Displaying 20 results from an estimated 2701 matches for "f1".
2004 Sep 20
1
Using eval() more efficiently?
...ot;
automatically generated by some selection criteria.
Now, if I have a data frame with many variables, of which the variables in
"names.select" are also variables from the data frame. e.g.
> all.df[1:5,]
Mouse Idd5 Idd6.19.20 Idd13 Idd14 Idd8.12 Idd3.10.17.18 Idd9
1 904 F1 NOD NOD F1 NOD F1 NOD
2 934 NOD F1 F1 F1 F1 NOD NOD
3 950 NOD NOD F1 NOD F1 F1 NOD
4 977 F1 NOD NOD F1 F1 F1 F1
5 1050 F1 F1 NOD NOD NOD...
2010 Dec 23
1
with(data.frame,ifelse(___,___,___))
Hello, All,
Mac OS 10.6.5
R64 2.11.1
This works as expected:
f1 = c(0.084, 0.099, 0)
data= data.frame(f1)
data$f1=with(data,ifelse(f1==0, 0.0001, f1))
data
f1
1 0.0840
2 0.0990
3 0.0001
Substituting ''f1==0'' with ''T'' produces the expected result:
f1 = c(0.084, 0.099, 0)
data= data.frame(f1)
data$f1=with(data,ifelse(T,...
2008 Apr 18
3
Function redefinition - not urgent, but I am curious
This is just my curiousity working.
Suppose I write:
f1 <- function(x) x + 1
f2 <- function(x) 2 * f1(x)
f2(10)
# 22
f1 <- function(x) x - 1
f2(10)
# 18
This is quite obvious. But is there any way to define f2
in such a way that we "freeze" the definition of f1?
f1 <- function(x) x + 1
f2 <- function(x)
# put something here
2...
2006 Aug 16
1
Specifying Path Model in SEM for CFA
I'm using specify.model for the sem package. I can't figure out how to
represent the residual errors for the observed variables for a CFA
model. (Once I get this working I need to add some further constraints.)
Here is what I've tried:
model.sa <- specify.model()
F1 -> X1,l11, NA
F1 -> X2,l21, NA
F1 -> X3,l31, NA
F1 -> X4,l41, NA
F1 -> X5, NA, 0.20
F2 -> X1,l12, NA
F2 -> X2,l22, NA
F2 -> X3,l32, NA
F2 -> X4,l42, NA
F2 -> X6, NA, 0.25
F1 <-> F2,g12, 1
F1 <-> F1,g11, 1
F2 <->...
2009 Jun 30
2
Using functions to change values in a data.frame
...s to copy
positive values of y into p and negative values into l.
<START COPY>
AddCols = function (MyFrame) {
MyFrame$p<-0
MyFrame$l<-0
return(MyFrame)
}
BinPosNeg = function (MyFrame) {
ifelse(MyFrame$y>0, MyFrame$p<-MyFrame$y, MyFrame$l<MyFrame$y)
return(MyFrame)
}
F1 <- data.frame(x=1:10, y=-4:5)
F1
F1 <- AddCols(F1)
F1
F1 <- BinPosNeg(F1)
F1
<END COPY>
My results below are weird. After the last function call F1 acts like
BinPosNeg always evaluated MyFrame$y>0. All updates went into p - none
into l.
What am I doing wrong?
Thanks,
Mark
MY...
2008 Apr 24
4
bug in file.path?
Se ha borrado un texto insertado con un juego de caracteres sin especificar...
Nombre: no disponible
Url: https://stat.ethz.ch/pipermail/r-help/attachments/20080424/2226f24e/attachment.pl
2019 Sep 30
5
Is missingness always passed on?
...or a local call. This may change in the future."
