Displaying 2 results from an estimated 2 matches for "fbms".
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bms
2010 Feb 04
1
for loop with if statment problem
...2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L), .Label = c("bmcm", "fbms", "fcms", "jcms", "jpms", "lrf1",
"wpms"), class = "factor"), Date = structure(c(2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2...
2010 Aug 03
2
subset based on column names and then subset based on the inverse (grep?, or...)
...;ftbr", "ftbr", "ftbr", "ftbr", "ftbr",
"ftbr", "ftbr", "ftbr"), creek = c("jcms", "wpms", "lrf1", "bmcm",
"fcms", "lrtb", "hcms", "jpms", "fbms", "gbms"), date = c("06/20/2010",
"06/20/2010", "06/18/2010", "06/18/2010", "06/21/2010", "06/22/2010",
"06/22/2010", "06/21/2010", "06/19/2010", "06/19/2010"), elevation_m = c(101,
81...