search for: five

Dear all, I want to make three plot below to only one plot together with legend, how can I do that? I have tried with matplot function but I did not succeed. Thanks for your help. Sincerelly, Jan Sabee test.five.x <- c(0.02,0.05,0.07,0.09,0.10,0.12,0.13,0.14,0.16,0.17,0.20,0.21,0.34,0.40) test.five.y <- c(18,12,17,12,3,15,1,5,1,1,3,10,15,10) plot(test.five.x, test.five.y, type="l",lty=1, lwd=3, col='red') legend(par('usr')[2], par('usr')[4], xjust=1, c('fiv...

...to modify the way cmd VoicemailMain works to fix language difference and other my conveniences. What I want to do are... 1) Add words used in message retrieving guidance. I need to add different suffixes to numeric words due to Japanese way of mentioning time. (e.g. in English, you can say "Five forty-five" for 5:45, but in Japanese, we have to put "hour" and "minute" for respective time unit (meaning, VoicemailMain should pronounce as "Five hours and forty-five minutes" in Japanese). So, is there any way to add words modifying the regular word order? 2)...

I'm trying to read in some data from a .csv format and have come across the following issue. Here is a simple example for replication # A sample .csv format schid,sch_name 331-802-7081,School One 464-551-7357,School Two 388-517-7627,School Three \& Four 388-517-4394,School Five Note the third line includes the \ character. However, when I read the data in I get > read.csv(file.choose()) schid sch_name 1 331-802-7081 School One 2 464-551-7357 School Two 3 388-517-7627 School Three & Four 4 388-517-4394 School F...

Hi - I've got a question about what optimizations the "inbounds" keyword of "getelementptr" allows you to use. In the code below, %five is loaded from and inbounds offset of either a null pointer or %mem: target datalayout = "e-i64:64-f80:128-n8:16:32:64-S128" define i8 @func(i8* %mem) { %test = icmp eq i8* %mem, null br i1 %test, label %done, label %mem.is.valid mem.is.valid: %1 = getelementptr inbounds i8, i8* %...

The OpenSSH project turns five years old ---------------------------------------- Five years ago, in late September 1999, the OpenSSH project was started. It began with an audit, cleanup and update of the last free version of Tatu Ylonen's legacy ssh-1.2.12 code. The project quickly gathered pace, attracting a portability e...

The OpenSSH project turns five years old ---------------------------------------- Five years ago, in late September 1999, the OpenSSH project was started. It began with an audit, cleanup and update of the last free version of Tatu Ylonen's legacy ssh-1.2.12 code. The project quickly gathered pace, attracting a portability e...

Hey, Once again I ask for some quick help. Here is some code: ovendata<- read.table("ovens.dat",header=TRUE) attach(ovendata) print(ovendata) Here is the .dat file: D One Two Three Four Five Seven Eight 1130 254 252 375 384 252 375 876 127 250 250 384 386 251 378 875 Here is the R Console output: > ovendata<- read.table("ovens.dat",header=TRUE) Warning message: incomplete final line found by readTableHeader on...

root at five-72 ~ # dd if=/dev/zero of=/dev/sdb bs=1M count=1000 1000+0 records in 1000+0 records out 1048576000 bytes (1.0 GB) copied, 8.67101 s, 121 MB/s root at five-72 ~ # parted /dev/sdb GNU Parted 2.1 Using /dev/sdb Welcome to GNU Parted! Type 'help' to view a list of commands. (parted) mklabel g...

Dear All,   Here's my problem. I have two lists:   > v [[1]] [1] "five" [[2]] [1] "four" [[3]] [1] "three" [[4]] [1] "two" [[5]] [1] "one" [[6]] [1] "six" [[7]] [1] "five"  "four"  "three" "two"   "one"   "six"  [[8]] [1] "four"  "three&qu...

Hello, Say all the below five vectors should have same elements in any situation. How to find the non matching vectors among these five, if so how we can find the non matching elements of those vectors? Can anyone help? a=c(1,2,3) b=c(1,2,3,4) c=c(1,2,3) d=c(1,2,3) e=c(1,4,5) identical(a,b,c,d,e) Visit us at Booth No. 5 at 201...

