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eth
2009 Aug 05
1
Decision boundaries for lda function?
....ld,type="n",xlab="LD1", ylab="LD2",las=1)
> text(aa.ld,c(rep('f',13),rep('b',10),rep('p',10)))
> aa.mean<-lda(aa.ld,AA$group)$means
> points(aa.mean,pch=3)
Best,
Thomas Larsen
Leibniz-Laboratory for Stable Isotope Research
Max-Eyth-Str. 11-13, 24118 Kiel, Germany
Work: +49-431-880-3896
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