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#Mdarts is a matrix 2343x788 #frequencia is a vector 2343x1 # 9 in Mdarts[fri,frj] stands for my missing values which i want to replace by the value in the vector frequencia Mdarts<-t(matrix(scan("C:/GWS/CNB/dartg.txt"),ncol=nindT,nrow=nm, byrow=T)) frequencia <- matrix(scan("C:/GWS/CNB/freq.txt"),ncol=1) for (fri in 1:nindT){ for (frj in 1:nm){ Mdart...

hello, i'm pete ,how can i order rows of matrix by max to min value? I have a matrix of membership degrees, with 82 (i) rows and K coloumns, K are clusters. I need first and second largest elements of the i-th row. for example 1 0.66 0.04 0.01 0.30 2 0.02 0.89 0.09 0.00 3 0.06 0.92 0.01 0.01 4 0.07 0.71 0.21 0.01 5 0.10 0.85 0.04 0.01 6 0.91 0.04 0.02 0.02 7 0.00 0.01 0.98 0.00 8 0.02

...405507 21 22 4 5 0.05574547 22 23 6 1 -0.06750403 23 > P= P[order(P$V4),] P=P[,3] This is trasformed vector ris$silinfo =P. I can't to use this vector object in the classe.memb. K=2 K.max=6 while (K<=K.max) { ris=fanny(frj,K,memb.exp=m,metric="SqEuclidean",stand=TRUE,maxit=1000,tol=1e-6) ris$centroid=matrix(0,nrow=K,ncol=J) for (k in 1:K) { ris$centroid[k,]=(t(ris$membership[,k]^m)%*%as.matrix(frj))/sum(ris$membership[,k]^m) } rownames(ris$centroid)=1:K colnames(ris$centroid)=colnames(frj)...

...lenge [2008/04/22 16:12:30, 5] auth/auth.c:get_ntlm_challenge(137) auth_context challenge created by random [2008/04/22 16:12:30, 5] auth/auth.c:get_ntlm_challenge(138) challenge is: [2008/04/22 16:12:30, 5] lib/util.c:dump_data(2264) [000] 2A 9B A6 66 72 4A 89 8D *..frJ.. [2008/04/22 16:12:30, 5] rpc_parse/parse_prs.c:prs_debug(84) 000000 smb_io_rpc_hdr_auth [2008/04/22 16:12:30, 5] rpc_parse/parse_prs.c:prs_uint8(616) 0000 auth_type : 0a [2008/04/22 16:12:30, 5] rpc_parse/parse_prs.c:prs_uint8(616) 0001 auth_level : 06 [2008/04/22 16:12:30, 5]...

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