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Buenos días, estoy haciendo unos mapas con ggplot, con 29 categorías, por lo que tengo que utilizar library(RColorBrewer) para disponer de suficientes colores. El problema es que al hacerlo acorde a dos variables distintas (color=var1 y color=var2), cuyas 29 categorías son obviamente las mismas, les da distintos colores y no puedo comparar los mapas. Muchas gracias, Manuel

...e approached this problem before? What replication options work well with the current stable build of samba? Is there any way to replicate when a file is locked, so the user will get the warning that the file is locked? Any feedback would be helpful, even if it is a link. Thanks in advance, Steve Francia

Hi, Does anyone know if the D'agostino test is available with R ? Alex

Dear R-list readers: Royston described the effect of sample size on the p-value obtained from the Shapiro-Francia test (Estimating departure from normality. Stat Med 1991;10:1283-93). He developed two indices from the Shapiro-Francia test (i) V' - an index of departure from normality and (ii) v' - a plot of the cumulative squared residuals. He mentioned the availability (in 1991) of a Mini...

...2 36 CR 2 2 37 B?jar 4 4 38 B?jar 8 8 39 B?jar 6 6 40 Gata 2 3 41 Gata 2 3 42 Sta Teresa 4 4 43 Sta Teresa 5 5 44 Sta Teresa 2 2 45 Sta Teresa 2 2 46 Francia 3 2 47 Francia 2 2 48 Navamu?o 21 21 49 Navamu?o 8 8 50 Ledesma 11 3 51 Ledesma 12 3 52 Ledesma 15 2 53 Ledesma 21 2 54 Ledesma 6 2 55 Monleras 2 2 56 Monleras 2...

Hi all, apologies for seeking advice on a general stats question. I ve run normality tests using 8 different methods: - Lilliefors - Shapiro-Wilk - Robust Jarque Bera - Jarque Bera - Anderson-Darling - Pearson chi-square - Cramer-von Mises - Shapiro-Francia All show that the null hypothesis that the data come from a normal distro cannot be rejected. Great. However, I don't think it looks nice to report the values of 8 different tests on a report. One note is that my sample size is really tiny (less than 20 independent cases). Without wanting to s...

...16 > shapiro.test(ln.Mn.Total..ug/kg) Error in inherits(x, "factor") : object "ln.Mn.Total..ug" not found > shapiro.test(ln.Mn.Total..ug.kg) Shapiro-Wilk normality test data: ln.Mn.Total..ug.kg W = 0.943, p-value = 1.301e-06 > sf.test(Mn.Total..ug.kg) Shapiro-Francia normality test data: Mn.Total..ug.kg W = 0.5173, p-value < 2.2e-16 > sf.test(ln.Mn.Total..ug.kg) Shapiro-Francia normality test data: ln.Mn.Total..ug.kg W = 0.9403, p-value = 3.461e-06 > cvm.test(Mn.Total..ug.kg) Cramer-von Mises normality test data: Mn.Total..ug.kg W = 4.024...

...16 > shapiro.test(ln.Mn.Total..ug/kg) Error in inherits(x, "factor") : object "ln.Mn.Total..ug" not found > shapiro.test(ln.Mn.Total..ug.kg) Shapiro-Wilk normality test data: ln.Mn.Total..ug.kg W = 0.943, p-value = 1.301e-06 > sf.test(Mn.Total..ug.kg) Shapiro-Francia normality test data: Mn.Total..ug.kg W = 0.5173, p-value < 2.2e-16 > sf.test(ln.Mn.Total..ug.kg) Shapiro-Francia normality test data: ln.Mn.Total..ug.kg W = 0.9403, p-value = 3.461e-06 > cvm.test(Mn.Total..ug.kg) Cramer-von Mises normality test data: Mn.Total..ug.kg W = 4.024...

I have a problem related with the HABTM relationships with checkboxes. I''ve got a profile and a service model, both related with has_and_belongs_to_many. The problem is that i can insert new data in the profiles_services table, however, i cant delete already existing data. What could be the problem? --~--~---------~--~----~------------~-------~--~----~ You received this message

...efors > > > > > - Shapiro-Wilk > > > > > - Robust Jarque Bera > > > > > - Jarque Bera > > > > > - Anderson-Darling > > > > > - Pearson chi-square > > > > > - Cramer-von Mises > > > > > - Shapiro-Francia > > > > > > > > > > All show that the null hypothesis that the data come from a normal > > > > > > > distro cannot be rejected. Great. However, I don't think > > > it looks nice > > > > > to report the values of 8 differ...

Hello all, Would somebody be kind enough to show me how to do a KS test in R for a lognormal distribution with ESTIMATED parameters. The R function ks.test()says "the parameters specified must be prespecified and not estimated from the data" Is there a way to correct this when one uses estimated data? Regards, Kwabena. -------------------------------------------- Kwabena Adusei-Poku

Hola: Tengo los datos diarios del número de casos de coronavirus por comunidades autónomas y quiero calcular el número diario de nuevos casos y la tasa diaria de variación del número de casos y no se como hacerlo en R. *fecha* *comunidad* *poblacion* *casos_totales* 04/03/2020 Andalucía 8414240 13 05/03/2020 Andalucía 8414240 12 06/03/2020 Andalucía 8414240 21 04/03/2020 Aragón

If I have data that I feed into shapio.test and jarque.bera.test yet they seem to disagree. What do I use for a decision? For my data set I have p.value of 0.05496421 returned from the shapiro.test and 0.882027 returned from the jarque.bera.test. I have included the data set below. Thank you. Kevin "Category","Period","Residual" "CHILD HATS, WIGS &