Displaying 1 result from an estimated 1 matches for "fuzzybreaks".
2010 Mar 30
1
hist.default()$density
Dear developers,
the current implementation of hist.default() calculates 'density' (and
'intensities') as
dens <- counts/(n*h)
where h has been calculated before as
h <- diff(fuzzybreaks)
which results in 'fuzzy' values for the density, see e.g.
> tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE)
> print(tmp$density,digits=15)
[1] 0.0399999920000016 0.1000000000000000 0.0600000000000000
Since hist.default()$breaks are not the fuzzy breaks used for the
c...