Displaying 1 result from an estimated 1 matches for "fueltype".
Did you mean:
  freetype
  
2010 Sep 13
1
Transforming character vector
...'86-'09	(1996,1997]
7	DODG	2002	'86-'09	(2001,2002]
8	BMW	1997	'86-'09	(1996,1997]
11	TOYT	2006	'86-'09	(2005,2006]
12	CHEV	1997	'86-'09	(1996,1997]
13	CHEV	1992	'86-'09	(1991,1992]
14	CHEV	1996	'86-'09	(1995,1996]
I need to do the same for a fueltype where each record has a character
representing the data instead of a numeral(as in year).  No reproducible
code or data because i think this is pretty straight forward.  I could do
this using a series of loops but i think there is prob a more elegant way. 
Use of grep?  Thanks for the help
JR
--...