search for: exponent

Things are going along well, but there is one remaining area of confusion...."units". I understand exponents now...it's basically how you pass decimal values. That's easy enough. But "units"....in other words, I have a voltage I want to put in a report. If I include in the report descriptor the fact that it is actually a voltage, with units of "volts", then I'm suddenly...

## the following is a dream: add some sugar syntax to allow for contracts with teeth (in and out checking) > is.positive <- function(x) (all(x>0)) > exponentiate <- function( x ::is.data.frame , exponent ::is.numeric is.positive) :: is.vector is.numeric { x$base :: is.positive ## error also if base does not exist in x; may need some special IQ x$base^exponent } should be self-explanatory. anything that has '::' means "...

...s and optimize, or perhaps not optimize, accordingly. At present, underflow tininess is detected after rounding; it should be straight forward to add support for the before-rounding case too. Non-zero finite numbers are represented internally as a sign bit, a 16-bit signed exponent, and the significand as an array of integer parts. After normalization of a number of precision P the exponent is within the range of the format, and if the number is not denormal the P-th bit of the significand is set as an explicit integer bit. For denormals the most significant...

Dear all, I would like to (i) produce boxplot graphs with axis in logarithm in base 10 and (ii) showing the values on the axis in 10^exponent format rather than 10E+exponent. To illustrate with an example, I have some widely spread data that I chart plot using boxplot() [figure on the left]; the log="y" option of boxplot() I obtained the natural logarithm conversion of the data and the unfriendly notation baseE+exponent [f...

I am having difficulty with the calculation of the power law exponent for set of nodes within a graph. Specifically, I am interested in the distribution of in-degree and out-degree among communities of web pages where the web pages are the nodes of the graph and the hyperlinks the edges. According to the literature, the distribution of incoming and outgoing links...

Hello, I'm using fArma package to estimate the value of Hurst exponent using R/S method. However, for a certain set of data I get H ~ 1.8. How do I interpret this? Following are the output that I get for this set: > mean(data[,2]) [1] 400.5433 > sd(data[,2]) [1] 1139.786 > > rsFit(data[,2], levels = 64) Title: Hurst Exponent from R/S Method Call: rsF...

Dear all, Has anyone worked on coding for calculating Lyapunov Exponent for a time series data? or any package is available for computing Lyapunov? Please advice and many thanks in advance. Catherine X Wang

Hello i tried to connect my netys 2000 pr ups to ubuntu 11.10 and i have a problem connecting it. After readin a few post i realized to dianosse the connection. I need help resolving the connextion issue So here is the response to??/lib/nut/usbhid-ups -u root -DDDDD -a netys: Network UPS Tools - Generic HID driver 0.35 (2.6.1) USB communication driver 0.31 ? ?0.000000 ? ? send_to_all: SETINFO

Dear All, I am a novice when it comes to time-series analysis and at the moment I am actually interested in calculating the Hurst exponent of a time series. This question has already been asked quite some time ago http://bit.ly/98dZsi and I trust some progress has been made ever since. I was able to find some functions in the packages http://cran.r-project.org/web/packages/Rwave/index.html and http://cran.r-project.org/web/packa...

...I am using SPARSE matrix to solve the problem This is the code I use to obtain bonpower using Sparse Matrix & alternatively the code is in the following website http://igraph.wikidot.com/r-recipes#toc6 *bonpow.sparse <- function(graph, nodes=V(graph), loops=FALSE, exponent=1, rescale=TRUE, tol=1e-07) {* * ## remove loops if requested * * ## sparse adjacency matrix d <- get.adjacency(graph, sparse=TRUE)* * ## sparse identity matrix id <- spMatrix(vcount(graph), vcount(graph), i=1:vcount(graph), j=1:vcount(graph), x=rep(...

Hello, Does anybody know if there is somewhere in R a function to calculate the Lyapunov exponent in a time series? Thanks, Philippe Grosjean .......................................................<??}))><.... ) ) ) ) ) ( ( ( ( ( Prof. Philippe Grosjean \ ___ ) \/ECO\ ( Numerical Ecology of Aquatic Systems /\___/ ) Mons-Hainaut University, Pentagone / ___ /( 8, Av. du...