...replictates of time deleted) to which I fitted the linear model given below: time group mass 11 control 0.019 11 control 0.014 14 control 0.0306 14 control 0.0289 14 control 0.0236 17 control 0.0469 17 control 0.0709 11 five 0.0077 11 five 0.0101 14 five 0.0092 14 five 0.0125 17 five 0.0134 17 five 0.0143 11 ten 0.0088 11 ten 0.0092 14 ten 0.0114 14 ten 0.0113 17 ten 0.0131 17 ten...

Hello, I have a question regarding the candisc package. My data are: species three five 1 2.95 6.63 1 2.53 7.79 1 3.57 5.65 1 3.16 5.47 2 2.58 4.46 2 2.16 6.22 2 3.27 3.52 I put these in a table and then a linear model >newdata <- lm(cbind(three, five) ~ species, data=rawdata) and then do a candisc on them >candata<-candisc(new...

....3, libgmpxx.so.4, liblber-2.4.so.2, libacl.so.1 I've tried the suggestion of running rpm -Va --nofiles --nodigest, which completes but does not fix the files. Has anyone run into this i686 / x86_64 dual package conflicting issue before?? Any suggestions? Christopher Wensink IS Administrator Five Star Plastics, Inc 1339 Continental Drive Eau Claire, WI 54701 Office: 715-831-1682 Mobile: 715-563-3112 Fax: 715-831-6075 cwensink at five-star-plastics.com www.five-star-plastics.com

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for each of 26 weeks and store this data as a separate dataframe. I have been unable to get the sample function to work properly....

...+-----------+----------+ | root | localhost | | | root | buildbox | | | root | 127.0.0.1 | | | | localhost | | | | buildbox | | +------+-----------+----------+ 5 rows in set (0.00 sec) This shows that in my initial setup, I have no less than five initial users. A root user for three different hosts (localhost, buildbox and 127.0.0.1), and an empty user for two different hosts (localhost and buildbox). I don't know if I'm expected to set five passwords (five times the same? five different passwords?) for these five entities, but...

Hi, I have a problem passing multiple arguments to program running by wine. Lets say I want to run foo.exe and pass 3 args: one two five. I found I should use sth like wine -- foo.exe one two five but then my wine says "unable to run --". I tried many possibilities and found that wine one foo.exe works but I can pass only 1 arg... I have wine 20041019 (know its really old, but upgrading is out of me, moreover it seems...

...ve a call at the same using one VoIP line? In the analog world this obviously isn't possible, but with VoIP, it's just bandwidth: the more callers, the more bandwidth. I keep saying to myself it should be possible, but the VoIP providers don't provide any information about this. If five people in the office all need to use their phones at the same time, would I need five VoIP lines, or would I only need one VoIP line? Am I over-thinking this? Thanks in advance, Ranbir -- Kanwar Ranbir Sandhu Systems Aligned Inc. www.systemsaligned.com

I have been making some segment plots with five variables. They work great, especially when I used a different scale function, which scaled them by area of the circle rather than radius scale <- function(x, Mr = 1 , Mx = 100) { ((x/Mx)^.5)*Mr} Where x is the the value, Mr is the Maximum radius, and Mx is the maximum data value. You could c...

Hi, I am fairly new to 'R' and would like advice on the following. I want to calculate a weekly average number of reports (e.g. of flu, norovirus) based on the same weeks for the last five years. I will then use this to plot a chart with 52 points for the average based on the last five years; another line will then plot the current year, enabling a comparison of current weekly counts against a five year average for the same week. I would like some advice on how this can be done in &...

Hi, I hope that folks can give me some simple approaches to taking the data set below, which is accumulated in two columns called "long" and "group", then arrange the data is the "long" column into a data frame containing five variables: "Group 1", "Group 2", "Group 3", "Group 4", and "Group 5". I am hoping for a few different techniques which I can pass on to my students. Thanks David Arnold College of the Redwoods > dput(flies) structure(list(long = c(40L, 37L,...