search for: expalins

Hi all I want to add a band of fluctuaci?n (exponential decreading) to a linear deacrecing values Imagine: I have a matrix like c(10,9,8,7,6,5,4,3,2,1) The thing is I want two new lines so that the m?ximum value of the new colum on the m?ximum is from 10% to 5% higher and the same lower for the m?nimum the final two matix will be something like c(10+0.10*10,9+0.089*9,8+0.075*8.....,1+0.05*1)

Hi all,,Im using function arima() I.e series is my data model<-arima(series,c(1,0,0)) forecast<-predict(model,80) I want to create a variable: b1<-forecast$pred - 1.96*forecast$se and save in a txt file but using this: save(b1, file= "b1.txt") creates afile butwith this inside: ]{HQ ~|LJIiW*-l)% )m#), RIiSfdbGur9p94; H"L#Rez 1y3pN8{,I6W!6= {6l?OMw_5KZ+ =

great thanks Steve ___________________________________________________________________________________________ Mario Pio Russo, System Admin SWG IT Services Dublin, Phone & FAX: +353 1 815 2236, eMail: mariopiorusso at ie.ibm.com IBM Ireland Product Distribution Limited registered in Ireland with number 92815. Registered Office: IBM House, Shelbourne Road, Ballsbridge, Dublin 4 (Embedded

Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Jun 1, 2017 at 11:20 AM, Pedro p?ramo <percentil101 at gmail.com> wrote: > Hi all > > I want to add a band of fluctuaci?n (exponential decreading) to a linear > deacrecing

I explain better: I have this percentage z<-1/(n*365) where n=20 so z is 0,000136986 Imagine: a matrix with length(n*365) so that matrix result is resultc( 1, 1-z result previous row-z result previous row-z .... 0) If I plot this is a linear decreasing line I want to plot an upper line wich is 10% higher tan resultc on the first values and then decreasing so that last value will be 0.05.

.../var/log/all.log # uncomment this to enable logging to a remote loghost named loghost #*.* @loghost The file /var/log/caioa.log exists and is 600. I got the syntax off a web page, but it is not working for me and I don't see anything in the man page that expalins how to do it. Any help would really be appreciated. Thanks. -- Karyn Williams, CNE Network Services Manager California Institute of the Arts karyn@calarts.edu http://www.calarts.edu/network

On 08/05/15 12:49, Mario Pio Russo wrote: > Hi all > > just going back to this, Steve can you please expalin where did you take > this number from? 11644473600 > > that seems not to work correctly on my system so I was lookin g how to > tailor down the right value > > thanks > > >

Sorry, For me a vector is a matrix with mx1 dimmensions. But it is true that it is not the way I correctly must talk in R. Can you guide me in what I?m trying to do? I?m trying to find what I want in Excel using something like a parabolic function but dind?t get yet (then to try to replicate in R). 2017-06-02 7:01 GMT+02:00 Bert Gunter <bgunter.4567 at gmail.com>: > Bert Gunter >

Hello I have a big dataset where i have pulled out some periods of time acording to a herd-number (see below): CHR_NR DATO_TEST SALMO_INDEX didiffdatoperiode 11377 2003-06-20 7.9 29 11377 2003-09-01 4.3 59 11377 2004-02-24 5.1 78 where the variable 'diffdatoperiode' is the period in days and

On 14 Jan 2018, at 00:14, sangeeta chowdhary <sangitachowdhary at gmail.com> wrote: > > I have taken SimplePass and added in Transform directory, “libLLVMSimplePass.a” is built but I can not see this pass in opt —help. I don’t even see the name of pass while registering it in the example. The SimplePass example is intended to be built out of tree, so I’ve no idea what happens if you

Hi @ all, I hope for some help of you. I have a dataframe and I want to regroup it. examp4.csv <http://r.789695.n4.nabble.com/file/n4648927/examp4.csv> I need the arguments of "VAL" as table heads and the "TYPE " only in individual expression. The result should look like in the example pic. exp4.png <http://r.789695.n4.nabble.com/file/n4648927/exp4.png> I

Hi all just going back to this, Steve can you please expalin where did you take this number from? 11644473600 that seems not to work correctly on my system so I was lookin g how to tailor down the right value thanks ___________________________________________________________________________________________ Mario Pio Russo, System Admin SWG IT Services Dublin, Phone & FAX: +353 1 815

Hi all, That issue is over now. I found why my ESTABLISHED,RELATED rule at the top of INPUT chain did not work for udp and icmp. The reason was I have included the protocol as tcp as below iptables -A INPUT -i eth0 -p tcp -m state --state ESTABLISHED,RELATED -j ACCEPT I removed -p tcp from above rule. Now it works for all protocols. Thanks for your support. ---------- Forwarded message

I have taken SimplePass and added in Transform directory, “libLLVMSimplePass.a” is built but I can not see this pass in opt —help. I don’t even see the name of pass while registering it in the example. > On Jan 13, 2018, at 7:35 AM, David Chisnall <David.Chisnall at cl.cam.ac.uk> wrote: > > On 13 Jan 2018, at 03:45, Craig Topper via llvm-dev <llvm-dev at lists.llvm.org>

thanks Rowland! btw, when will samba 4.2.2 released? looking foward to it! (I need the bug of the RDP fixed :D) thanks! ___________________________________________________________________________________________ Mario Pio Russo, System Admin SWG IT Services Dublin, Phone & FAX: +353 1 815 2236, eMail: mariopiorusso at ie.ibm.com IBM Ireland Product Distribution Limited registered in

Dear R helpers   I have some variables say ABC, DEF, PQR, LMN and XYZ. I am choosing any three varaibles at random at a time for my analysis and name these files as input1.csv, input2.csv and input3.csv. So if I choose variables say ABC, DEF and PQR, I am passing the specifications of these variables to input1.csv, input2.csv and input3.csv respectively.   This means in another case even if I