Displaying 14 results from an estimated 14 matches for "factorb".
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2009 Feb 27
1
testing two-factor anova effects using model comparison approach with lm() and anova()
I wonder if someone could explain the behavior of the anova() and lm()
functions in the following situation:
I have a standard 3x2 factorial design, factorA has 3 levels, factorB has 2
levels, they are fully crossed. I have a dependent variable DV.
Of course I can do the following to get the usual anova table:
> anova(lm(DV~factorA+factorB+factorA:factorB))
Analysis of Variance Table
Response: DV
Df Sum Sq Mean Sq F value Pr(>F)
factorA...
2009 Apr 10
2
Problem with bargraph.CI in Sciplot package
...ponse<-c(32,54,32,65,34,65,65,45,54,23,43,23,76,87,65,45)
factorA<-c("A","A","A","A","A","A","A","A","B","B","B","B","B","B","B","B")
factorB<-c("a","a","a","a","b","b","b","b","a","a","a","a","b","b","b","b")
data<-data.frame(response,factorA,factorB)
bargraph.CI(x.factor =...
2008 Mar 25
0
Behaviour of interactions in glm
...is as a separate column in my data. So, it looks like I have
factor A + factor B + factor C:factor B, but I don't want terms for the
base level of factor B for that factor C:factor B interaction.
An example of the data I'm trying to fit a model to could be as follows:
Record FactorA FactorB Weight Response
1 1 1 1 0.73
2 1 2 0.5 0
3 1 3 1 1.00
4 2 1 0.33 2.77
5 2 2 0.4 0
6 2 3 5 0
(I've given a sample here, as my data h...
2011 Jan 21
1
TRADUCING lmer() syntax into lme()
...ject.org
Dear Rsociety,
I'd like to kingly ask to anyone is willing to answer me how to implement a
NON NESTED random effects structure in lme()
In particular I've tried the following translation from lmer to lme, as
suggested from some web example
mod1<-lmer(y~x*z+(x*z|factorA1/factorB)+(x*z|factorA2/factorB)) # y,x,z
continuous
mod2<-lme(y~x*z, random= pdBlocked(list(pdIdent(~1|factorA1/factorB
),pdIdent(~1|factorA2/factorB))))
In detail check how I've tried to state in mod1 that Iwant to evaluate
randomness in the interaction x*z (i.e intercept, slope, interaction)
g...
2008 Nov 04
1
How to generate a new factor variable by two other factor variables
How to generate a new factor variable by two other factor variables?
For example, if I have two factor variables, factorA and factorB,
factorA factorB
0 0
0 0
1 0
0 1
1 1
Is there a simple way to generate a new 4-levels factor variable as
factorC factorA factorB
0 0 0
0 0 0
1 1 0
2 0 1
3 1 1
--
Shuguang...
2008 Nov 30
2
Randomization of a two-way ANOVA?
Hello list,
I wish to perform a randomization test on the F-statistics of a 2 way ANOVA
but have not been able to find out how to do so - is there a package /
function that can perform this that I am unaware of?
FactorA has 6 levels (0,1,2,3,4,5) whereas FactorB has 3 (1,2,3). A sample:
Resp. FactorA FactorB
2 0 2
3 1 2
1 2 2
0 3 2
0 4 2
0 5 2
4 0 1
6 1 1
1 2 1
0 3 1
1 4 1
0 5 1
2 0 2
3 1 2
1 2 2
2 3 2
1 4 2
0 5 2
3 0 1
3 1 1
1 2 1
0 3 1
0 4 1
7 1 3
2 2 3
0 3 3
1 4 3
0 5 3
1 0 3
Also, is the F-statistic an appropriate test-statistic for the randomization...
2016 Sep 19
3
[arm, aarch64] Alignment checking in interleaved access pass
Hi,
As a follow up to Patch D23646 <https://reviews.llvm.org/D23646>, I'm
trying to figure out if there should be an alignment check and what the
correct approach is.
Some background:
For stores, the pass turns:
%i.vec = shuffle <8 x i32> %v0, <8 x i32> %v1,
<0, 4, 8, 1, 5, 9, 2, 6, 10, 3, 7, 11>
store <12 x i32> %i.vec, <12 x i32>* %ptr
2004 Aug 06
1
Lattice: how to index in a custom panel function?
