search for: fives

Dear all, I want to make three plot below to only one plot together with legend, how can I do that? I have tried with matplot function but I did not succeed. Thanks for your help. Sincerelly, Jan Sabee test.five.x <- c(0.02,0.05,0.07,0.09,0.10,0.12,0.13,0.14,0.16,0.17,0.20,0.21,0.34,0.40) test.five.y <- c(18,12,17,12,3,15,1,5,1,1,3,10,15,10) plot(test.five.x, test.five.y,

Dear Asterisk Users, I'm a Japanese and now configuring Voicemail. Now I need to modify the way cmd VoicemailMain works to fix language difference and other my conveniences. What I want to do are... 1) Add words used in message retrieving guidance. I need to add different suffixes to numeric words due to Japanese way of mentioning time. (e.g. in English, you can say "Five

I'm trying to read in some data from a .csv format and have come across the following issue. Here is a simple example for replication # A sample .csv format schid,sch_name 331-802-7081,School One 464-551-7357,School Two 388-517-7627,School Three \& Four 388-517-4394,School Five Note the third line includes the \ character. However, when I read the data in I get >

Hi - I've got a question about what optimizations the "inbounds" keyword of "getelementptr" allows you to use. In the code below, %five is loaded from and inbounds offset of either a null pointer or %mem: target datalayout = "e-i64:64-f80:128-n8:16:32:64-S128" define i8 @func(i8* %mem) { %test = icmp eq i8* %mem, null br i1 %test, label %done, label

The OpenSSH project turns five years old ---------------------------------------- Five years ago, in late September 1999, the OpenSSH project was started. It began with an audit, cleanup and update of the last free version of Tatu Ylonen's legacy ssh-1.2.12 code. The project quickly gathered pace, attracting a portability effort and, in early 2000, an independent implementation of version 2

The OpenSSH project turns five years old ---------------------------------------- Five years ago, in late September 1999, the OpenSSH project was started. It began with an audit, cleanup and update of the last free version of Tatu Ylonen's legacy ssh-1.2.12 code. The project quickly gathered pace, attracting a portability effort and, in early 2000, an independent implementation of version 2

Hey, Once again I ask for some quick help. Here is some code: ovendata<- read.table("ovens.dat",header=TRUE) attach(ovendata) print(ovendata) Here is the .dat file: D One Two Three Four Five Seven Eight 1130 254 252 375 384 252 375 876 127 250 250 384 386 251 378 875 Here is the R Console output: >

root at five-72 ~ # dd if=/dev/zero of=/dev/sdb bs=1M count=1000 1000+0 records in 1000+0 records out 1048576000 bytes (1.0 GB) copied, 8.67101 s, 121 MB/s root at five-72 ~ # parted /dev/sdb GNU Parted 2.1 Using /dev/sdb Welcome to GNU Parted! Type 'help' to view a list of commands. (parted) mklabel gpt (parted) print Model: ATA ST3000DM001-1CH1 (scsi) -->

Dear All,   Here's my problem. I have two lists:   > v [[1]] [1] "five" [[2]] [1] "four" [[3]] [1] "three" [[4]] [1] "two" [[5]] [1] "one" [[6]] [1] "six" [[7]] [1] "five"  "four"  "three" "two"   "one"   "six"  [[8]] [1] "four"  "three"

Hello, Say all the below five vectors should have same elements in any situation. How to find the non matching vectors among these five, if so how we can find the non matching elements of those vectors? Can anyone help? a=c(1,2,3) b=c(1,2,3,4) c=c(1,2,3) d=c(1,2,3) e=c(1,4,5) identical(a,b,c,d,e) Visit us at Booth No. 5 at 2012 ChemOutsourcing Conference, 10-13 Sept 2012, Ocean Place Resort -

Dear all I have the following data (a shortened extract shown; some replictates of time deleted) to which I fitted the linear model given below: time group mass 11 control 0.019 11 control 0.014 14 control 0.0306 14 control 0.0289 14 control 0.0236 17 control 0.0469 17 control 0.0709 11 five 0.0077 11 five

Hello, I have a question regarding the candisc package. My data are: species three five 1 2.95 6.63 1 2.53 7.79 1 3.57 5.65 1 3.16 5.47 2 2.58 4.46 2 2.16 6.22 2 3.27 3.52 I put these in a table and then a linear model >newdata <- lm(cbind(three, five) ~ species, data=rawdata) and then do a candisc on them >candata<-candisc(newdata)

Hello Everyone, I need to do a complex migration of either a guest VM as a whole or as individual files with a dump and load of a progress database-based ERP system. The old host is an Amd Opteron 8 Core 16 GB ram single Socket CPU with a RAID 10 array of 8x 500 GB SATA Disks.? It is running Centos 6.10 as a base OS using OpenVZ as the VM technology.? Kernel version is 2.6.32-042stab142.1 x86_64

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for

Hi, I've always been a bit puzzled by MySQL's initial setup. Right after installing MySQL, no password is set, so that's the first thing I care about. I know there's a way to do that with mysqldadmin, but hey, different ways lead to Saint-Bauzille-de-Montmel. # chkconfig mysqld on # service mysqld start # mysql -u root mysql> use mysql; mysql> select user, host, password

Hi, I have a problem passing multiple arguments to program running by wine. Lets say I want to run foo.exe and pass 3 args: one two five. I found I should use sth like wine -- foo.exe one two five but then my wine says "unable to run --". I tried many possibilities and found that wine one foo.exe works but I can pass only 1 arg... I have wine 20041019 (know its really old, but

Hello Everyone, I've been running Asterisk as our PBX for several months now, and recently I've been thinking about using one of the VoIP providers to lower our phone bill. I know that VoIP providers can supply their customers with a local number and/or virtual numbers, and then that number/account can be used with Asterisk (well, it depends on the provider and whether or not their

I have been making some segment plots with five variables. They work great, especially when I used a different scale function, which scaled them by area of the circle rather than radius scale <- function(x, Mr = 1 , Mx = 100) { ((x/Mx)^.5)*Mr} Where x is the the value, Mr is the Maximum radius, and Mx is the maximum data value. You could change the exponent .5 to .57 if you wanted Flannery

Hi, I am fairly new to 'R' and would like advice on the following. I want to calculate a weekly average number of reports (e.g. of flu, norovirus) based on the same weeks for the last five years. I will then use this to plot a chart with 52 points for the average based on the last five years; another line will then plot the current year, enabling a comparison of current weekly counts

Hi, I hope that folks can give me some simple approaches to taking the data set below, which is accumulated in two columns called "long" and "group", then arrange the data is the "long" column into a data frame containing five variables: "Group 1", "Group 2", "Group 3", "Group 4", and "Group 5". I am hoping for a few