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2007 May 03
2
convert text to exprission good for lm arguments
Hi,
I ran into a problem of converting a text representation of an expression into parsed expression to be further evaluated inside lm ().
> n <- 100
> data <- data.frame(x= rnorm (n), y= rnorm (n))
> data. lm <- lm (y ~ x, data=data)
>
> ## this works
> update(data. lm , subset=x<0)
Call:
lm (formula = y ~ x, data = data, subset = x < 0)