Displaying 2 results from an estimated 2 matches for "fsuppi".
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fsubp
2007 Jan 22
0
Fwd: Re: aov y lme
...0.969 0.4158
> > Residuals 9 69.917 7.769
> >
> > Error: Within
> > Df Sum Sq Mean Sq F value Pr(>F)
> > Residuals 24 63.333 2.639
> >
> >
> > > you should perform the calculate the test with:
> >
> > > (Fsuppi <- summary(material.aov)[[1]][1,"Mean Sq"]/
> > > summary(material.aov)[[1]][2,"Mean Sq"])
> > > pf(Fsuppi, df1 = 2, df2 = 9)
> >
> > You want the other tail.
> >
> > --
> > Brian D. Ripley, ripley at st...
2007 Jan 20
1
aov y lme
Dear R user,
I am trying to reproduce the results in Montgomery D.C (2001, chap 13,
example 13-1).
Briefly, there are three suppliers, four batches nested within suppliers
and three determinations of purity (response variable) on each batch. It is
a two stage nested design, where suppliers are fixed and batches are random.
y_ijk=mu+tau_i+beta_j(nested in tau_i)+epsilon_ijk
Here are the