Displaying 20 results from an estimated 639 matches for "fff".
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2005 Oct 21
0
MASQed network to exit on different ext IP addres
...------- -------------------
|
|
VLAN0015 ETH0 -----
xxx.xxx.xxx.xxx
10.0.0.0/24 (alias on eth0) --
fff.fff.fff.fff.fff
i need that all traffic from subnet 10.0.0.0/24 goes out masqueraded
with ip address of alias on eth0 (fff.fff.fff.fff)
and have default gw bbb.bbb.bbb.bbb . There is obsolote kernel 2.2.25
and iproute ver. iproute2-ss991023 with ipchains version
ipchains 1.3.8, 27-Oct-1998
I t...
2002 Sep 19
5
how to use if statement in function correctly
...all
I try to persuade if statement in my function to work as I want (but I am not very
successful:(
My question is why my function with if statement is evaluated correctly in case of
atomic variables and incorrectly in case of vector variables.
Here is an example:
#function with if statement
fff <- function(otac,sklon)
{
test <- (otac * 3.69683+286.6*(1/sklon)-0.03100345*otac*sklon)
if(test<65)
{otac/sklon * 141.76}
else
{otac * 3.69683+286.6*(1/sklon)-0.03100345*otac*sklon}
}
> fff(20,70)
[1] 40.50286
# correct
> fff(50,70)
[1] 80.42371
#correct
> fff(seq(20,50,5),7...
2007 Oct 03
3
Factor levels.
I have factors with levels ``Unit", "Achieved", and "Scholarship"; I
wish to replace these with
"U", "A", and "S".
So I do
fff <- factor(fff,labels=c("U","A","S"))
This works as long as all of the levels are actually present in the
factor. But if ``Scholarship'' is absent
(as if often is) then I get an error.
I can do a workaround such as
fff <- factor(c("U",&quo...
2002 Nov 08
1
Using the ``...'' argument.
Suppose that I have a function fff which calls a couple of functions
foo and bar, and that foo takes optional arguments a and b, and bar
takes optional arguments u and v.
Is there an elegant way of passing ***both*** sets of optional
arguments via a ``...'' argument for fff?
I'd like to be able to have a structure like...
2010 Nov 30
2
xyplot : superimposed 2 groups in different panels
Hello,
I would like to plot the following xyplot : for each date of fff (1 date per
panel), bbb=f(aaa) for the two groups (ddd=1 and ddd=2) superimposed.
I can do it by group (see below) but not together.
I looked at http://lmdvr.r-forge.r-project.org/figures/figures.html but I
haven't found what I was looking for (to be honest, I haven't understood all
the ex...
2007 Jul 17
1
problem with length()
...hy length(eee) returns 9? I
was expecting 15398, and when I try to add this vector to a data
frame with that many rows, it fails complaining that the vector is of
length 9. In what I thought was an identical situation with a
related dataset, the same code worked as expected.
> length(fff)
[1] 15398
> str(fff)
int [1:15398] 20010102 20010102 20010102 20010103 20010103 20010102
20010102 20010104 20010103 20010102 ...
> fff[1:12]
[1] 20010102 20010102 20010102 20010103 20010103 20010102 20010102
20010104 20010103 20010102 20010105 20010103
> eee <- as.POSIXlt(strpti...
2004 Mar 25
1
factor based on pattern match ?
Hello,
is't possible to specify pattern in levels ?
> y=c("ff","f","m","mm","fm","mf","ffm","mmf","mmm","fff");
> factor(y)
[1] ff f m mm fm mf ffm mmf mmm fff
Levels: f ff fff ffm fm m mf mm mmf mmm
I want to specify levels using regexp ("f.*","m.*") or use some
another method. So, I could have 2 levels, say, F and M, where
F means everything beginning from 'f...
2010 Jul 07
3
how to process this in R
...med as xxx.txt. the content of the file looks like the
following:
name count
1. aaa 100
2. bbb 2000
3. ccc 300
4. ddd 3000
........
more that 1000 rows in each files.
these are the areas i need help:
1. how can i only read in the files with the string patterns ggg or fff as
part of the file names?
for instance, I only need the file names with the ggg or fff in it
xxxxx_ggg_yyyyy_1.txt
yyyy_fff_yyyy_xxx.txt
i don't need to read in the files, such as xxxx_aaa_yyyy.txt
2.how cam rename the files:
for instance: xxxxx_ggg_yyyyy_1.txt======...