Someone pointed out (in https://stackoverflow.com/a/58169498/2554330)
that this isn't true in the examples they've tried: missingness does
get passed along. This example shows it (this is slightly different
than the SO example):
f1 <- function(x, y, z){
if(missing(x))
cat("f1: x is missing\n")
if(missing(y))
cat("f1: y is missing\n")
}
f2 <- function(x, y, z){
if(missing(z))
cat("f2: z is missing\n")
f1(x, y)
}
f2()
which produces
f2: z is missing
f1: x is mis...
2011 Feb 14
4
sem problem - did not converge
Someone can help me? I tried several things and always don't converge
# Model
library(sem)
dados40.cov <- cov(dados40,method="spearman")
model.dados40 <- specify.model()
F1 -> Item11, lam11, NA
F1 -> Item31, lam31, NA
F1 -> Item36, lam36, NA
F1 -> Item54, lam54, NA
F1 -> Item63, lam63, NA
F1 -> Item65, lam55, NA
F1 -> Item67, lam67, NA
F1 -> Item69, lam69, NA
F1 -> Item73, lam73, NA
F1 -> Item75, lam75, NA
F1 -> Item76, lam7...
2008 Apr 04
2
How to create a function calling two functions with unknown number of parameters?
... can be used to represent unknown number of parameters passed into a
function.
For example, I write a function g. g calls another function f1.
For example f1 could be different random number generation function.
when f1=rnorm(), it has 3 parameters n, mean and standard deviation.
when f1=rexp(), it has 2 parameters n and rate.
g can be defined as
g <- function(f1, ...) {
f1(...)
}
My problem is what about g calls two functio...
2005 Jul 18
1
levels() deletes other attributes
Dear All,
it seems to me that levels() deletes other attributes. See the following
example:
## example with levels
f1 <- factor(c('level c','level b','level a','level c'), ordered=TRUE)
attr(f1, 'testattribute') <- 'teststring'
attributes(f1)
levels(f1) <- c('L-A', 'L-B', 'L-C')
attributes(f1)
If I run it, after assigning new levels,...
2009 Jul 01
1
How should I denormalise a data frame list of lists column?
...e based on membership of the lists in that column and be
able to 'denormalise' the data frame so that a row is duplicated for each of
its list elements. Example code follows:
# The data is read in in this form with the c2 list values in single strings
which I then split to give lists:
> f1 <- data.frame(c1=0:2, c2=c("A,B,C", "A,E", "F,G,H"))
> f1$Split <- strsplit(as.character(f1$c2), ",")
> f1
c1 c2 Split
1 0 A,B,C A, B, C
2 1 A,E A, E
3 2 F,G,H F, G, H
# So f1$Split is the list of lists column I want to denormalise...
2000 Dec 29
2
how to create help files
...regarding the
documentation of ones own functions.
I have ceated a private library for my functions, which works all very well,
apart from that I am not able to create appropriate help files.
For illustration, here is a simple example of where I'm stuck:
> # first, create a simple function f1:
> f1 <- function(x) x^2
> # create directories where a package called "testfunctions" with my own
functions will live:
> R.home()
[1] "D:\\Programme\\R\\rw1020"
> mypath <- paste(R.home(),"\\library\\testfunctions", sep="")
> mypath
[1]...
2002 Aug 20
1
About lm()
Dear Mr. and Mrs.
I'm very grateful for these software and this list.
My question is:
when a use linear multiple regression (lm()) for my data,
abundance ichthyoplankton ~ salinity + temperature + month of the
year(f1 is a factor: 1 for january, 2 for february, ..., 12 for december),
the summary() of results is
...
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 0.726347 0.285607 2.543 0.011217 *
temperature -0.011410 0.014200 -0.804 0.421978
salinity...
2009 Jul 01
2
?max (so far...)
