Displaying 20 results from an estimated 310 matches for "fuller".
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fulle
2010 Oct 29
3
Dickey Fuller Test
...5573,5331,5355,6057,6055,6771,6669,6375,6666,6383,6118
,5927,5750,5122,5398,5817,6163,6763,6835,6678,6821,6421,6338,6265,6291
,5540,5822,6318,6268,7270,7096,6505,7039,6440,6446,6717,6320)
YY=as.timeSeries(Y)
adf.test(Y)
adf.test(YY)
======== Output ====
> adf.test(Y)
Augmented Dickey-Fuller Test
data: Y
Dickey-Fuller = -6.1661, Lag order = 5, p-value = 0.01
alternative hypothesis: stationary
Warning message:
In adf.test(Y) : p-value smaller than printed p-value
> adf.test(YY)
Augmented Dickey-Fuller Test
data: YY
Dickey-Fuller = 12.4944, Lag order = 5, p-value = 0....
2013 Jun 23
1
Scaling Statistical
Short question: Is it possible to use statistical tests, like the Augmented
Dickey-Fuller test, in functions with for-loops? If not, are there any
alternative ways to scale measures?
Detailed explanation: I am working with time-series, and I want to flag
curves that are not stationary and which display pulses, trends, or level
shifts.
>df
DATE ID VALUE2012-03-06 1 5....
2007 Dec 08
2
time series tests
Hi all,
Can anyone clear my doubts about what conclusions to take with the following what puts of some time series tests:
> adf.test(melbmax)
Augmented Dickey-Fuller Test
data: melbmax
Dickey-Fuller = -5.4075, Lag order = 15, p-value = 0.01
alternative hypothesis: stationary
Warning message:
p-value smaller than printed p-value in: adf.test(melbmax)
>adf.test(melbmax,k=0,alternative="stationary")
Augmented Dickey-Fuller Test
data...
2009 May 15
1
Dickey-Fuller Tests with no constant and no trend
R has a Dickey-Fuller Test implementation (adf.test) that tests for unit
roots in an autoregressive process with a constant and linear trend. Is
there a DF implementation that doesn't use the constant or trend?
Thanks,
Jake.
--
View this message in context: http://www.nabble.com/Dickey-Fuller-Tests-with-no-cons...
2005 May 23
3
Dickey-Fuller Test
Hi All ,
Could you please tell using which library ,Dickey-Fuller Test can be run?
Thanks a lot
__________________________________________________
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2013 Apr 30
1
ADF test --time series
Hi all,
I was running the adf test in R.
CODE 1:
adf.test(data$LOSS)
Augmented Dickey-Fuller Test
data: data$LOSS
Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775
alternative hypothesis: stationary
CODE 2:
adf.test(diff(diff(data$LOSS)))
Augmented Dickey-Fuller Test
data: diff(diff(data$LOSS))
Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01
alternative hypoth...
2007 Aug 16
2
ADF test
...5.26 5.26 5.26 5.26 5.26 5.26 5.27
[145] 5.27 5.26 5.27 5.27 5.28 5.29 5.29 5.29 5.29 5.30 5.30 5.30 5.31 5.31 5.31 5.32 5.32 5.33
[163] 5.33
Now I want to conduct a test for stationarity using ADF test :
> adf.test((data[,1]), "stationary", 0)
Augmented Dickey-Fuller Test
data: (data[, 1])
Dickey-Fuller = -3.7351, Lag order = 0, p-value = 0.02394
alternative hypothesis: stationary
But surprisingly it leads towards rejestion of NULL [p-value is less than 0.05], i.e. indicates a possible stationary series. However ploting a graph of actual data set it doe...
2010 Aug 23
1
Dickey–Fuller test in R
Hi,
While doing the adf test using ur.df
?price.df2=ur.df(y=log(price),type = "drift", selectlags="AIC")
summary(price.df2)?
It gives two values for ?value of test statistic is: -1.5992?? 2.32?
one value is the t-test (or t-ratio), what is the other one?
Please help.
TIA
Aditya
2009 Mar 20
1
Dickey Fuller test of a time series (problem)
Hi all,
I tried to do a Dickey Fuller test with R using adf.test with a time series of german stock prices. I have 10 stocks from 1985 to 2009 with monthly stock prices. So if you do the math I have 289 values for each stock.
I tried to do the test for each stock alone and had the 289 values of my first stock listed in R.
When I tried...
2004 Oct 13
4
incomplete function output
...tput of the last test is
displayed. How can I ensure that the function root(var)
will run and display the output from all tests, and not
just the last one?
Thank you,
b.
root <- function(var)
{
#---Phillips-Perron
PP.test(var, lshort = TRUE)
PP.test(var, lshort = FALSE)
#---Augmented Dickey-Fuller
adf.test(var, alternative = "stationary", k =
trunc((length(var)-1)^(1/3)))
#---KPSS
kpss.test(var, null = "Level", lshort = TRUE)
kpss.test(var, null = "Trend", lshort = FALSE)
}
2009 May 08
2
Override sip.conf settings in extensions.conf? Possible?
...gs in extensions.conf
(for example: session-minse=90) without needing to create an overarching peer in sip.conf
and selecting it specifically in the dial plan?
