search for: expresssion

...Expression) - and the aforegoing type==DNase HS (which is not necessarly row n-1 - assumung that the defined row is n). I dont know how to add this to my subset command. Is that possible? Thanks Hermann > df start.ens fc.trans type end.ens peak end.grcm38 dpeak 1 9191942 0.9379 Expresssion NA NA NA NA 2 9191942 0.9741 Expresssion NA NA NA NA 3 9191942 0.9748 Expresssion NA NA NA NA 4 9195570 NA DNase HS NA NA 9195792 109 5 9579854 NA DNase HS NA NA 9580110 131 6 1108...

...have looked at ?plotmath, but didn't find the answer and also searched the R website. ------------------------------------------------------------------------ -- plot(1:10,xlab=expression(^{14}*C)) # I want to have a superscript with nothing in front, but it doesn't work plot(1:10,xlab=expresssion(.^{14}*C)) # this works, but is not beautiful Any ideas ? ------------------------------------------------------------- Henrik Andersson Netherlands Institute of Ecology - Centre for Estuarine and Marine Ecology P.O. Box 140 4400 AC Yerseke Phone: +31 113 577473 h.andersson at nioo.knaw.nl http...

I need to play games with an expression similar to the following one: print(xyplot(DepVar ~ Group|Covar, groups=Othergroup, data=mydf, pch = 18 ,main="Testcase",auto.key = TRUE)) The problem is that the formula argument (the first argument) an the groups argument are passed over from another program as strings. The formula argument does not pose problems, I can do

...inute data). But this is only a partial solution as I am not interested in data where the time difference is more than 15 minutes. How can I make the merge to work for fuzzy matching? Would it be easier to convert the times into data classes? Or, it better to treat them as strings and use regular expresssions for doing the matching? I would appreciate any help that I can get. Thanking You, Ravi

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Hello, I am wondering if someone can help me. I have the following function that I derived using nls() SSlogis. I would like to find its derivative. I thought I had done this using deriv(), but for some reason this isn't working out for me. Here is the function: asym <- 84.951 xmid <- 66.90742 scal <- -6.3 x.seq <- seq(1, 153,, 153) nls.fn <- asym/((1+exp((xmid-x.seq)/scal)))

Hello colleagues, I am attempting to determine the nonlinear least-squares estimates of the nonlinear model parameters using nls. I have come across a common problem that R users have reported when I attempt to fit a particular 3-parameter nonlinear function to my dataset: Error in nls(r ~ tlm(a, N.fix, k, theta), data = tlm.data, start = list(a = a.st, : step factor 0.000488281

...ole32: Use IsEqualIID instead of memcmp in HGLOBALLockBytesImpl_QueryInterface. libwine: Eliminate duplicate function implementations in string.c ole32: The stream returned by StgStreamImpl_Clone should have one reference, so call AddRef before returning. widl: Print EXPR_NUM expresssions as unsigned to avoid printing an extra negative sign when lval is large. user32: Send WM_GETTEXT to get the window caption when drawing the nonclient caption bar. rpcrt4: Set TCP_NODELAY on the socket for the ncacn_ip_tcp transport to reduce latency. secur32: SealMessage and Unse...