search for: g1enn

Hi All, would appreciate an answer on this if you have a moment; Is there a function (before I try and write it !) that allows the input of a covariance or correlation matrix to calculate PCA, rather than the actual data as in princomp() Regards Glenn [[alternative HTML version deleted]]

For a list say; list1<-{1,2,3,4,5,2,1} How do I remove the duplicates please? My real list is 20,000 obs long of dates with many duplicates Regards Glenn [[alternative HTML version deleted]]

Hi All, I have a small dataframe [dates, values) I am plotting with plot(df,type=²l²) And the date date covers a year. The graph only have marks at Œ2008¹ and Œ2009¹. How do I get the months labeled at the bottom please Thanks as always Glenn [[alternative HTML version deleted]]

Very simple questions if anyone can help: (1) what is the value in saving workspaces, which is offered at every close? I thought it might save the set up of the GUI but I cant work out what it does ­ I run a script that loads the packages I need at the start of every session. (2) mathematica has a term (%) that when typed means the last returned value, so > % + 1 say would return the last

Hi All, some help on this would be appreciated; Understood combinations(7,4) returns all the possible 4 part combinations out of 7. Is is possible to substitute the ³7² for a list of stuff you would like to see the mix of; c(³a²,...,²g²) say ? Thanks Glenn [[alternative HTML version deleted]]

Hi all - has anyone ot and experienced problems with R+. Have downloaded the trail and it will not work -does it need vista (like it says on the box!) Thanks glenn [[alternative HTML version deleted]]

Newbie question sorry (have tried the help pages I promise) I have a dataframe (date,stockprice) say and looking how I might get the return of: dataframe (difference in days, change in stock price) using sapply - I require a very simple function and don't really want to go down the zoo and quant mod route Regards glenn [[alternative HTML version deleted]]

Very quick newbie question sorry; How do I standardize a list of data please (other than do the calculation of course). Is there a quick way please ? glenn [[alternative HTML version deleted]]

Dear All; Is it possible to create a list of lists (I am sure it is) along these lines; I have a dataframe data02 that holds a lot of information, and the first column is ³date² I have a list of dates in; data03<-c(date1,.....,daten) And would like to create a list; data04 <- subset(data02, date == data03[1,]) Ie. data04 holds the data from data02 that matches a date in data03 How do

Help with this much appreciated I have a large dataframe that I would like to subset where the constraint Test1 <- subset(df, date == uniques[[1]]), where uniques is a list of dates that must be matched to create Test1. I would like to perform an operation on Test1 that results in a single column of data. So far so good. How do loop through all values in the uniques list (say

....uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ------------------------------ Message: 38 Date: Mon, 22 Dec 2008 23:07:29 +0000 From: glenn roberts <g1enn.roberts at btinternet.com> Subject: [R] Integrate function To: "r-help at R-project.org" <r-help at R-project.org> Message-ID: <C575CE31.4DB%g1enn.roberts at btinternet.com> Content-Type: text/plain Quick One if any one can help please. On use of integration function inte...

Hi All, I've been having a little trouble with creating a loop that will run a a series of t.tests for inspection, Below is the code i've tried, and some checks i've looked at. I've used the get(paste()) idea as i was told previously that the use of the eval should try and be avoided. I've run a single syntax to check that my systax is correct and works without any problems

Another Newbie Question sorry: I am trying to apply a function a dataframe and could use some help: Assuming, dim(df) = (10,2) say, I would like to apply a function that looks at each row in turn and returns a list (dim =(10,1)) using the columns as inputs to the function, but with no INDEX stuff that the by() function refers to. For a simple function x+y I know in Mathematica it would be

I have got a general problem when applying a function to a dataframe using the function; Apply(df,1,myfunct) Where myfunct has an IF statement in it along the lines of; If (z == 0) X = 1 If (z ==0) Z = 1 I.e. Two If statements Is there something I am missing or have a just formed the if statements wrong ­ just checking there is not some trick you have to use when using apply with functions

Would appreciate some help on this problem please: Using nls to solve for 5 parameters to a set of data, and for particular mixes of the parameters the function can yield NaN and infinity returns. Is is making nls fall over ­ I have tried starting values, lower and upper bounds to no avail. New to R and not sure how to put constraints into this function, the parameters have constraining

If I have 2 data frames; df1: dim(df1) = (1,10) df2: dim(df2) = (2000,10) Both with column header names, how do I multiply them together please. I.e create a dateframe dim() = (2000,1) Many Thanks in advance Glenn [[alternative HTML version deleted]]

Dear All, A very quick newbie question sorry. I am running R on Windows and would like to know if I can store a .R file in a location that it gets run on start up. Or is there some file I can alter please? Regards Glenn [[alternative HTML version deleted]]

Very quick one please team; How do I return the number of possible unique subsets in a data set (not combinations i.e. not (1,2,3,4) and (4,3,2,1)) please ? e.g. In a list of integers 1 to 12, there is 495 sets with 4 elements in regards glenn [[alternative HTML version deleted]]

Dear All, Could someone give me some pointers (just a guide as to what functions I need to look at would be fine) as to how I go about this simple problem please; The problem looks like this; Choose x1 to x4 such that you minimize the MAXIMUM ABSOLUTE value returned in the vector result of this matrix problem; [x1,x2,x3,x4].[ -0.38 -0.52 0.68 -0.29 ] [ -0.39 -0.42

Is there a general method for finding out what "something" is in R please. I have a list (bycontract) that; > is.list(bycontract3) [1] TRUE And an element of this list would be this say; > bycontract3[[1]] [1] 22 3.2 -8 -17 49 3 [7] 30 -3 -21 8 3 12 [13] 49 19 -13 -2 25 39 [19] -12 -90 -1 15 -87 30 I can not seem to see what type of object