Displaying 2 results from an estimated 2 matches for "filtera".
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filter
2006 Jan 07
1
level sets of factors are different
Hi,
I have two data frames A en B.
I want to filter B with values of A
data_frame_b
names <- colnames(data_frame_b[1:1, ])
filtera <- data.frame(data_frame_a[1:1])
print(nrow(filtera))
if (nrow(filtera)>0){
filtered_frame_b <- subset(data_frame_b, ColumnX == filtera[1, 1], names)
}
The results are:
[1] 124
Error in Ops.factor(ColumnX, filtera[1, 1]) :
level sets of factors are different...
2007 Jul 05
3
Using conditions appropriately
...e been struggling with this function for most of the morning, but
something just doesn''t seem right in my logic with respect to
efficiency.
I have a basic view that is submitting information on three variables
directly to this function. The information is accessible simply through
params[:filtera1], params[:filtera2] and params[:filtera1].
I''m trying to build a find that will check the filter_a column in my
database table (places) and list the record if filter_a matches any one
of the three parameters just passed to it.
The difficulty comes from two areas
1. I have not perfected...