search for: frequence

Can someone enlighten me on why the following doesn't work? setwd('C:/Temp/R') d <- rep(1:53,2) (s <- ts(d, frequency=53, start=c(2000,10))) n <- length(s) k <- n%/%3 for(i in (n-k):n) { st <- c(start(s)[1] + (start(s)[2] + i)%/%frequency(s), (start(s)[2] + i) %% frequency(s)) ed <- c(start(s)[1] +

Hi, I'm in dire need of a fast fourier transformation for me stupid biologist, i.e. I have a heartbeat signal and would like to decompose it into pure sin waves, getting three vectors, one containing the frequencies of the sin waves, one the magnitudes and one the phases (that's what I get from my data acquisition software's FFT function). I'd be very much obliged, if someone

I know how to do this when creating the time series variable in one expression, e.g. valuesTS1<-ts(values,start=2000); # Frequency naturally defaults to 1 How can I specify the frequency of a time series? > values=c(12,34,65,12); > values<-ts(values); > frequency(values); [1] 1 > start(values) [1] 1 1 > frequency(values)<-12; Error in frequency(values) <- 12 : could

> Why are you using a stereo file > containing the same sweep in both channels > and then downmixing to mono? When I first tried encoding at a higher bitrate, I needed to test the different behavior of the "mid" (l+r) and "side" (l-r) channels. That's why I made the first sweep identical on both the left and the right channel (i.e. "side" is silent)

Dea'R' helpers I have following data - prob = c(0.1, 0.2, 0.3, 0.4, 0.5) frequency = c(100, 75, 45, 30, 25) no_trials = c(10, 8, 6, 4, 2) freq1 = rbinom(frequency[1], no_trials[1], prob[1]) freq2 = rbinom(frequency[2], no_trials[2], prob[2]) freq3 = rbinom(frequency[3], no_trials[3], prob[3]) freq4 = rbinom(frequency[4], no_trials[4], prob[4]) freq5 = rbinom(frequency[5],

For the command 'spectrum' I read: The spectrum here is defined with scaling 1/frequency(x), following S-PLUS. This makes the spectral density a density over the range (-frequency(x)/2, +frequency(x)/2], whereas a more common scaling is 2? and range (-0.5, 0.5] (e.g., Bloomfield) or 1 and range (-?, ?]. Forgive my ignorance but I am having a hard time interpreting this. Does this mean

Hi, I have designed the following function to extract count frequencies from an array of integers. For example... # Tipical array x <- cbind(1,1,1,1,1,2,2,2,2,3,3,3,3,4,5,6,7,22) # Define the frequency function frequency <- function(x){ max <- max(x) j <- c() for(i in 1:max){ j[i] <- length(x[x==i]) } return(j) } fre <- frequency(x) plot(fre) How

Always reply to the list. I am not a free, private consultant! "For example, if I have the values : 1 , 2 , 3 in each column, applying Tabulate () would calculate the frequency of 1 and 2 without 3" Huh?? > x <- sample(1:3,10,TRUE) > x [1] 1 3 1 1 1 3 2 3 2 1 > tabulate(x) [1] 5 2 3 Cheers, Bert Bert Gunter "The trouble with having an open mind is that people

Hi, This has been a problem since the xen-acpi-processor code was added to the kernel source. I wasn''t sure if the problem I was seeing was related to the old version (4.1.2) of Xen that I was using but now I''m on 4.2.0 and it still exists I thought I would check if I have a misconfiguration or if I have discovered a problem. My system is a dual AMD Opteron(tm) Processor

Hi folks, I am trying to figure out how run a repeated measures ANOVA on the following data set. subject trial frequency dplvl 1 FSI052A A 1 NA 2 FSI052B B 1 NA 3 FSI053A A 1 NA 4 FSI055A A 1 NA 5 FSI055B B 1 NA 6 FSI057A A 1 NA 7 FSI057B B 1 NA 8 FSI058A A 1 NA 9

Thank you for your effort Bert.., I knew what is the problem now, the values (1,2,3) were only an example. The values I have are 0 , 1, 2 . Tabulate () function seem to ignore calculating the frequency of 0 values and this is my exact problem as the frequency of 0 values should also be calculated for the maf to be calculated correctly. ________________________________ From: Bert Gunter

Dear R users, I would like to great a frequency table from raw data and then access the classes/bins and their respective frequencies separately. Here the code to create the frequency tables: x1 <- c(1,5,1,1,2,2,3,4,5,3,2,3,6,4,3,8) t1 <- table(x1) print(t1[1]) Its easy to plot this, but how do I actually access the frequencies alone and the bins alone? Basically I am looking to get:

>From my book on corpus linguistics with R: # (10) Imagine you have two vectors a and b such that a<-c("d", "d", "j", "f", "e", "g", "f", "f", "i", "g") b<-c("a", "g", "d", "f", "g", "a", "f", "a",

|> x <- sample(0:2, 10, replace = TRUE) |> x [1] 1 0 2 1 0 2 2 0 2 1 |> tabulate(x) [1] 3 4 |> table(x) x 0 1 2 3 3 4 B. > On Nov 10, 2017, at 4:32 AM, Allaisone 1 <allaisone1 at hotmail.com> wrote: > > > > Thank you for your effort Bert.., > > > I knew what is the problem now, the values (1,2,3) were only an example. The values I have are

Hello Dimitris, I was goggling for some help on Sensitivity vs 1-specificity and saw your link. I hope you can be of help to me in one of the issue that I am facing in generating combo chart(bar chart and plot). I am a novice and have some difficulty in getting this logic correct. I am give a dataset (I am attaching a sample dataset). I am using a barplot() and passing values for

I've been trying to get rid of the loop scale limiting problem during BFI. Initially, this was saturating frequencies to the max side of the scale, so a double nested loop would get max frequencies in all the blocks (e.g., llvm/test/CodeGen/X86/lsr-i386.ll). This made the inner loop no hotter than the outer loop, so block placement would not bother aligning them. In convertFloatingToInteger()

In PR 22718, we are looking at issues with long running applications producing non-representative frequencies. For example, in these two loops: int g = 0; __attribute__((noinline)) void bar() { g++; } extern int printf(const char*, ...); int main() { int i, j, k; for (i = 0; i < 1000000; i++) bar(); printf ("g = %d\n", g); g = 0; for (i = 0; i < 500000; i++)

Hi: I have been trying to figure out a simple way to plot an histogram whose frequencies are modified by a factor (associated with each value). Actually what I did was plotting each value with its modified frequency(using plot($values, $frequency, type="h")), but it doesnt take into account the probability distribution(which is necessary). It will be very helpful from you any

Hello all, I'm new in R, and I have a data-frame like this (dput information below): Specie Fooditem Occurrence Volume 1 Schizodon vegetal 1 0.05 2 Schizodon sediment 1 0.60 3 Schizodon vegetal 1 0.15 4 Schizodon alga 1 0.05 5 Schizodon sediment 1 0.90 6 Schizodon

Hi, To clarify the default behavior that Boris is referencing below, note the definition of the 'bin' argument to the tabulate() function: bin: a numeric vector ***(of positive integers)***, or a factor. Long vectors are supported. I added the asterisks for emphasis. This is also noted in the examples used for the function in ?tabulate at the bottom of the help page. The second