Displaying 2 results from an estimated 2 matches for "g2659310".
2006 Nov 13
1
handling time units--hours, minutes, days--from file times
...eric(intervalue))
ifelse(unitless.interval>=5, hour.interval<-(unitless.interval/60),
hour.interval<-unitless.interval)
hours<-0
for (i in 1:(fileno-1)){hours<-c(hours,(i*hour.interval))}
myfileinfo <-
size isdir mode
mtime ctime
G2659310 2006-307-21-09-57.txt 10220 FALSE 666 2006-11-03 21:04:00
2006-11-13 10:56:39
G2659310 2006-307-21-45-55.txt 10230 FALSE 666 2006-11-03 21:40:00
2006-11-13 10:56:39
G2659310 2006-307-22-23-00.txt 10236 FALSE 666 2006-11-03 22:17:00
2006-11-13 10:56:39
G2659310 2006-307-23-00-33.txt 10236 FALSE...
2006 Nov 17
0
difftime for handling time units--hours, minutes, days--from file times
.../13/06, Tim Calkins <tcalkins@gmail.com> wrote:
> hardly the most efficient way to go, but consider using a substring
> function to extract the time bits from your data, then reading them as POSIX
> dates and using difftime.
>
> for example,
>
> > mytime <- c("G2659310 2006-310-10-55-32.txt 10134 FALSE 666 2006-11-06
> 10:49:00 2006-11-13 10:56:41",
> "G2659310 2006-310-11-31-43.txt 10136 FALSE 666 2006-11-06 11:25:00
> 2006-11-13 10:56:41",
> "G2659310 2006-310-12-08-04.txt 10140 FALSE 666 2006-11-06 12:02:00
> 2006-11-13 10...