Displaying 1 result from an estimated 1 matches for "ffunarg".
Did you mean:
funarg
2011 Apr 29
3
How to define specially nested functions
Dear All,
I would like to define a function: f(x,y,z) with three arguments x,y,z, such that: given values for x,y, f(x,y,z) is still a function of z and that I am still allowed to find the root in terms of z when x,y are given.
For example: f(x,y,z) = x+y + (x^2-z), given x=1,y=3, f(1,3,z)= 1+3+1-z is a function of z, and then I can use R to find the root z=5.
Thank you.
-Chee
[[alternative