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On Thu, Jun 26, 2014 at 3:39 PM, Robinson, Paul <Paul_Robinson at playstation.sony.com> wrote: > The main motivation for turning it off is that no known consumer (debugger) > took advantage of it. > > Turning it on does more than slightly increase the object file size, it can > cause the same source line to be listed multiple times in the .debug_line > table (with different

R Users: I am trying to estimate a model of fertility behaviour using birth history data with maximum likelihood. My code works but is extremely slow (because of several for loops and my programming inefficiencies); when I use the genetic algorithm to optimize the likelihood function, it takes several days to complete (on a machine with Intel Core 2 processor [2.66GHz] and 2.99 GB RAM). Computing

Hello All, As part of my clang/LLVM experiments and explorations with different clang-built kernel versions, I have tried to bring up other Linux/Ubuntu applications with their kernel modules also being clang-built. One such case has been with VMware Player 14.1.1. I am sharing this report for interested people that highlights my research and success in overcoming and solving the challenges in

Dear R users, I used to "OPTIM" to minimize the obj. function below. Even though I used the true parameter values as initial values, the results are not very good. How could I improve my results? Any suggestion will be greatly appreciated. Regards, Kathryn Lord #------------------------------------------------------------------------------------------ x = c(0.35938587,

Dear R users, I used to "OPTIM" to minimize the obj. function below. Even though I used the true parameter values as initial values, the results are not very good. How could I improve my results? Any suggestion will be greatly appreciated. Regards, Kathryn Lord #------------------------------------------------------------------------------------------ x = c(0.35938587,

Dear R users, I have a response variable in a csv file called "y" and a matrix of predictor variables in a csv file called "mat". I have used the function "nls" I have specified the nonlinear relation between these variable.The code I have witten is called Rprog which begins with the phrase: L.minor.m1<-nls(Y~a ....etc.. The program when I execute the program, I

I'm very new to R and am trying to create my first loop. I have: x <-c(0:200) A <- dpois(x,exp(4.5355343)) B <- dpois(x,exp(4.5355343 + 0.0118638)) C <- dpois(x,exp(4.5355343 -0.0234615)) D <- dpois(x,exp(4.5355343 + 0.0316557)) E <- dpois(x,exp(4.5355343 + 0.0004716)) F <- dpois(x,exp(4.5355343 + 0.056437)) G <- dpois(x,exp(4.5355343 + 0.1225822)) and would like to

Hello All, This is about my successful experience in bringing up Ubuntu 17.10 x86_64 on the clang-built Linux 4.15.7 kernel(latest stable as of early March 2018) and clang-built proprietary Nvidia 390.25(latest as of early March 2018) driver for my Nvidia GTX GeForce 860M graphics card. I wanted to share the same here for any similarly interested people out here. By the way, appreciate the

LLVMers, The LLVM 2.1 pre-release version2 is now available: http://llvm.org/prereleases/2.1/version2/ You can help test this pre-release by doing one of the following: 1) Download llvm-2.1, llvm-test-2.1, and the appropriate llvm-gcc4.0 binary. Run "make check" and the full llvm-test suite (make TEST=nightly report). 2) Download llvm-2.1, llvm-test-2.1, and the llvm-gcc4.0 source.

Hi all again, llvm is failing the 2006-11-30-NoCompileUnit and 2006-11-30-Pubnames tests on me. -m32 and --disable-multilib didn't change the outcome. Did I get the command wrong? I tried jo at kurier:~/Delta/llvm/test$ CFLAGS=--multilib make check See below for a transcript of the failed check. What next? Regards, Jo -- snip -- jo at kurier:~/Delta/llvm/test$ make check llvm[0]:

Among others, datam contains the columns: logconc, tm, dose, subj, bilirubin. None of these are factor variables. The following compartment models work (the first still has not converged after 100 interations): res1 <- nlme(logconc~p2+p3+log(dose/(exp(p1)-exp(p2))* (exp(-exp(p2)*tm)-exp(-exp(p1)*tm))),start=list(fixed=c(5,-2,-0.1)), fixed=list(p1+p2+p3~1),control=list(maxIter=100),

