Displaying 8 results from an estimated 8 matches for "find_wher".
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find_where
2008 May 19
0
changed to will_paginate
Hi
Till now we used the rails pagination.But now onwards shifting to
will_paginate
The code I use currently is as below .This is with the help of
find_where pluggin..A fantastic pluggin which we still want to use...I
would like to know how can i modify the following code to work with
will_paginate
step 1: set the variables you''ll need
page = (params[:page] ||= 1).to_i
items_per_page = 20
offset = (page -...
2008 Mar 06
1
pagination for an object array
...iables you''ll need
page = (params[:page] ||= 1).to_i
items_per_page = 20
offset = (page - 1) * items_per_page
# step 2: instead of performing the full find, just find the
record count
@search_sd_ticket_count_result =
ServiceDeskTicket.find_where(:all,:select=>''count(*) as count1'' ) do
|sd|
sd.number.downcase =~
"%"+@sd_ticket_number.downcase+"%" if !@sd_ticket_number.nil?
sd.name== @sd_ticket_name...
2008 Apr 26
0
moving pagination code to model
...es you''ll need
page = (params[:page] ||= 1).to_i
items_per_page = 20
offset = (page - 1) * items_per_page
# step 2: instead of performing the full find, just find the
record count
@search_sd_ticket_count_result =
ServiceDeskTicket.find_where(:all,:select=>''count(*) as count1'' ) do
|sd|
end
record_count=@search_sd_ticket_count_result[0].count1.to_i
# step 3: create a Paginator, the second variable has to be
the number of ALL items on all pages...
2006 Jun 14
6
find and LIKE ''xxx%'' clause
Hi there !
I try to figure out how to do something like this in Rails :
SELECT * FROM my_table WHERE name LIKE ''GOGONAM%''
My problem is the % and the quotes.
>From now, I do like this :
searched_name = params[:name]+''%''
user = MyTable.find(:all, :conditions => ["name LIKE ?", searched_name])
But is there a more gracefull way to do a LIKE
2006 Jun 30
3
New release of ez-where plugin
...expect.
So you can use blocks and ruby ops for very complex conditions. Here
is a teaser:
# find all articles with title, body or extended LIKE "%#{params
[:search]}%"
# AND (author.name = params[:author] OR comment.body LIKE "%#{params
[:search]}%")
@articles = Article.find_where(:all, :include => [:author,
{ :comments => :users }]) do
|article, author, comment|
article.any_of(:title, :body, :extended) =~ "%#{params[:search]}%"
any {
author.name == params[:author]
comment.body =~ "%#{params[:search]}%"
}
end
=>[&quo...
2006 Aug 07
2
Dynamically created queries
Hello,
I am having difficulty dynamically building a query. I want to ensure
that I''m using Active Record protection against SQL injection attacks.
In PHP land, I would have built up the query in my logic & attempted to
clean every variable - a bit tedious really.
I want to be able to achieve something like:
events = Event.find(:all,
:conditions => [**DynamicallyBuiltQuery**
2006 Jul 02
18
JOIN conditions
Hi,
how can I get Rails to generate SQL queries with conditions in the JOIN clause?
What I would want is:
SELECT * FROM people p
LEFT OUTER JOIN jobs j (p.job_id = j.id AND j.salary > 9999999)
I tried
People.find(:all, :include => ''jobs'', :conditions => ''jobs.salary > 9999999'')
but that generates
SELECT * FROM people p
LEFT OUTER
2006 Jun 19
6
SQL Search Qustion
I am working on writing a search method where a user can type a string
of words and I return all the objects that have fields that match all of
the words in one or a combination of fields.
Person
first_name
last_name
Pet
name
Person has_many :pets
I want to write some SQL so that if I search for "Tony AAAA" I will get
all the people who have Tony and AAA either in their