Displaying 1 result from an estimated 1 matches for "fruehling".
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freeling
2012 Oct 16
1
data dividing
hey
I'd like to divide my data into four seasons. for this I made a function:
Jahreszeit <- function(x) {
if (x<=02 || x==12) {return("Winter")
}else{
if (x>=03 && x<=05) {return("Fruehling")
}else{
if (x>=06 && x<=08) {return("Sommer")
}else{
if (x>=09 && x<=11) {return("Herbst")
}}}}}
Now, I have some trouble to apply this function.
I tried lapply(), sapply() and tapply() but everytime i get for every month
just "Winter&quo...