2020 Oct 29
2
dovecot quota-warning detection mail
...-------------------------
---------------------
root:*::::/root::
aaaa:{CRAM-MD5}b09a26aedaddd0e66901eb4bc146b81930aac8be0dac96d1c83bb652fd4f7
451::::/var/home/xxx/aaaa::
bbbb-ccc-ddd:{CRAM-MD5}b09a15aedaddd0e55901eb4bc146b81930aac8be0dac96d1c83bb
652fd4f7451::::/home/vhosts/ddd/bbbb-ccc-ddd::
eeee-fff-ggg:{CRAM-MD5}f4c336c68f063d1bbc2a1e32ae32bc9c978d0d2565eae42b4485d
50370d157cd::::/home/vhosts/ggg/eeee-fff-ggg::
hhhh-iii-jjj:{CRAM-MD5}78b337b326d57d564454d8019ed22b5d5cd181437aff77988e2c3
a12ec2d8490::::/home/vhosts/jjj/hhhh-iii-jjj::
:
:
----------------------------------------------------...
2012 Feb 20
2
Help on lattice barchart ploting
...AAA 3.636 2/2
BBB 85.965 2/2
BBB 14.035 2/1
CCC 63.158 1/1
CCC 21.053 1/2
CCC 15.789 2/2
DDD 26.786 2/2
DDD 46.429 2/1
DDD 26.786 1/1
EEE 32.759 2/2
EEE 43.103 2/1
EEE 24.138 1/1
EEE 37.931 1/1
EEE 51.724 1/2
EEE 10.345 2/2
FFF 23.214 2/2
FFF 53.571 2/1
FFF 23.214 1/1
GGG 46.552 1/1
GGG 44.828 1/2
GGG 8.621 2/2
HHH 65.517 2/2
HHH 32.759 2/1
HHH 1.724 1/1
Following is the code which I have written to get the plot.
barchart(Genotype~Freqs | RsID, data=gDataFr,layout=c(4,6),...
2004 Jan 09
1
degree-min-sec data
...")
but surely there is a better way!
Or is this the wrong technique?
More generally, is there a way to "unzip" a character vector along some
split marker, handling irregulatirites gracefully? For example, from
y<-c("aaa#bbb", "ccc#ddd", "eee","fff"),
strsplit(y,split="#") would produce
c(c("aaa","bbb"), c("ccc","ddd"), c("eee","fff")).
Is there a way to produce instead
c(c("aaa","ccc","eee"),c("bbb","ddd","fff...
2001 Apr 17
0
RE: [Rd] converting body of a function to a a character vector
1. This query belongs in r-help, not in r-devel
2. Pity about your shift key...
3. The function you need is deparse() rather than as.character():
> fff <- function(x) {
+ x*x
+ }
> deparse(body(fff))
[1] "{" "x * x" "}"
>
4. There is a reason why as.character works this way. It transforms to
character from a more fundamental representation of the language object, but
that's a larger story...
B...
2009 Jul 20
0
No subject
...1
Content-Transfer-Encoding: quoted-printable
<span id=3D"result_box" class=3D"long_text"><span title=3D"Boa tarde." onmo=
useover=3D"this.style.backgroundColor=3D'#ebeff9'" onmouseout=3D"th=
is.style.backgroundColor=3D'#fff'">Good afternoon.
<br>
<br></span><span title=3D"Obrigado =E0 todos pelas respostas." onmouseover=
=3D"this.style.backgroundColor=3D'#ebeff9'" onmouseout=3D"this.styl=
e.backgroundColor=3D'#fff'">T...
2013 Feb 04
1
Help on conditional selection of data.frame data...
Hello,
I have trouble with using data.frame data.
1. I loaded data using the following:
ff <- read.table("E:/R/VM/matrix.txt", header=T)
The data I used is attached.
I want to use at least 2 conditions for selecting of data. But I failed.