Dear R experts, I really have difficulty when I try to deal with this question. suppose X is a square symmetric matrix. The exponent of X is defined by the matrix limit as following: exp(X) = lim (I + X/n)^n, note: the limit is from n to infinite. How can I write R function for the above? Thank you very much -- View this message in context: http://r.789695.n4.nabble.com/Exponent-of-sqr-symmetric-matrix-tp3031436p3031436.htm...

Hello, I'm using the fArma package to estimate Hurst exponent by R/S method. I've some measurements in the following format: Call_number Call_duration I'm using the following steps. Am new to R, so it would help if someone could please confirm if my steps are correct. Further, this method seems to give a value H ~= 0.8 (> 0.5). Is the use of R/S...

I am attempting to deploy OpenSSH. The trouble is I keep getting the rsa_public_encrypt() exponent too small or not odd with the SSH 1 or 1.5 protocols. I can't get OpenSSH to communicate with itself with any protocal other than SSH 2. Platform notes: HP-UX 11.00 Dart 51 64bit OpenSSL 0.9.6 Zlib 1.1.3 Cflags: -Ae I have tried with and without optimizations. I noticed that this problem...

...float *dest4) { unsigned char *msbin = (unsigned char *)src4; unsigned char *ieee = (unsigned char *)dest4; unsigned char sign = 0x00; unsigned char ieee_exp = 0x00; int i; /* MS Binary Format */ /* byte order => m3 | m2 | m1 | exponent */ /* m1 is most significant byte => sbbb|bbbb */ /* m3 is the least significant byte */ /* m = mantissa byte */ /* s = sign bit */ /* b = bit */ sign = msbin[2] & 0x80;...

...veral global measures or statistics for time-series as well as packages of R that can compute them. I have found several of them in papers and books, but the literature is so big i am sure i am missing several of them. skewness kurtosis min max mean SD trend seasonality periodicity chaos (Lyapunov Exponent) / Largest Lyapunov Exponent (i think is the same statistic) serial correlation / auto-correlation (this is the same if i am correct Box-Pierce autocorrelation sum) higher-order autocorrelation nonlinearity (terasvirta test) self similarity (Hurst exponent) matual information sum any other statist...

I've acquired and installed NUT 2.4.1 on a D-Link DNS323 NAS. With exception of Load and Battery Temp readings all works well. A upsc ups at localhost command returns; battery.charge: 100 battery.charge.low: 10 battery.charge.warning: 50 battery.date: 2001/09/25 battery.mfr.date: 2008/06/05 battery.runtime: 2122 battery.runtime.low: 120 battery.temperature: 3022999999999998800 battery.type:

Dear R, I have two small questions confused me recently. Now assume I have a matrix "a", like this, > a <- matrix(1:6, 2, 3) > a [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 I sometimes need each row of "a" raised to a different exponent. So I do a trick like this, > a^c(2, 3) [,1] [,2] [,3] [1,] 1 9 25 [2,] 8 64 216 My first question is that if it is possible to do this trick column wise? Just out of curiosity, of course I know there are other ways of doing this. And the second question is why I get such r...

Dear R users, The function lmacfPlot( ) in fBasics, returns a list including the Hurst Exponent. I get sometimes a value for Hurst Exponent using lmacfPlot bigger than 1 which is theoretically incorrect. What could be reason ? From the related documents, I could not find how the Hurst Exponent in lmacfPlot is estimated. Could you please say how it is estimated here? Thank you so m...

I'm trying to make a function that will output the exponent... so f2(2,2) = 4 and f2(2,3)=8. But I don't want to just use the x^n function, I want to do it another way, and without a recursion. I did the follow code but for some reason it doesn't work. Help please? f2 <- function(x, n) #without recursion { y <- 1 if (n==0) {return(1)} else...