search for: fracs

... or if I understand correctly, simply expression(frac(additive ~ HCO[3]^"-", true ~ HCO[3]^"-" ))) Cheers, Bert On Fri, Feb 2, 2024 at 3:06?AM Rui Barradas <ruipbarradas at sapo.pt> wrote: > ?s 10:01 de 02/02/2024, Troels Ring escreveu: > > Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and > > > >

?s 10:01 de 02/02/2024, Troels Ring escreveu: > Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and > > ylab(expression(paste(frac("additive BIC","true BIC")))) worked OK - but > now I have been asked to put the chemistry instead - so I wrote > >

Hi friends - I'm plotting a ratio of bicarbonates i ggplot2 and ylab(expression(paste(frac("additive BIC","true BIC")))) worked OK - but now I have been asked to put the chemistry instead - so I wrote ?ylab(expression(paste(frac("additive",HCO[3]^"-","true",HCO[3]^"-")))) - and frac saw that as additive = numerator and HCO3- =

hello, I have the following problem setting parameter 'frac' in the sigest function of the kernlab package. ## executing the ?sigest example: library(kernlab) data(spam) srange <- sigest(type~.,data = spam) ## works fine... ## setting 'frac' explicitly ## (in this case even to the default of .25) options(error=recover) srange <- sigest(type~.,data = spam, frac = .25) ##

MM> I've sent two bug reports that both haven't been forwarded to R-devel MM> and haven't should up at the jitterbug repository. MM> ?? MM> Martin Well, actually only one [the other went to R-core alone] Here it is : From: Martin Maechler <maechler@sophie> To: R-bugs Subject: plot math - segfault and "frac", "^" bug(s).. Date: 8

...Vec) shortVec<-numeric() tics <- from*to for(j in 1:to){ interval <- ((j/to)*tics - (1/to)*tics + 1):((j/to)*tics) benchmarks <- interval/to #FIRST RUN ASSUMES FINAL BENCHMARK/TO IS AN INTEGER... positions <- which(round(benchmarks) == benchmarks) indeces <- benchmarks[positions] fracs <- numeric() #SINCE MUCH OF THE TIME THIS WILL NOT BE THE CASE, THIS SCRIPT DEALS WITH THE REMAINDER... for(i in 1:length(positions)){ if(i == 1) fracs[i] <- positions[i]/length(benchmarks) else{ fracs[i] <- (positions[i] - sum(positions[1:(i-1)]))/length(benchmarks) } } #AND UPDATES STA...

[this didn't go out at noon time during our e-mail storm...] In R versions 0.65, 0.90.0, and the current "pre-release", both on Linux and Solaris (the segfault at least) [with x11() , but most probably not device dependent]. The following shows it all : plot(1,type='n') ## Frac doesn't shrink properly... text(.7,1.3, expression( frac(7,4) == 1 *

This is in R versions 0.65, 0.90.0, and the current "pre-release", both on Linux and Solaris [with x11() , but most probably not device dependent]. The following shows it all : plot(1,type='n') ## Frac doesn't shrink properly... text(.7,1.3, expression( frac(7,4) == 1 * frac(3,4)), cex=1) text(.7,1.2, expression( frac(7,4) == 1 * frac(3,4)), cex=3)

Hi to all I use a loop to plot 9 different histograms of 9 different transformations of one dataset (x). I want to label the histograms with the mathematical expression of each transformation (e.g. x^3). For that I've prepared a vector with the labeling names for "expression". > trans.expr <- c("x^3", "x^2", "x", "frac(1,x)",

The following line of code seems fairly straight forward, yet it is kicking back an error message: for (i in 1:length(mean.natveg.frac)){month.observed[i]=as.numeric(names(mean.natveg.frac[i]))%%12} Error message: Error in month.observed[i] = as numeric(names(mean.natveg.frac[i]))%%12 : object 'month.observed' not found Seems like its not found because I'm trying to define it. Also

Recent questions about using plotmath have renewed my interest in this question I want to have expressions take values of variables from the environment. I am able to use expressions, and I am able to use paste to put text and values of variables into plots. But the two things just won't work together. Here is some example code that shows what I mean. plot(NA,xlim=c(0,100),ylim=c(0,100))

Hi, my proposal is based on a mathematical proof (see mail before) and yours is correct too. They cannot but match. Let's inspect your examples: Ady wrote: > ISO size: 1'085'736'960 bytes ( > 1GiB) This are exactly 132 cylinders of 255x63. 132 is divisible by 4. So there is no padding needed. > Cylinders (1st attempt)=132 > [...] > 2120580 / 4 = 530145, so

Hi all, I've been trying (unsuccessfully) to modify an xyplot I created using the lattice package. I would like to change default strip colors and locations. I started with numeric data in 4 columns, which look like this: 0.25 2 1 32 0.25 2 2 30 0.25 2 3 27 0.25 2 4 23 0.25 2 5 17 0.25 3 1 30 0.25

I'm currently working on writing up some documentation for some of my code, but am having the darndest time coding in equations. For example, the equation in the following: \details{ Calculated the R Squared for observed endogenous variables in a structural equation model, as well as several other useful summary statistics about the error in thoe variables. R Squared values are

Hi all; I recently have been used 'maxLik' function for maximizing G2StNV178 function with gradient function gradlik; for receiving this goal, I write the following program; but I have been seen an error  in calling gradient  function; The maxLik function can't enter gradlik function (definition of gradient function); I guess my mistake is in line ******** ,that the vector  ‘h’ is

From: Thorvald Natvig <slicer at users.sourceforge.net> Some optimizing compilers miscompile the current SSE optimizations when full optimizations are enabled. By using output value pointer instead of a return value, we can bypass this misbehaviour. --- libspeex/resample.c | 8 ++++---- libspeex/resample_sse.h | 24 ++++++++---------------- 2 files changed, 12 insertions(+), 20

I'm not sure who is responsible for quantile(), but I assume they read this list. Ivan Frohne and I have produced a revision of the quantile.default() function which enables the computation of alternative sample quantile definitions. The code and .Rd file are attached. This enables the user to produce quantiles that are equivalent to those in various statistics package. There is a type

Is there any R function to calculate automatically the last day of a particular month? For example "sep2009" should be converted to last day of September of 2009? Thanks -- View this message in context: http://www.nabble.com/How-to-get-last-day-of-a-month--tp25425645p25425645.html Sent from the R help mailing list archive at Nabble.com.

The boxplot below is close to what I would like, but needs some clean up. I've been unable to address the following: 1) How can I use the full extent of the plot space (there is white space on either side of the data)? 2) How can I reduce the # of month labels (e.g. every 3rd month Jan Mar Jun...) but still keep them staggered? 3) The year labels at the top of the plot have been positioned

Dear r-helpers, Does anyone have a straightforward example of putting together three unrelated (expect for a common y-axis) xyplot() figures in what would be in base graphics a par(mfrow = c(1, 3)) arrangement? _____________________________ Professor Michael Kubovy University of Virginia Department of Psychology USPS: P.O.Box 400400 Charlottesville, VA 22904-4400 Parcels: Room 102