", ylab="Miles per Gallon") mtcars$wt.cyl<-mtcars$wt[mtcars$cyl] mtcars$mpg.cyl<-mtcars$mpg[mtcars$cyl] points(mtcars$wt.cyl, mtcars$mpg.cyl, pch = 17, col = "red") title("Motor Trend Data") text(2,10,"LTR",cex=1.2,adj=0,col=3) legend(4,30,c("4 cylinder","6 cylin...

...om simulation .Detailed info the column names and attributes for clarity 1. id: alphanumeric factor/character 2. datetime.of.trip.start: POSIXct yyyy-mm-dd hh:mm:ss 3. datetime.of.trip.end: POSIXct yyyy-mm-dd hh:mm:ss 4. trip.distance: numeric, miles 5. trip.fuel.consumed: numeric, gallons Close to 2500 trucks , simulated for a year with varying trip behavior. This is what I am trying to accomplish 1. First, I want to create 10 minute intervals from a chosen start date and end date from simulation, ex: 2011-03-30 00:00:00 to 2012-04-01 00:00:00 { approximately 8760 hours * six, 10...

i have a data set with repeated measures on same people, structure like below: id x1 x2 ... 001 10 20 ... 001 8 45 ... 001 4 2 ... 002 .... 002 ... 002 .... 002 .... 003 .... ....... what is the easist way to show how many observations for each subject id? [[alternative HTML version deleted]]

i have converted my data into date format like below: > day=as.Date(originaldate,"%m/%d/%Y") > day[1:5] [1] "2008-04-12" "2011-07-02" "2011-09-02" "2008-04-12" "2008-04-12" I wish to select only those observations from 2007 to 2009, how can I select from this list? [[alternative HTML version deleted]]

I have two vectors for values collected from a group of subjects, say a=c(100,200,150,120,140,180) b=c(200,300,420,130) I also have two vectors which indicate the corresponding subjects for a and b, say for a, the subjects are suba=c(1,2,3,4,5,6) for b, the subjects are subb=c(1,3,5,6) Then, I want to find out the paired values from a and b, such as (100, 200) (from subject 1), (150,300)

Currently, I am doing it this way. x <- mtcars$mpg h<-hist(x, breaks=10, col="red", xlab="Miles Per Gallon", main="Histogram with Normal Curve") xfit<-seq(min(x),max(x),length=40) yfit<-dnorm(xfit,mean=mean(x),sd=sd(x)) yfit <- yfit*diff(h$mids[1:2])*length(x) lines(xfit, yfit, col="blue", lwd=2) But since, ggplot2 has more appealing graphics, I wonder how can it b...

...ng a strange error in protocol.rb when I run a script that uses mechanize in a multi threaded fashion, but not with a single thread. I''m trying to write a spider that does multiple gets in parallel, but it keeps puking when I thread it. Thanks, -carl -- EPA Rating: 3000 Lines of Code / Gallon (of coffee)

...;ve got the same message with R 2.14.1. In the description file, I wrote in the "Depends" item R (>=2.10.0) In the namespace file : import("stats","graphics") export(granstat,granplot) Can you help me? Regis ________________________________________ R?gis GALLON Doctorant MNHN Station Marine de Dinard Centre de recherche et d'enseignement sur les ?cosyst?mes c?tiers 38 rue du Port Blanc, 35800 Dinard. ---------- PhD student French national museum of natural history Dinard Marine Station Center for research and teaching on coastal ecosystem 38 rue du...

I have the following list of observations of calendar time: [1] 03-Nov-1997 09-Oct-1991 27-Aug-1992 01-Jul-1994 19-Jan-1990 12-Nov-1993 [7] 08-Oct-1993 10-Nov-1982 08-Dec-1986 23-Dec-1987 02-Aug-1995 20-Oct-1998 [13] 29-Apr-1991 16-Mar-1994 20-May-1991 28-Dec-1987 14-Jul-1999 27-Nov-1998 [19] 09-Sep-1999 26-Aug-1999 20-Jun-1997 05-May-1995 26-Mar-1998 15-Aug-1994 [25] 24-Jun-1996 02-Oct-1996

5-foot pencils? Gallon-sized coffee mugs? 10-pound chocolate bars? Yes! Yes! Yes! And yes to dozens of other common objects in uncommonly BIG sizes! That's what GreatBigStuff.com is all about! Thank you for your interest in http://www.GreatBigStuff.com. This message is to verify that you wish to have your email...

I know how to compute the ROC curve and the empirical AUC from the logistic regression after fitting the model. But here is my question, how can I compute the standard error for the AUC estimator resulting form logistic regression? The variance should be more complicated than AUC based on known test results. Does anybody know a reference on this problem? [[alternative HTML version deleted]]

Also, it is possible to change "ylim" also? 2012/7/1 li li <hannah.hlx@gmail.com> > Dear all, > I have a few questions regarding the boxplot output from the > "geom_boxplot" function. > Attached is the output I get. Below are my questions: > > 1. How can I define the xlab and ylab myself? > Also I would like to remove