search for: farnel

Suppose I have a string of objects names: name <- c("foo", "bar", "baz") and I would like to use a for loop to automatically create three objects called "foo", "bar" and "baz" accordingly. Then how can this be done" (so that in the workspace, foo = 1, bar = 2 and baz=3) for (i in name) { ..... } Thanks! Mark

I wish to draw a graph representing multiple series (sets of x,y points). Each series has its own label and points within each series are joined by a line ordered by their X cooridnate. I would also like a legend automatically showing which each series is. Which high-level command can serve this purpose? I looked at my book but can't find such a command. Thanks! Mark

Hello! I'm using Red hat 7.2 with WINE installed. When I try to run the Windows notepad under WINE, the console lists many fonts that it can't load (about 50) and the WINE program takes about 10 minutes to load the program. How can I fix the problem? Regards, Mark Farnell

When I use xyplot (from package lattice) to produce a multi-series graph: xyplot(linear+quadratic+sqrt~x, data=df, main="complexity of different functions", ylab="y", col=c("red", "black", "orange"), type="b", lty=c(1,2,3), pch=c(1,2,3), auto.key=TRUE) where I changed the default colour, line type and data point type so that each series

...an AGI script for some time, having the two parties talk to each other, at the same time have asterisk or the AGI script listen for DTMF tones on both channels and react to certain tones, i.e. disconnecting the two channels on reception of "0", but not hanging up either one? I found Cam Farnell's AGI documentation. Fine work, Cam, thanks a lot, but no clue in there. As far as I understand asterisk, the "Dial" application won't do this job either, would it? Any help is greatly appreciated. Rgds, Markus

Currently I invoke: foo <- read.table("foo.data", header=TRUE) to read a table into foo Then when I try to plot a histogram out of the 5th column of foo: hist(foo[5]) It fails and it says: Error in hist.default(foo[5]) : 'x' must be numeric Then I tried: >typeof(foo[5]) [1] "List" So how can I get an numeric array out of one of the columns? Also suppose