...ind examples for the strips using which.given and
which.panel. But this does not work for the panels...
Can Anybody give a hint? Thanks
Joris
I work with R 1.9.1 under Linux
panel.txt = function(sometxt,x,y,...){
grid.text(sometxt,x,y)
}
xyplot(data = Pdata, P ~ DAS | FactorA,
groups = FactorB,
type ="s",
col = c("red","blue"),
panel = function(x,y,...){
panel.abline(h = 100, lty = 5, lwd =0.5, col = "darkgrey")
panel.txt(mytext, 0.2, 0.8)
}
--
======================================================================
Jo...
2016 Oct 10
2
[arm, aarch64] Alignment checking in interleaved access pass
...[i+2] * Factor; // B
>
> This pattern is easily vectorised on most platforms, since loads, muls
> and stores are the exact same operation. which can be combined.
>
> for (i..N)
> out[i] = in[i] * FactorR; // R
> out[i+1] = in[i+1] * FactorG; // G
> out[i+2] = in[i+2] * FactorB; // B
>
> This still can be vectorised easily, since the Factor vector can be
> easily constructed.
>
> for (i..N)
> out[i] = in[i] + FactorR; // R
> out[i+1] = in[i+1] - FactorG; // G
> out[i+2] = in[i+2] * FactorB; // B
>
> Now it gets complicated, because the...
2005 Dec 26
3
factorial anova
Hello every body, I am trying to do a factorial anova analysis
following this model:
model<-anova(lm(responsevariable~factorA*factorB))
model<-anova(lm(luz$dosel~luz$estado*luz$Bosque))
Df Sum Sq Mean Sq F value Pr(>F)
estado 1 6931.1 6931.1 41.6455 7.974e-06 ***
Bosque 1 36.6 36.6 0.2197 0.6456
estado:Bosque 1 36.6 36.6 0.2197 0.6456
Residuals 16 2662.9 166.4
Strange is that...
2012 Nov 21
0
Two way manova
Hello everyone,
I would like to perform a 2-way manova test, but I'm having some issues.
I implemented like this
Y<-cbind(Resp1,Resp2,Resp3,....,Respn)
model<-manova(Y "tilda" FactorA*FactorB)
summary.aov(model)
1. I don't know at what level I have to do the Type I error correction. Is
it on p-values returned by "summary.aov(model)? Or is it when I compare each
subgroup with another subgroup? Or is it for summary(model)?
2. I have a significant interaction on summary(model)...
2010 Sep 15
0
A question on modelling binary response data using factors
...r C has 5 levels (C1,C2,C3,C4,C5). The experiment has only
partial coverage, that is not every A is tested with every B and every C.
However,
I was careful in the experimental design to ensure that every A and every B
was tested against at least one C.
Here is my experimental data:
FactorA FactorB FactorC Hit Miss
A1 B1 C1 17 83
A1 B1 C2 17 83
A1 B1 C3 18 82
A1 B1 C4 NA NA
A1 B1...
2007 Mar 29
3
Vector indexing question
Suppose you have 4 related vectors:
a.id<-c(1:25, 1:25, 1:25)
a.vals <- c(101:175) # same length as a.id (the values for those IDs)
a.id.levels <- c(1:25)
a.id.ratings <- rep(letters[1:5], times=5) # same length as a.id.levels
What I would like to do is specify a rating from a.ratings (e.g. "e"),
get the vector of corresponding IDs from a.id.levels (via
2011 Jan 22
0
how to call BayesX in R to see the graph
...ject.org
Dear Rsociety,
I'd like to kingly ask to anyone is willing to answer me how to implement a
NON NESTED random effects structure in lme()
In particular I've tried the following translation from lmer to lme, as
suggested from some web example
mod1<-lmer(y~x*z+(x*z|factorA1/factorB)+(x*z|factorA2/factorB)) # y,x,z
continuous
mod2<-lme(y~x*z, random= pdBlocked(list(pdIdent(~1|factorA1/factorB
),pdIdent(~1|factorA2/factorB))))
In detail check how I've tried to state in mod1 that Iwant to evaluate
randomness in the interaction x*z (i.e intercept, slope, interaction)
g...