search for: funtionality

Hi, I have a variable X classified in a lot of groups and I need to run the [fitdistr] funtion for each group. I tried with the [by] or the [tapply] funtions because my data is organize in two columns (variable and the groups), but neither of these command work. If somebody have a tip to help me up I really appreciate it. thanks, [[alternative HTML version deleted]]

Have any way to write a funtion into a list ? -- Nash - morrison at ibms.sinica.edu.tw

Hi, I would like to display results on the screen . Can I use the printf function in LLVM? How do I call the funtion? Could someone give me an example Thanks Jai

Hi, I have an apply statement that looks like: > check.cols <- function(v1, v2) { + return( identical(v1,v2) ); + } > x [,1] [,2] [,3] [1,] 1 3 3 [2,] 4 5 4 [3,] 2 7 6 > apply(x, c(2), check.cols, v2=c(7,8,9)) [1] FALSE FALSE FALSE Is it possible to make the function check.cols() inline to the apply statement. Some thing like this: apply(x,

I'm trying to create a bargraph of means with standard error bars using the function bargraph.CI (in the sciplot package). Like this: bargraph.CI(x.factor, response,data,xlab, ylab, par(family="serif"),font=11) However, an error message comes up when I try to use the par funtion. Does the character font/style need to be changed in a different way for this kind of plot? Or am I

Hei, I just wonder the use of family=binomial in glm function. As I learned from book (e.g. Andy Field) that logistic regression (binary logit) can use glm funtion with family = binomial. Here the y is a factor variable (e.g. value = 1 or 2). But I have also seen i many other cases, same function glm with family=binomial, but y is a variable with several column , like y= cbind(y1, y2), and

Just compile a trivial C program containing printf through llvm-gcc and you will see how to call printf from within llvm. You could even do it on the llvm web page if you don't have llvm-gcc installed. --Vikram http://www.cs.uiuc.edu/~vadve http://llvm.cs.uiuc.edu/ On Dec 11, 2004, at 1:13 AM, <vasanth2 at uiuc.edu> wrote: > Hi, > > I would like to display results on the

The gcc front-end page in llvm.cs.uiuc.edu seems to be down for the last 18 hrs. I was finding that tool very useful to get the syntactic constructs, could someone fix it ? Thanks Jai On Sat, 11 Dec 2004 11:10:00 -0600, Vikram S. Adve <vadve at cs.uiuc.edu> wrote: > Just compile a trivial C program containing printf through llvm-gcc and > you will see how to call printf from within

On Sat, 11 Dec 2004, Jai Vasanth wrote: > The gcc front-end page in llvm.cs.uiuc.edu seems to be down for the > last 18 hrs. I was finding that tool very useful to get the syntactic > constructs, could someone fix it ? Fixed, sorry. -Chris > On Sat, 11 Dec 2004 11:10:00 -0600, Vikram S. Adve <vadve at cs.uiuc.edu> wrote: >> Just compile a trivial C program containing

Hey all, I need some help with a cross validation. I'm new with R and as well with statistics. I had a group work to create a tool for remote sensing class that extracts the best bands of hyperspectral satellite images that describe vegetation. Its a regression between a linear function of using a normalized differenced index (i-j)/(i+j) while i and j are the bands (in the data these are the

What was the issue? On Sat, 2004-12-11 at 14:59, Chris Lattner wrote: > On Sat, 11 Dec 2004, Jai Vasanth wrote: > > The gcc front-end page in llvm.cs.uiuc.edu seems to be down for the > > last 18 hrs. I was finding that tool very useful to get the syntactic > > constructs, could someone fix it ? > > Fixed, sorry. > > -Chris > > > On Sat, 11 Dec 2004

Dear all, 1) I have a very large matrix of  str(keep)  num [1:153899, 1:3415] -98.6 -95.8 -96.4 -95.8 -98 ... that  I would like to reduce its size to something like str(keep)  num [1:1000, 1:3415] -98.6 -95.8 -96.4 -95.8 -98 ...  or anything similar in size as this is a matrix that needs plotting (so is ok if it is 1000 row, 995, or 1123) I think what I need here is a way of selecting

I am trying to call a funtion within another function and I clearly am misunderstanding what I should do. Below is a simple example. I know lstfun works on its own but I cannot seem to figure out how to get it to work within ukn. Basically I need to create the variable "nts". I have probably missed something simple in the Intro or FAQ. Any help would be much appreciated. EXAMPLE

Dear R-list, Could anybody tell me (or give me a tip) of how to implement the Duncan distribution in R? I've been trying to make a new and more flexible function for multiple comparison of means: Tukey, SNK and Duncan, from 'aov' objects, like TukeyHSD function. For while, it is running nice (Tukey and SNK), for simple design (completely randomized, randomized block and Latin

Jose - Before implementing SNK and Duncan's, you may want to be aware of some criticisms of these methods: >From Hsu (1996), "Newman-Keuls multiple range test is not a confident inequalities method and cannot be recommended." "Duncan's multiple range test is not a confident inequalities method and cannot be recommended either. In the words of Tukey (1991),

  Hello, my name is German, I am from Argentina, and we are working at university with R. This work is about sounds and how they affect out ears, we are using R to analice different recordings of sounds and we need to get the intensity of this recordings in dB.  In order to get the intensity of the sounds, we are using the plot function, but we can not figure out what is the menaning of the

Hello all! I've posted the question before but I am still struggling for an answer, please help if you can;-) Suppose a discrete series of data is generated by the following equation: CF=exp(-(t^2)/2) which is the characteristic function of a random variable X with standard normal distribution, how do I *numerically* solve for its probability density function? i.e., obtain a series of data

Hello, Do you have a function returns codes of given characters? Best Regards, hyunjo [[alternative HTML version deleted]]

Hello, I have a data.frame: name    col1    col2    col3    col4 AA    23    54    0.999    0.78 BB    123    5    1    0.99 AA    203    98    0.79    0.99 I want to get mean value data.frame in terms of name: name    col1    col2    col3    col4 AA    113.0000  76.0000   0.8945   0.8850 BB    123.00   5.00   1.00   0.99 I tried to use by function: >aa<-by(test[,2:5], feature, mean)

Dear R users, I am applying the augmented-Dickey-Fuller Unit Root Test (ur.df function of the urca package) to a time series of approximately 50 values. To be sure I understood what was going on with the ur.df function, I checked the critical values of the 3 test statistics (tau, phi2 and phi3 if a trend is included) or the 2 test statistics (tau and phi1 if only a drift is included) with the