It works. ->
fff <- ff[ff$HG == "GUEST",]
ffff <- fff[fff$WR == "READ",]
But it doesn't work -> ff[ff$HG == "GUEST",ff$WR=="READ"]
How can I use 2 or more conditions together in one sentence ?
2. I want to plot Throuput data using BlockSize a...
2007 Jun 20
2
[LLVMdev] Unique shape and types
...es, LLVM only has one instance of a given
shape, mostly for type equality (and I suppose projects like pool
allocation requires it).
However, this leads to a somehow misleading bytecode representation. For
example, consider the C++ program compiled with llvm-g++:
class AAA {
int b;
};
class FFF {
int a;
};
extern int foo(AAA * aaa);
extern int bar(FFF * aaa);
This gets compiled to
%struct.AAA = type { i32 }
%struct.FFF = type { i32 }
declare i32 @foo(AAA*)(%struct.AAA*)
declare i32 @bar(FFF*)(%struct.AAA*)
This is misleading because the bytecode tells us the argument type of
ba...
2012 Nov 23
2
error in IF condition with factor evaluation
..." that are named "DISCONECTED"
thank you
> summary(dataset$STATUS.x)
ACTIVE DISCONECTED PENDING SUSPENDED TERMINATED
158869 169181 3028 8565 47233
NA's
6
> class(dataset$STATUS.x)
[1] "factor"
>
> fff = function(x) {
+ for (i in 1:length(x)){
+ if (x[i] == "DISCONECTED") {
+ x[i] == "DISCONNECTED"
+ } else x[i] == x[i]
+ }
+ return(x)
+ }
>
> r = fff(dataset$STATUS.x)
Error in if (x[i] == "DISCONECTED") { :
missing value where TRUE/FALSE needed
[[alternati...
2011 Aug 15
2
area under the curve
...answer:
x<-seq(1:50)
y<-seq(1:50)
simp <- function (y, a = NULL, b = NULL, x = NULL, n = 200)
{
if (is.null(a) | is.null(b)) {
if (is.null(x))
stop("No x values provided to integrate over.\n")
}
else {
x <- c(a, b)
}
fff <- 1
if (length(x) == 2) {
if (x[1] == x[2])
return(0)
if (x[2] < x[1]) {
fff <- -1
x <- rev(x)
}
x <- seq(x[1], x[2], length = n)
if (is.function(y))
y <- y(x)
else {...
2006 Jul 08
1
KhmaladzeTest
..., ]) : NA/NaN/Inf en llamada a una funci?n externa (arg
1)
> invisible(edit(Datos))
> local({pkg <- select.list(sort(.packages(all.available = TRUE)))
+ if(nchar(pkg)) library(pkg, character.only=TRUE)})
> fit <- rqProcess( yyy ~ lll, data = Datos, taus = seq(.1,.9,by =
.05))
> fff <- rqProcess( yyy ~ lll, data = Datos, taus = seq(.1,.9,by =
.05))
taus: 0.1 Erro en summary.rq(rq(formula, data = data, tau = taus[i],
method = "fn"), :
tau - h < 0: error in summary.rq
> fff <- rqProcess(yyy ~ lll, data = Datos, taus = -1, nullH =
"locati...
2007 Feb 23
4
using "integrate" in a function definition
Dear list members,
I'm quite new to R, and though I tried to find the answer to my probably
very basic question through the available resources (website, mailing
list archives, docs, google), I've not found it.
If I try to use the "integrate" function from within my own functions,
my functions seem to misbehave in some contexts. The following example
is a bit silly, but
2010 May 20
2
Re : Manipulating Data Frames
...csv(file='ipsample.csv',sep=',' , header=TRUE)
> data
State Jan Feb Mar Apr May Jun
1 AAA 1 1 0 2 2 0
2 BBB 1298 1195 1212 1244 1158 845
3 CCC 0 0 0 1 2 1
4 DDD 5 11 17 15 10 9
5 EEE 18 28 27 23 23 16
6 FFF 68 152 184 135 111 86
from this data frame, I took "Jan" as base and calculating weightage like
this :
> basemonth.sum <- sum(data[[2]])
> basemonth.sum
[1] 1390
> basemonth.data <- data[[2]]
> basemonth.data
[1] 1 1298 0 5 18 68
> weightage...