search for: exctract

Dear all, Here I come with another stupid question. Suppose I want to use nls() to fit a series of data (here modelled by generated points), then plot the points and the fitting curve. I figured out some way of doing it: x <- runif(1:20, 0, 10) y <- 0.1*x^2 - rep(3, length(x)) + rnorm(length(x), sd = 0.5) yfit <- nls(y ~ a*x^2 + b*x + c, start = list(a = 1, b = 1, c = 1),

I want to be able to exctract a matrix from a data frame that contains repeated measurements for individuals. i.e I want to exctract the second observation for each individual in the study. Is there a way of doing this? I guess what I am trying to ask is if there as a multidimensional version of aggregate() as in aggregate(d...

Hi, I am using the NLSY79 data (longitudinal data from the Bureau of labour stats in the US). The extractor exctracts this data in a "wide" format and I need to reshape it into a long format. What I am doing right now is to do it in chuncks for each and evry variable that is varying and then I merge the data together. This is taking a long time. my question is: How do I specify that there are multiple...

...option named "Icon", where path to some icon is set. Sometimes this path points to some PNG image file, but sometimes it points to something I don't have a clue about, like that one: "Icon=4e90_flv2mp3.0". Could anybody tell a newbie what does that means? And, how does WINE exctract icons from EXE files and converts them into PNG? Could I somehow do it by myself, if a program I install has no installation file, so I have to manege it manually?

...th '1' for 'survival'. I thought of creating matrices for each individual, adding first one column 'survival' containing zeros to the original dataset, then creating matrices with data = 'the vector containing all elements of an individual/row' ([1,], nrow = [a,b], exctracting the element for longevity, and then with byrow = TRUE letting the data be filled in by row. At the end I would have to set the last element in 'survival' to '1', and then combine all matrices into one single one. So far I've used Excel to create these datesets manually, but...

...3.3 0 Sac= 0.00 Acc= 0.00 DG 23 O6 Rad= 3.3 1 Sac= 0.04 Acc= 0.22 DG 23 O6 Rad= 3.3 0 Sac= 0.00 Acc= 0.00 DG 23 O6 Rad= 3.3 0 Sac= 0.00 Acc= 0.00 (it's a data.frame) at first i wanted all the line begining with A 24: data[grep("^24", data$V2)] this works and than i wanted to exctract all the lines with G23 N7, neither the column 23 and the column N7 are unique so i tried this data[grep("^23*N7", data),] but doesn't work not either x[(grep("^N7", as.character(x$V3))) &(grep("^23", x$V2)),] he just returns everything. thank u for any help,...

Hi List. I've got SAMBA 3.0.7 with LDAP passwd backend (OpenLDAP 2.2.15) on Solaris 9 box. When joining the domain I have permanent error "The user name could not be found". To add machine I use account "administrator" which is already exist in SAMBA/LDAP with uid=0 and proper password. I have "add machine script" directive in smb.conf file and I see that

Hi, I've a list of list. I want to extract an element by the rownames. I can extract it by: data[[1]][[1]][[4]][1] But I want to exctract it by a command like this: data[[1]][["B0"]][["smac"]][["cont"]][1] It's possible? Thanks, Alfredo > str(data) List of 1 $ :List of 4 ..$ :List of 4 .. ..$ : num [1, 1:3] 0.4 0.458 0.5 .. ..$ : num [1:41, 1] 0.4 0.403 0.405 0.407 0.41 ... .. .....

...wever, the documentation states "...you can?t have attributes that aren?t part of the table columns." Why is this possible (this isn''t really a problem, but I just wanted to know)? The above method works for individual files. My problem is this - I would like to have rubyzip exctract files to create new Logfiles. My current method is to iterate through the ZipFile using foreach, but this yields ZipEntries. Is there a way to extract this as a Tempfile until its final destination is determined using my above-mentioned handlers? Or is there a better way to go about this?...

Hello I am able to extract partial regression coefficients from a fitted model object "model", i.e. model <- lm(var.sel.gkm, weights = count.gkm, data = DATA) summary(model) write.table(model$coef, file = "C:/coef_CO_gkm.txt", row.names = TRUE, col.names = TRUE) I was wondering if anyone could advise me how to extract other object items such as std. error, t-values

...ething wrong. My collegaues made a little program what shows the bug. Two screenshots and the source are included in the tar.gz. Please somebody examine it, and help me if you can. The source, binaries, and screenshots can be downloaded from ftp://ftp.uhulinux.hu/misc/testprg.tar.gz. It needs to be exctracted to the wine c:\ directory Thanks for your help in advance! If needed I can send you wine debug msgs. -- doome

Dear all, I have a variable 'x' like that: > x [1] "2005-09-01" Here, 2005 represents year, 09 month and 01 day. Now I want to create three variables naming: y, m, and d such that: y = 2005 m = 09 d = 01 can anyone tell me how to do that? Regards, [[alternative HTML version deleted]]

Hi everyone. Is it possible in R to create a matrix or a list (vector) or R object. For instance, I have f1 <- function(x) sqrt(x%*%x); f2 <- function(x) (2x+1); I would like to do something like L <- List(); L[1] = f1; L[2] = f2; So, is there a way to create matrix or vector that can contains R object. With regards, Phil -- View this message in context:

https://bugs.freedesktop.org/show_bug.cgi?id=101601 Bug ID: 101601 Summary: Nvidia GT 1030 (NV138/GP108) support Product: xorg Version: unspecified Hardware: Other OS: All Status: NEW Severity: normal Priority: medium Component: Driver/nouveau Assignee: nouveau at

A client of mine has a ton of data stored in Excel spreadsheets. I''m building a web application for her (backed by a real db of course) and want to import all that data. Is there a library available to read data from Excel? Is there an easy way to upload the spreadsheets and then read the data? Thanks, Ken Kousen -- Kenneth A. Kousen, Ph.D. President Kousen IT, Inc.