I'm on the 1.4 stable code base and looking to implement session-timers on certain call
flows in a modular dial plan.
Thanks,
Josh Fuller josh.fuller at telus.com
The views expressed in this e-mail are mine alone and do not necessarily reflect the
views of my employer.
2013 Mar 22
4
error while extracting the p-value from adf.test
Hello all,
I tried to extract the p-value from adf.test in tseries; however, I got the error message such as
> ht=adf.test(list.var$aa)
> ht$p-value
Error in ht$p - value : non-numeric argument to binary operator
> ht
Augmented Dickey-Fuller Test
data: list.var$aa
Dickey-Fuller = -2.3147, Lag order = 4, p-value = 0.4461
alternative hypothesis: stationary
> ht$data
[1] "list.var$aa"
> ht$p-value
Error in ht$p - value : non-numeric argument to binary operator
> ht$p
NULL
I do not have problem extracting the data in...
2007 Jan 24
3
Cronbach's alpha
Dear Listers:
I used cronbach{psy} to evaluate the internal consistency and some set
of variables gave me alpha=-1.1003, while other, alpha=-0.2;
alpha=0.89; and so on. I am interested in knowing how to interpret
1. negative value
2. negative value less than -1.
I also want to re-mention my previous question about how to evaluate
the consistency of a set of variables and about the total
2014 Dec 07
4
syslinux 6.03 does not boot some kernels
...cussion of grub2 booting the kernel in a "hostile" way -- not
using the built-in kernel EFI bootloader. And thus, grub2 is able to boot
earlier kernels, while syslinux follows the rules. And is not able to.
H. Peter referenced https://www.kernel.org/doc/Documentation/efi-stub.txt
for a fuller explanation.
Great job writing up documentation, Gene. If H. Peter's explanation is
congruent with Ady's Linux pre-3.3 kernel research, would you add a link to
this fuller explanation?
i.e.,
https://www.kernel.org/doc/Documentation/efi-stub.txt
in the "Linux EFI pre-3.3" s...
2003 Feb 05
2
summary: printing to Win95 local printer
I tried to setup samba to print to a win95 box and I was using lpd from
RH7.3
After trying everything I found Cups and looked at the docs and it
prints great to the win95 Local Printer.
Thanks for your help
--
Ron Bramblett
Sys Admin
Fuller Brush Company
2009 Mar 24
0
Unit root
I am confused by obtaining different results when testing for unit root when using different packages. I have 2625 price entries for which I want to determine whether they exhibit unit root. First I test using adf.test from tseries package by running:
> adf.test(P, k=30)
Augmented Dickey-Fuller Test
data: P
Dickey-Fuller = -4.685, Lag order = 30, p-value = 0.01
alternative hypothesis: stationary
Warning message:
In adf.test(P, k = 30) : p-value smaller than printed p-value
But adf.test includes a time trend that I wan to omit, which I do not know if it is possible. Thus I have to run AD...
2006 Apr 06
1
How to implement an iterative unit root test
Hello,
How can an interative unit root test be implemented in R?
More specifically, given a time series, I wish to perform the Dickey
Fuller Test on a daily basis for say the last 100 observations. It would
be interative in the sense that this test would be repeated each day for
the last 100 observations.
Given the daily Dickey Fuller estimates of delta for the autoregressive
process
d(Y(t)) = delta * Y(t-1) + u(t)
, the significan...
2004 Jan 13
3
How can I test if a not independently and not identically distributed time series residuals' are uncorrelated ?
...#39;m analizing the Argentina stock market (merv)
I download the data from yahoo
library(tseries)
Argentina <- get.hist.quote(instrument="^MERV","1996-10-08","2003-11-03", quote="Close")
merv <- na.remove(log(Argentina))
I made the Augmented Dickey-Fuller test to analyse
if merv have unit root:
adf.test(merv,k=13)
Dickey-Fuller = -1.4645, p-value = 0.805,
merv have unit root than diff(merv,1) is stationary.
Than I made Breushch-Pagan test to test if residuals are identically distributed:
library(lmtest)
bptest(merv[2:1730]~-1+merv[1:1729],~merv[1:1...
2006 Sep 22
2
Merge problem
...le surprise when I check the dimensions of
the resultant data frame - dat0merge, the merged data frame has 8007
rows! How can this be? Where did these extra 7 rows come from?
This appears to defy logic!
Thank you in advance for your help. I've put my code below for
reference.
Tova Fuller
> dim(dat0)
[1] 8000 60
> dim(TransTable)
[1] 47296 9
> dat0merge=merge(TransTable,dat0,
by.x="Target",by.y="TargetID",all.x=F,all.y=F)
> dim(dat0merge)
[1] 8007 68
2016 Jan 15
2
JDataFrame API
...may see more overhead.
>
> If you need process separation, it may be a different story - in principle it is faster to use more native serialization than JSON since parsing is the slowest part for big datasets.
>
> Cheers,
> Simon
>
>
>> On Jan 14, 2016, at 4:52 PM, Thomas Fuller <thomas.fuller at coherentlogic.com> wrote:
>>
>> Hi Folks,
>>
>> If you need to send data from Java to R you may consider using the
>> JDataFrame API -- which is used to convert data into JSON which then
>> can be converted into a data frame in R.
>>...