Displaying 1 result from an estimated 1 matches for "fitlme7".
2006 Jan 09
2
decide between polynomial vs ordered factor model (lme)
...points (= equally
spaced)
zeitn = time points (n = 6)
subgr = small learning groups (n = 28)
gru = 4 different groups = treatment factor
levels: time (=zeitn) (n=6) within subject (n=4) within smallgroups
(=gru) (n = 28), i.e. n = 4 * 28 = 112 persons and 112 * 6 = 672 data points
library(nlme)
fitlme7 <- lme(nachw ~ I(zeitn-3.5) + I((zeitn-3.5)^2) +
I((zeitn-3.5)^3) + I((zeitn-3.5)^4)*gru, random = list(subgr = ~ 1,
subject = ~ zeitn), data = hlm3)
fit5 <- lme(nachw ~ ordered(I(zeitn-3.5))*gru, random = list(subgr =
~ 1, subject = ~ zeitn), data = hlm3)
anova( update(fit5, method="M...