...n (MyFrame) {
MyFrame$pwin <- round((MyFrame$pc / (MyFrame$pc+MyFrame$lc)),2)
return(MyFrame)
}
HighLow = function (MyFrame) {
temp1 <- MyFrame$p[1:row]
MyFrame$hp <- max(temp1) ## Highest p
temp1 <- MyFrame$l[1:row]
MyFrame$ll <- min(temp1) ## Lowest l
return(MyFrame)
}
F1 <- data.frame(x=1:10, y=2*(-4:5) )
F1 <- AddCols(F1)
F1 <- BinPosNeg(F1)
F1 <- RunningCount(F1)
F1 <- PercentWins(F1)
F1
F1 <- HighLow(F1)
F1
temp1<-F1$p[1:5]
max(temp1)
temp1<-F1$p[1:7]
max(temp1)
temp1<-F1$p[1:10]
max(temp1)
2007 Jul 12
1
sub-function default arguments
Hi.
I have defined a function, f1, that calls another function, f2. Inside f1
an intermediate variable called nm1 is created; it is a matrix. f2 takes a
matrix argument, and I defined f2 (schematically) as follows:
f2<-function(nmArg1=nm1,...){nC<-ncol(nmArg1); ... }
so that it expects nm1 as the default value of its ar...
2009 Jul 01
1
running count in data.frame
...e
MyFrame$l column, and likewise for $pc and $p. It seems that $lc
starts off OK until it gets to a 0 and then resets back to 0 which I
don't want. The $pc counter never seems to count. I also get a warning
message I don't understand so clearly I'm doing something very wrong
here:
> F1 <- RunningCount(F1)
Warning messages:
1: In MyFrame$pc[pos] <- cumsum(as.integer(pos)) :
number of items to replace is not a multiple of replacement length
2: In MyFrame$lc[pos] <- cumsum(as.integer(pos)) :
number of items to replace is not a multiple of replacement length
> F1...
2005 Feb 28
5
persistance of factor levels in a data frame
Hi,
Just something I don't understand:
data <- data.frame(V1=c(1:12),F1=c(rep("a",4),rep("b",4),rep("c",4)))
data_ac <- data[which(data$F1 !="b"), ]
levels(data_ac$F1)
Why the level "b" is always present ?
thanks
Tristan, R 2.0.1 for Linux Fedora 3
--
-------------------------------------------------------...
2012 May 02
2
output Shapiro-Wild results to a table
Hello,
I have applied the Shapiro test to a matrix with 26.925 rows of data using the following
F1.norm<-apply(F1.n.mat,1,shapiro.test)
I would now like to view and export a table of the p and W values from the Shapiro test, but I am not sure how to approach this.
I have tried the following with errors.
> write.table(x=F1.norm,file="I:/R_Work/F1/Shapiro.csv", sep=",&quo...
2012 Jul 11
2
[LLVMdev] [NVPTX] llc -march=nvptx64 -mcpu=sm_20 generates invalid zero align for device function params
...;
.reg .s32 %r<396>;
.reg .s64 %rl<396>;
.reg .f32 %f<396>;
.reg .f64 %fl<396>;
// BB#0: // %entry
mov.b64 %rl0, __internal_dsmul_param_1;
cvta.local.u64 %rl0, %rl0;
ld.f32 %f0, [%rl0+4];
neg.f32 %f1, %f0;
mov.b64 %rl1, __internal_dsmul_param_2;
mov.f32 %f2, 0f45800800;
// inline asm
mad.f32 %f1, %f1, %f2, %f0;
// inline asm
// inline asm
mad.f32 %f3, %f0, %f2, %f1;
// inline asm
cvta.local.u64 %rl1, %rl1;
ld.f32 %f1, [%rl1+4];
neg.f32...
2009 Jul 15
4
Extract pairs (rowname, columname) from a matrix where value is 0
Dear sir,
I have a matrix like
a<-matrix(c(0,2,0,4,0,6,5,8,0),nrow=3)
colnames(a)<-c("F1","F2","F3")
rownames(a)<-c("A1","A2","A3")
a
F1 F2 F3
A1 0 4 5
A2 2 0 8
A3 0 6 0
I want to extract all pairs (rownames, columnames) from which the value in
the matrix is 0
The result should be something like this
A1, F1
A2, F...