Dear R, I have two questions: 1, Why both R and Matlab give 0*Inf==NaN? To my knowledge, it should be zero mathematically. Am I right? 2, I need to calculate e.g. exp(a)/(exp(b)+c), where both a and b are very large numbers (>>1000, e.g a=1000, b=1007, and c=5). R gives me NaN when I use the following command: > exp(1000)/(exp(1007)+5) [1] NaN I am pretty sure this should be close to

Dear listers, I am trying to fit a model using nlsList() using alternately a SSfol() selfstart function or its developped equivalent formulae. This preliminary trial works well mydata<-groupedData(Conc~Tps|Organ,data=mydata) mymod1<-nls(Conc~SSfol(Dose,Tps,lKe,lKa,lCl),data=mydata) as well as a developped form: mymod2<-nls(Conc~Dose * exp(lKe+lKa-lCl) *

Hi all, Please review this patch. It's fixing PR3232 comment #8. Function bar from 2008-03-24-BitFiled-And-Alloca.c compiles to: %struct.Key = type { { i32, i32 } } ... define i32 @bar(i64 %key_token2) nounwind { entry: %key_token2_addr = alloca i64 ; <i64*> [#uses=2] %retval = alloca i32 ; <i32*> [#uses=2] %iospec =

Dear All,   #I have the following code   Dose<-1000 Tinf <-0.5 INTERVAL <-8 TIME8 <-matrix(c((0*INTERVAL):(1*INTERVAL))) TIME7 <-matrix(c((0*INTERVAL):(2*INTERVAL))) TIME6 <-matrix(c((0*INTERVAL):(3*INTERVAL))) TIME5 <-matrix(c((0*INTERVAL):(4*INTERVAL))) TIME4 <-matrix(c((0*INTERVAL):(5*INTERVAL))) TIME3 <-matrix(c((0*INTERVAL):(6*INTERVAL))) TIME2

I have assayed the concentrations of various metal elements in different anatomic regions of two strains of mice. Now, for each element, in each region, I want to do a t test to find whether there is any difference between the two strains. Here is what I did (using simulated data as an example): # create the data frame > elemconc = data.frame(expand.grid(id=1:3, geno=c('exp',

Hi I?m trying to fit a nonlinear model to a derivative of the logistic function y = a/(1+exp((b-x)/c)) (this is the parametrization for the SSlogis function with nls) The derivative calculated with D function is: > logis<- expression(a/(1+exp((b-x)/c))) > D(logis, "x") a * (exp((b - x)/c) * (1/c))/(1 + exp((b - x)/c))^2 So I enter this expression in the nls function:

Hi, Am i doing something silly here in expecting Euler's formula to be handled by exp? exp( ix ) = cos x + i sin x. The first example below follows this, the others not. Thanks for the education! > exp( complex(real = 0, imag = 2*pi) ) [1] 1-0i > exp( complex(real = pi, imag = 2*pi) ) [1] 23.14069-0i > exp( complex(real = pi/2, imag = 0) ) [1] 4.810477+0i [[alternative HTML

Dear R-user, I am trying to use the R "nlme" function to fit a non linear mixed effects model. The model I wand to fit is an individual somatic growth model with 4 parameters. For all parameters both fixed and random effects have to be estimated, as well as their covariance matrix (see the formula bellow). The data are simulated with the same growth model as in the nlme, with know

Hi Matt, Run these commands on all the bricks of the replica pair to get the attrs set on the backend. On the bricks of first replica set: getfattr -d -e hex -m . <brick path>/.glusterfs/10/86/ 108694db-c039-4b7c-bd3d-ad6a15d811a2 On the fourth replica set: getfattr -d -e hex -m . <brick path>/.glusterfs/ e0/c5/e0c56bf7-8bfe-46ca-bde1-e46b92d33df3 Also run the "gluster volume